Morphocompletion for #945 ⟨a, b | aababba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababba ⇒ ab
2. abbabba ⇒ aababbb
3. abababba ⇒ abb
4. abbbabba ⇒ abababbb
5. abbababba ⇒ abbb
6. abbbbabba ⇒ abbababbb
7. aabaababbb ⇒ abbba
8. abbaababbb ⇒ aababbbbba
9. abbbababba ⇒ abbbb
10. abbbbbabba ⇒ abbbababbb
11. ababaababbb ⇒ abbbba
12. abbbaababbb ⇒ abababbbbba
13. abbbbababba ⇒ abbbbb
14. abbabaababbb ⇒ abbbbba
15. abbbbbababba ⇒ abbbbbb
16. abbbabaababbb ⇒ abbbbbba
17. abbbbbbababba ⇒ abbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] bab, [3/4] aba, [3/5] aab, [3/6] baa
Length 4:[4/0] abbb, [4/1] abba, [4/2] babb, [4/3] abab, [4/4] bbab, [4/5] aaba, [4/6] bbbb
Length 5:[5/0] babba, [5/1] ababb, [5/2] babbb, [5/3] abbbb, [5/4] bbbab, [5/5] abbba, [5/6] aabab
Length 6:[6/0] ababba, [6/1] ababbb, [6/2] bbabba, [6/3] aababb, [6/4] bababb, [6/5] baabab, [6/6] abbbbb
Length 7:[7/0] bababba, [7/1] aababbb, [7/2] bbbabba, [7/3] baababb, [7/4] bbababb, [7/5] bbbabab, [7/6] abbbbba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aababba=ab.