Morphocompletion for #922 ⟨a, b | aaabbba=ab⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbba ⇒ ab
2. ababbba ⇒ aaabbbb
3. abaabbba ⇒ abb
4. abbabbba ⇒ abaabbbb
5. abbaabbba ⇒ abbb
6. aaabbaabbbb ⇒ abbbba
7. abbbabbba ⇒ abbaabbbb
8. abbbaabbba ⇒ abbbb
9. abaabbaabbbb ⇒ abbbbba
10. aaabbbbbbba ⇒ ababbaabbbb
11. abbbbabbba ⇒ abbbaabbbb
12. abbbbaabbba ⇒ abbbbb
13. abbaabbaabbbb ⇒ abbbbbba
14. abbbbbabbba ⇒ abbbbaabbbb
15. abbbbbaabbba ⇒ abbbbbb
16. abbbaabbaabbbb ⇒ abbbbbbba
17. abbbbbbaabbba ⇒ abbbbbbb
18. abbbbbbbaabbba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb86lf:82,ls:4,rf:71,rs:13
[2/1]ab52lf:37,lp:15,rf:24,rp:17,rs:1,re:1,lprp:14
[2/2]ba47lf:33,ls:14,rf:10,rs:4
[2/3]aa23lf:20,lp:3,rf:7,rp:1
[3/0]bbb52lf:48,ls:4,rf:50,rs:12
[3/1]abb46lf:34,lp:12,rf:21,rp:14,rs:1,re:1,lprp:11
[3/2]bba44lf:30,ls:14,rf:8,rs:4
[3/3]aab17lf:17,rf:6
[3/4]baa14lf:14,rf:5,a:1
[3/5]aba6lf:3,lp:3,rf:2,rp:2,a:1
[3/6]aaa6lf:3,lp:3,rf:1,rp:1
[4/0]bbba37lf:23,ls:14,rf:6,rs:4
[4/1]abbb36lf:27,lp:9,rf:18,rp:12,rs:1,re:1,lprp:8
[4/2]bbbb25lf:21,ls:4,rf:32,rs:11,a:3
[4/3]aabb17lf:17,rf:6
[4/4]baab14lf:14,rf:5,a:1
[4/5]bbaa12lf:12,rf:4,a:2
[4/6]abba10lf:7,lp:3,rf:2,rp:1,a:2
[5/0]abbba32lf:16,lp:3,ls:13,rf:1,rp:1,lsrp:1
[5/1]abbbb21lf:11,lp:6,ls:4,rf:16,rp:10,rs:7,re:1,lprp:5,lsrp:4,lprs:2,a:3
[5/2]baabb14lf:14,rf:5,a:1
[5/3]aabbb13lf:13,rf:6
[5/4]bbaab12lf:12,rf:4,a:2
[5/5]bbbbb10lf:10,rf:16,rs:4,a:4
[5/6]bbbba8lf:7,ls:1,rf:5,rs:4,a:4
[6/0]aabbba16lf:8,ls:8
[6/1]bbaabb12lf:12,rf:4,a:2
[6/2]baabbb11lf:11,rf:5,a:1
[6/3]babbba10lf:5,ls:5,a:6
[6/4]abbbbb9lf:5,lp:4,rf:7,rp:7,rs:1,re:1,lprp:3,a:4
[6/5]aabbbb9lf:5,ls:4,rf:6,rs:6,a:6
[6/6]abbaab8lf:6,lp:2,rf:2,rp:1,a:2
[7/0]baabbba14lf:7,ls:7,a:1
[7/1]bbaabbb10lf:10,rf:4,a:2
[7/2]bbabbba8lf:4,ls:4,a:7
[7/3]baabbbb8lf:4,ls:4,rf:5,rs:5,a:7
[7/4]abbaabb8lf:6,lp:2,rf:2,rp:1,a:2
[7/5]bbbaabb6lf:6,rf:2,a:3
[7/6]abbbbbb5lf:3,lp:2,rf:5,rp:5,rs:1,re:1,lprp:2,a:5

Considering [length 4 / frequency 0] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbba=ab⟩.