| Back: | ⟨a, b | aababba=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababba ⇒ ab |
| 2. | abbabba ⇒ aababbb |
| 3. | abababba ⇒ abb |
| 4. | abbbabba ⇒ abababbb |
| 5. | abbababba ⇒ abbb |
| 6. | abbbbabba ⇒ abbababbb |
| 7. | aabaababbb ⇒ abbba |
| 8. | abbaababbb ⇒ aababbbbba |
| 9. | abbbababba ⇒ abbbb |
| 10. | abbbbbabba ⇒ abbbababbb |
| 11. | ababaababbb ⇒ abbbba |
| 12. | abbbaababbb ⇒ abababbbbba |
| 13. | abbbbababba ⇒ abbbbb |
| 14. | abbabaababbb ⇒ abbbbba |
| 15. | abbbbbababba ⇒ abbbbbb |
| 16. | abbbabaababbb ⇒ abbbbbba |
| 17. | abbbbbbababba ⇒ abbbbbbb |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aba, [3/5] aab, [3/6] baa |
| Length 4: | [4/0] abbb, [4/1] abba, [4/2] babb, [4/3] abab, [4/4] bbab, [4/5] aaba, [4/6] bbbb |
| Length 5: | [5/0] babba, [5/1] ababb, [5/2] babbb, [5/3] abbbb, [5/4] bbbab, [5/5] abbba, [5/6] aabab |
| Length 6: | [6/0] ababba, [6/1] ababbb, [6/2] bbabba, [6/3] aababb, [6/4] bababb, [6/5] baabab, [6/6] abbbbb |
| Length 7: | [7/0] bababba, [7/1] aababbb, [7/2] bbbabba, [7/3] baababb, [7/4] bbababb, [7/5] bbbabab, [7/6] abbbbba |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aababba=ab⟩.