Morphocompletion for #915 ⟨a, b | aaabbaa=ba⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabbaa ⇒ ba
2. aaabbaba ⇒ bba
3. baabbaa ⇒ aaabbba
4. aaabaaabbba ⇒ babbaa
5. aaabbabba ⇒ bbba
6. baabbaba ⇒ aaabbbba
7. aaabaaabbbba ⇒ babbaba
8. aaabbabbba ⇒ bbbba
9. baabbabba ⇒ aaabbbbba
10. aaabbbabbaa ⇒ baabaaabbba
11. aaabaaabbbbba ⇒ babbabba
12. aaabbabbbba ⇒ bbbbba
13. baabbabbba ⇒ aaabbbbbba
14. aaabaaabbbbbba ⇒ babbabbba
15. aaabbabbbbba ⇒ bbbbbba
16. baabbabbbba ⇒ aaabbbbbbba
17. aaabbabbbbbba ⇒ bbbbbbba
18. aaabbabbbbbbba ⇒ bbbbbbbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]ba59lf:39,lp:5,ls:15,rf:27,rp:6,rs:17,re:1,lsrp:4,lprs:5,lsrs:14
[2/1]aa58lf:42,lp:13,ls:3,rf:14,rp:5,rs:1,lsrp:1,lprs:1
[2/2]bb57lf:57,rf:57,rp:7
[2/3]ab34lf:34,rf:14
[3/0]bba41lf:28,ls:13,rf:19,rp:1,rs:15,re:1,lsrs:11
[3/1]aaa30lf:17,lp:13,rf:6,rp:5
[3/2]bbb29lf:29,rf:38,rp:6,a:1
[3/3]abb28lf:28,rf:12
[3/4]aab22lf:22,rf:7
[3/5]baa20lf:12,lp:5,ls:3,rf:3,rp:1,rs:1,lsrp:1
[3/6]bab12lf:12,rf:7,rp:4,a:2
[4/0]aaab30lf:17,lp:13,rf:6,rp:5
[4/1]bbba23lf:12,ls:11,rf:13,rp:1,rs:13,re:1,lsrs:8,a:1
[4/2]abba18lf:16,ls:2,rf:5,rs:1
[4/3]aabb18lf:18,rf:6
[4/4]bbbb17lf:17,rf:25,rp:5,a:3
[4/5]bbab12lf:12,rf:3,a:2
[4/6]abbb12lf:12,rf:7,a:1
[5/0]aaabb22lf:13,lp:9,rf:6,rp:5
[5/1]bbbba16lf:8,ls:8,rf:9,rp:1,rs:9,re:1,lsrs:5,a:3
[5/2]aabba13lf:13
[5/3]abbab11lf:11,rf:3,a:2
[5/4]bbabb10lf:10,rf:2,a:4
[5/5]baabb10lf:5,lp:5,a:1
[5/6]bbbbb9lf:9,rf:16,rp:4,a:6
[6/0]aaabba16lf:8,lp:8
[6/1]aabbab11lf:11,a:2
[6/2]bbbbba10lf:5,ls:5,rf:7,rp:1,rs:7,re:1,lsrs:3,a:6
[6/3]baabba10lf:5,lp:5,a:1
[6/4]abbabb9lf:9,rf:2,a:4
[6/5]aaabaa8lf:4,lp:4,a:9
[6/6]bbabbb7lf:7,rf:1,a:5
[7/0]aaabbab14lf:7,lp:7,a:2
[7/1]aabbabb9lf:9,a:4
[7/2]baabbab8lf:4,lp:4,a:3
[7/3]aaabaaa8lf:4,lp:4,a:9
[7/4]abbabbb7lf:7,rf:1,a:5
[7/5]bbbbbba6lf:3,ls:3,rf:5,rp:1,rs:5,re:1,lsrs:2,a:8
[7/6]bbabbbb5lf:5,a:7

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbaa=ba⟩.