| Back: | ⟨a, b | abaaaab=ba⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaaab ⇒ ba |
| 2. | baaaaab ⇒ abaaaba |
| 3. | baaaaaab ⇒ aabaabaa |
| 4. | baaaaaaab ⇒ aaababaaa |
| 5. | baaaaaaaab ⇒ aaaabbaaaa |
| 6. | baaaaaaaaabb ⇒ aaaaabbaaaba |
| 7. | bbaaaaaaaaab ⇒ abaaabbaaaaa |
| 8. | baaaaaaaaaabb ⇒ aaaaaabbaabaa |
| 9. | baaaaaaaaabab ⇒ aaaaababaabaa |
| 10. | aaaaabbaaaabaaaa ⇒ baaaaaaaaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 70 | lf:68,lp:1,ls:1,rf:48,rp:6,rs:6 |
|---|---|---|---|
| [2/1] | ab | 21 | lf:13,lp:1,ls:7,rf:17,rp:2,rs:1,lsrp:2 |
| [2/2] | ba | 19 | lf:12,lp:7,rf:18,rp:2,rs:3,re:1,lprs:2 |
| [2/3] | bb | 7 | lf:4,lp:1,ls:2,rf:4,a:5 |
| [3/0] | aaa | 58 | lf:56,lp:1,ls:1,rf:29,rp:5,rs:3 |
| [3/1] | baa | 18 | lf:11,lp:7,rf:13,rp:1,rs:3,lprs:3 |
| [3/2] | aab | 17 | lf:11,ls:6,rf:13,rp:1,rs:1,lsrp:1 |
| [3/3] | abb | 5 | lf:3,ls:2,rf:4,a:5 |
| [3/4] | aba | 4 | lf:3,lp:1,rf:12,rp:2,rs:2 |
| [3/5] | bba | 3 | lf:2,lp:1,rf:4,a:5 |
| [3/6] | bab | 2 | lf:1,ls:1,rf:2,a:3 |
| [4/0] | aaaa | 46 | lf:44,lp:1,ls:1,rf:17,rp:4,rs:2 |
| [4/1] | baaa | 18 | lf:11,lp:7,rf:7,rp:1,rs:1,lprs:1 |
| [4/2] | aaab | 17 | lf:11,ls:6,rf:9,rp:1,rs:1,lsrp:1 |
| [4/3] | aabb | 5 | lf:3,ls:2,rf:4,a:5 |
| [4/4] | abaa | 3 | lf:2,lp:1,rf:8,rp:2,rs:3 |
| [4/5] | bbaa | 3 | lf:2,lp:1,rf:4,a:5 |
| [4/6] | aaba | 2 | lf:2,rf:8,rp:1,rs:2,a:1 |
| [5/0] | aaaaa | 33 | lf:32,lp:1,rf:10,rp:3,rs:1,a:1 |
| [5/1] | baaaa | 19 | lf:11,lp:7,ls:1,rf:3,rp:1,rs:1,lsrp:1,lprs:1 |
| [5/2] | aaaab | 17 | lf:11,ls:6,rf:5,rp:1,rs:1,lsrp:1 |
| [5/3] | aaabb | 5 | lf:3,ls:2,rf:4,a:5 |
| [5/4] | abaaa | 3 | lf:2,lp:1,rf:3,rp:2,rs:1 |
| [5/5] | bbaaa | 3 | lf:2,lp:1,rf:3,a:5 |
| [5/6] | aaaba | 2 | lf:2,rf:4,rp:1,rs:2,a:1 |
| [6/0] | aaaaaa | 23 | lf:23,rf:5,rp:1,a:2 |
| [6/1] | baaaaa | 15 | lf:8,lp:7,rf:2,rp:1,rs:1,a:1 |
| [6/2] | aaaaab | 15 | lf:9,lp:1,ls:5,rf:4,rp:2,rs:1,lprs:1,a:1 |
| [6/3] | aaaabb | 5 | lf:3,ls:2,rf:3,rp:1,a:5 |
| [6/4] | abaaaa | 4 | lf:2,lp:1,ls:1 |
| [6/5] | bbaaaa | 3 | lf:2,lp:1,rf:2,rs:1,a:5 |
| [6/6] | baaaab | 3 | lf:2,ls:1 |
| [7/0] | aaaaaaa | 16 | lf:16,rf:3,a:3 |
| [7/1] | baaaaaa | 13 | lf:7,lp:6,rf:1,rp:1,a:2 |
| [7/2] | aaaaaab | 11 | lf:7,ls:4,rf:2,rp:1,rs:1,a:2 |
| [7/3] | aaaaabb | 6 | lf:3,lp:1,ls:2,rf:2,rp:1,lsrp:1,a:9 |
| [7/4] | aabaaaa | 2 | lf:1,ls:1,a:9 |
| [7/5] | bbaaaaa | 2 | lf:1,lp:1,rf:1,rs:1,lprs:1,a:17 |
| [7/6] | aaaabab | 2 | lf:1,ls:1,rf:1,a:22 |
Considering [length 5 / frequency 1] baaaa=c.
Rewriting system is complete. See ⟨a, b | abaaaab=ba⟩.