| Back: | ⟨a, b | aaabbaa=ab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | aaabbaa ⇒ ab |
| 2. | abaabbaa ⇒ abb |
| 3. | aaabbb ⇒ abbbaa |
| 4. | aaabbab ⇒ ababbaa |
| 5. | abbaabbaa ⇒ abbb |
| 6. | abaabbb ⇒ abbbbaa |
| 7. | abaabbab ⇒ abbabbaa |
| 8. | abbbaabbaa ⇒ abbbb |
| 9. | abbaabbb ⇒ abbbbbaa |
| 10. | abbaabbab ⇒ abbbabbaa |
| 11. | abbbbaabbaa ⇒ abbbbb |
| 12. | abbbaabbb ⇒ abbbbbbaa |
| 13. | abbbaabbab ⇒ abbbbabbaa |
| 14. | abbbbbaabbaa ⇒ abbbbbb |
| 15. | abbbbaabbb ⇒ abbbbbbbaa |
| 16. | abbbbaabbab ⇒ abbbbbabbaa |
| 17. | abbbbbbaabbaa ⇒ abbbbbbb |
| 18. | abbbbbaabbb ⇒ abbbbbbbbaa |
| 19. | abbbbbaabbab ⇒ abbbbbbabbaa |
| 20. | abbbbbbbaabbaa ⇒ abbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 73 | lf:67,ls:6,rf:76,rs:7 |
|---|---|---|---|
| [2/1] | ab | 66 | lf:43,lp:17,ls:6,rf:26,rp:20,rs:1,re:1,lprp:17,lsrp:6 |
| [2/2] | aa | 42 | lf:31,lp:3,ls:8,rf:12,rs:12,lprs:2 |
| [2/3] | ba | 31 | lf:31,rf:18 |
| [3/0] | abb | 48 | lf:34,lp:14,rf:24,rp:18,rs:1,re:1,lprp:14 |
| [3/1] | bbb | 39 | lf:33,ls:6,rf:52,rs:6,a:3 |
| [3/2] | baa | 33 | lf:25,ls:8,rf:12,rs:12 |
| [3/3] | bba | 28 | lf:28,rf:17 |
| [3/4] | aab | 20 | lf:20 |
| [3/5] | bab | 12 | lf:6,ls:6,rf:6,a:1 |
| [3/6] | aba | 6 | lf:3,lp:3,rf:1,rp:1,a:1 |
| [4/0] | abbb | 34 | lf:17,lp:11,ls:6,rf:16,rp:16,rs:1,re:1,lprp:11,lsrp:6,a:3 |
| [4/1] | bbaa | 30 | lf:22,ls:8,rf:12,rs:12 |
| [4/2] | aabb | 20 | lf:20 |
| [4/3] | abba | 20 | lf:17,lp:3,rf:7,rp:1 |
| [4/4] | baab | 17 | lf:17,a:2 |
| [4/5] | bbbb | 16 | lf:16,rf:36,rs:5,a:5 |
| [4/6] | bbab | 12 | lf:6,ls:6,rf:5,a:1 |
| [5/0] | abbaa | 22 | lf:11,lp:3,ls:8,rf:6,rs:6,lprs:1 |
| [5/1] | baabb | 17 | lf:17,a:2 |
| [5/2] | abbbb | 16 | lf:8,lp:8,rf:13,rp:13,rs:1,re:1,lprp:8,a:5 |
| [5/3] | bbaab | 14 | lf:14,a:3 |
| [5/4] | aabba | 14 | lf:14 |
| [5/5] | aabbb | 12 | lf:6,ls:6,a:6 |
| [5/6] | abbab | 12 | lf:6,ls:6,rf:1,rp:1,lsrp:1,a:1 |
| [6/0] | aabbaa | 16 | lf:8,ls:8 |
| [6/1] | bbaabb | 14 | lf:14,a:3 |
| [6/2] | aabbab | 12 | lf:6,ls:6,a:1 |
| [6/3] | baabba | 12 | lf:12,a:2 |
| [6/4] | bbbaab | 11 | lf:11,a:5 |
| [6/5] | abbbbb | 10 | lf:5,lp:5,rf:10,rp:10,rs:1,re:1,lprp:5,a:9 |
| [6/6] | baabbb | 10 | lf:5,ls:5,a:7 |
| [7/0] | baabbaa | 14 | lf:7,ls:7,a:2 |
| [7/1] | bbbaabb | 11 | lf:11,a:5 |
| [7/2] | baabbab | 10 | lf:5,ls:5,a:4 |
| [7/3] | bbaabba | 10 | lf:10,a:3 |
| [7/4] | bbaabbb | 8 | lf:4,ls:4,a:10 |
| [7/5] | bbbbaab | 8 | lf:8,a:9 |
| [7/6] | abbbbba | 6 | lf:3,lp:3,rf:2,rp:2,a:10 |
Considering [length 3 / frequency 0] abb=c.
Rewriting system is complete. See ⟨a, b | aaabbaa=ab⟩.