Morphocompletion for #953 ⟨a, b | aabbaba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaba ⇒ ab
2. ababbaba ⇒ abb
3. aabbabb ⇒ abbbaba
4. abbbabaaba ⇒ aabbb
5. abbabbaba ⇒ abbb
6. ababbabb ⇒ abbbbaba
7. abbbbabaaba ⇒ ababbb
8. abbbabbaba ⇒ abbbb
9. abbabbabb ⇒ abbbbbaba
10. aabbbbbaba ⇒ abbbabaabb
11. abbbbbabaaba ⇒ abbabbb
12. abbbbabbaba ⇒ abbbbb
13. abbbabbabb ⇒ abbbbbbaba
14. abbbbbbabaaba ⇒ abbbabbb
15. abbbbbabbaba ⇒ abbbbbb
16. abbbbbbabbaba ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] aba, [3/2] bab, [3/3] bbb, [3/4] bba, [3/5] aab, [3/6] baa
Length 4:[4/0] bbab, [4/1] baba, [4/2] abbb, [4/3] babb, [4/4] abba, [4/5] bbbb, [4/6] bbba
Length 5:[5/0] bbaba, [5/1] bbabb, [5/2] abbab, [5/3] abbbb, [5/4] bbbab, [5/5] babba, [5/6] baaba
Length 6:[6/0] abbaba, [6/1] abbabb, [6/2] abbbbb, [6/3] babbab, [6/4] abaaba, [6/5] bbbbab, [6/6] bbabba
Length 7:[7/0] babbaba, [7/1] babaaba, [7/2] bbabbab, [7/3] babbabb, [7/4] bbbbbab, [7/5] abbbbba, [7/6] bbbabba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aabbaba=ab.