| Back: | ⟨a, b | aabbbaa=ab⟩ |
|---|
Solved by morph:4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbbaa ⇒ ab |
| 2. | ababbbaa ⇒ abb |
| 3. | aabbbab ⇒ abbbbaa |
| 4. | abbabbbaa ⇒ abbb |
| 5. | ababbbab ⇒ abbbbbaa |
| 6. | abbbbaabbaa ⇒ aabbbb |
| 7. | abbbabbbaa ⇒ abbbb |
| 8. | abbabbbab ⇒ abbbbbbaa |
| 9. | abbbbbaabbaa ⇒ ababbbb |
| 10. | abbbbabbbaa ⇒ abbbbb |
| 11. | abbbabbbab ⇒ abbbbbbbaa |
| 12. | aabbbbbbbaa ⇒ abbbbaabbab |
| 13. | abbbbbbaabbaa ⇒ abbabbbb |
| 14. | abbbbbabbbaa ⇒ abbbbbb |
| 15. | abbbbabbbab ⇒ abbbbbbbbaa |
| 16. | abbbbbbbaabbaa ⇒ abbbabbbb |
| 17. | abbbbbbabbbaa ⇒ abbbbbbb |
| 18. | abbbbbbbabbbaa ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 81 | lf:81,rf:72,rs:11 |
|---|---|---|---|
| [2/1] | ab | 58 | lf:38,lp:15,ls:5,rf:23,rp:17,rs:2,re:1,lprp:14,lsrp:5 |
| [2/2] | aa | 36 | lf:20,lp:3,ls:13,rf:7,rp:1,rs:5,lsrp:1,lprs:1 |
| [2/3] | ba | 33 | lf:33,rf:10 |
| [3/0] | bbb | 50 | lf:50,rf:52,rs:10 |
| [3/1] | abb | 44 | lf:31,lp:13,rf:20,rp:15,rs:1,re:1,lprp:11 |
| [3/2] | bba | 31 | lf:31,rf:9 |
| [3/3] | baa | 30 | lf:17,ls:13,rf:6,rs:5 |
| [3/4] | bab | 21 | lf:16,ls:5,rf:4,rs:1,a:1 |
| [3/5] | aab | 10 | lf:7,lp:3,rf:2,rp:1 |
| [3/6] | aba | 4 | lf:2,lp:2,rf:1,rp:1,a:2 |
| [4/0] | abbb | 36 | lf:25,lp:11,rf:17,rp:13,rs:1,re:1,lprp:8 |
| [4/1] | bbaa | 30 | lf:17,ls:13,rf:6,rs:5 |
| [4/2] | bbbb | 25 | lf:25,rf:35,rs:9,a:1 |
| [4/3] | bbba | 25 | lf:25,rf:7 |
| [4/4] | bbab | 19 | lf:14,ls:5,rf:3,rs:1,a:1 |
| [4/5] | babb | 11 | lf:11,rf:3,a:2 |
| [4/6] | aabb | 10 | lf:7,lp:3,rf:2,rp:1 |
| [5/0] | bbbaa | 22 | lf:13,ls:9,rf:6,rs:5 |
| [5/1] | abbbb | 19 | lf:10,lp:9,rf:15,rp:11,rs:5,re:1,lprp:5,lprs:4,a:1 |
| [5/2] | bbbab | 17 | lf:12,ls:5,rf:1,a:1 |
| [5/3] | abbba | 17 | lf:15,lp:2,rf:1,rp:1 |
| [5/4] | bbbbb | 15 | lf:15,rf:20,rs:4,a:4 |
| [5/5] | babbb | 11 | lf:11,rf:3,a:2 |
| [5/6] | bbbba | 10 | lf:10,rf:6,a:1 |
| [6/0] | abbbaa | 16 | lf:8,ls:8 |
| [6/1] | abbbab | 14 | lf:7,lp:2,ls:5,rf:1,rp:1,a:1 |
| [6/2] | abbbbb | 13 | lf:7,lp:6,rf:8,rp:8,rs:1,re:1,lprp:3,a:4 |
| [6/3] | babbba | 11 | lf:11,a:2 |
| [6/4] | bbabbb | 9 | lf:9,rf:2,a:3 |
| [6/5] | bbbbbb | 8 | lf:8,rf:12,rs:3,a:7 |
| [6/6] | aabbaa | 8 | lf:4,ls:4,a:10 |
| [7/0] | babbbaa | 14 | lf:7,ls:7,a:2 |
| [7/1] | abbbbbb | 9 | lf:5,lp:4,rf:6,rp:6,rs:1,re:1,lprp:2,a:7 |
| [7/2] | bbabbba | 9 | lf:9,a:3 |
| [7/3] | babbbab | 8 | lf:4,ls:4,a:4 |
| [7/4] | baabbaa | 8 | lf:4,ls:4,a:10 |
| [7/5] | bbbabbb | 7 | lf:7,rf:1,a:5 |
| [7/6] | bbbbabb | 5 | lf:5,a:6 |
Considering [length 4 / frequency 0] abbb=c.
Rewriting system is complete. See ⟨a, b | aabbbaa=ab⟩.