| Back: | ⟨a, b | aaabbaa=ba⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabbaa ⇒ ba |
| 2. | aaabbaba ⇒ bba |
| 3. | baabbaa ⇒ aaabbba |
| 4. | aaabaaabbba ⇒ babbaa |
| 5. | aaabbabba ⇒ bbba |
| 6. | baabbaba ⇒ aaabbbba |
| 7. | aaabaaabbbba ⇒ babbaba |
| 8. | aaabbabbba ⇒ bbbba |
| 9. | baabbabba ⇒ aaabbbbba |
| 10. | aaabbbabbaa ⇒ baabaaabbba |
| 11. | aaabaaabbbbba ⇒ babbabba |
| 12. | aaabbabbbba ⇒ bbbbba |
| 13. | baabbabbba ⇒ aaabbbbbba |
| 14. | aaabaaabbbbbba ⇒ babbabbba |
| 15. | aaabbabbbbba ⇒ bbbbbba |
| 16. | baabbabbbba ⇒ aaabbbbbbba |
| 17. | aaabbabbbbbba ⇒ bbbbbbba |
| 18. | aaabbabbbbbbba ⇒ bbbbbbbba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ba, [2/1] aa, [2/2] bb, [2/3] ab |
|---|---|
| Length 3: | [3/0] bba, [3/1] aaa, [3/2] bbb, [3/3] abb, [3/4] aab, [3/5] baa, [3/6] bab |
| Length 4: | [4/0] aaab, [4/1] bbba, [4/2] abba, [4/3] aabb, [4/4] bbbb, [4/5] bbab, [4/6] abbb |
| Length 5: | [5/0] aaabb, [5/1] bbbba, [5/2] aabba, [5/3] abbab, [5/4] bbabb, [5/5] baabb, [5/6] bbbbb |
| Length 6: | [6/0] aaabba, [6/1] aabbab, [6/2] bbbbba, [6/3] baabba, [6/4] abbabb, [6/5] aaabaa, [6/6] bbabbb |
| Length 7: | [7/0] aaabbab, [7/1] aabbabb, [7/2] baabbab, [7/3] aaabaaa, [7/4] abbabbb, [7/5] bbbbbba, [7/6] bbabbbb |
Considering [length 3 / frequency 0] bba=c.
Rewriting system is complete. See ⟨a, b | aaabbaa=ba⟩.