| Back: | ⟨a, b | aabbaba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaba ⇒ ab |
| 2. | ababbaba ⇒ abb |
| 3. | aabbabb ⇒ abbbaba |
| 4. | abbbabaaba ⇒ aabbb |
| 5. | abbabbaba ⇒ abbb |
| 6. | ababbabb ⇒ abbbbaba |
| 7. | abbbbabaaba ⇒ ababbb |
| 8. | abbbabbaba ⇒ abbbb |
| 9. | abbabbabb ⇒ abbbbbaba |
| 10. | aabbbbbaba ⇒ abbbabaabb |
| 11. | abbbbbabaaba ⇒ abbabbb |
| 12. | abbbbabbaba ⇒ abbbbb |
| 13. | abbbabbabb ⇒ abbbbbbaba |
| 14. | abbbbbbabaaba ⇒ abbbabbb |
| 15. | abbbbbabbaba ⇒ abbbbbb |
| 16. | abbbbbbabbaba ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 58 | lf:45,lp:13,rf:25,rp:15,rs:1,re:1,lprp:12 |
|---|---|---|---|
| [2/1] | bb | 55 | lf:51,ls:4,rf:49,rs:11 |
| [2/2] | ba | 53 | lf:41,ls:12,rf:13,rs:4 |
| [2/3] | aa | 10 | lf:7,lp:3,rf:2,rp:1 |
| [3/0] | abb | 42 | lf:27,lp:11,ls:4,rf:18,rp:13,rs:2,re:1,lprp:9,lsrp:4 |
| [3/1] | aba | 32 | lf:18,lp:2,ls:12,rf:6,rp:1,rs:4,lsrp:1,lprs:1 |
| [3/2] | bab | 25 | lf:25,rf:8 |
| [3/3] | bbb | 24 | lf:24,rf:31,rs:9,a:2 |
| [3/4] | bba | 23 | lf:23,rf:7 |
| [3/5] | aab | 10 | lf:7,lp:3,rf:2,rp:1 |
| [3/6] | baa | 4 | lf:4,rf:1,a:9 |
| [4/0] | bbab | 23 | lf:23,rf:7 |
| [4/1] | baba | 20 | lf:12,ls:8,rf:5,rs:4 |
| [4/2] | abbb | 19 | lf:10,lp:9,rf:15,rp:11,rs:5,re:1,lprp:6,lprs:4,a:2 |
| [4/3] | babb | 17 | lf:13,ls:4,rf:3,a:1 |
| [4/4] | abba | 15 | lf:13,lp:2,rf:1,rp:1 |
| [4/5] | bbbb | 14 | lf:14,rf:16,rs:4,a:4 |
| [4/6] | bbba | 10 | lf:10,rf:6,a:2 |
| [5/0] | bbaba | 20 | lf:12,ls:8,rf:5,rs:4 |
| [5/1] | bbabb | 15 | lf:11,ls:4,rf:2,a:2 |
| [5/2] | abbab | 15 | lf:13,lp:2,rf:1,rp:1 |
| [5/3] | abbbb | 13 | lf:7,lp:6,rf:7,rp:7,rs:1,re:1,lprp:3,a:4 |
| [5/4] | bbbab | 10 | lf:10,rf:6,a:2 |
| [5/5] | babba | 9 | lf:9,a:1 |
| [5/6] | baaba | 8 | lf:4,ls:4,a:9 |
| [6/0] | abbaba | 14 | lf:7,ls:7 |
| [6/1] | abbabb | 12 | lf:6,lp:2,ls:4,rf:1,rp:1,a:2 |
| [6/2] | abbbbb | 9 | lf:5,lp:4,rf:5,rp:5,rs:1,re:1,lprp:2,a:6 |
| [6/3] | babbab | 9 | lf:9,a:1 |
| [6/4] | abaaba | 8 | lf:4,ls:4,a:9 |
| [6/5] | bbbbab | 7 | lf:7,rf:3,a:4 |
| [6/6] | bbabba | 7 | lf:7,a:3 |
| [7/0] | babbaba | 12 | lf:6,ls:6,a:1 |
| [7/1] | babaaba | 8 | lf:4,ls:4,a:9 |
| [7/2] | bbabbab | 7 | lf:7,a:3 |
| [7/3] | babbabb | 6 | lf:3,ls:3,a:4 |
| [7/4] | bbbbbab | 5 | lf:5,rf:2,a:7 |
| [7/5] | abbbbba | 5 | lf:3,lp:2,rf:1,rp:1,a:7 |
| [7/6] | bbbabba | 5 | lf:5,a:5 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aabbaba=ab⟩.