Morphocompletion for #914 ⟨a, b | aaabbaa=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaabbaa ⇒ ab
2. abaabbaa ⇒ abb
3. aaabbb ⇒ abbbaa
4. aaabbab ⇒ ababbaa
5. abbaabbaa ⇒ abbb
6. abaabbb ⇒ abbbbaa
7. abaabbab ⇒ abbabbaa
8. abbbaabbaa ⇒ abbbb
9. abbaabbb ⇒ abbbbbaa
10. abbaabbab ⇒ abbbabbaa
11. abbbbaabbaa ⇒ abbbbb
12. abbbaabbb ⇒ abbbbbbaa
13. abbbaabbab ⇒ abbbbabbaa
14. abbbbbaabbaa ⇒ abbbbbb
15. abbbbaabbb ⇒ abbbbbbbaa
16. abbbbaabbab ⇒ abbbbbabbaa
17. abbbbbbaabbaa ⇒ abbbbbbb
18. abbbbbaabbb ⇒ abbbbbbbbaa
19. abbbbbaabbab ⇒ abbbbbbabbaa
20. abbbbbbbaabbaa ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] aa, [2/3] ba
Length 3:[3/0] abb, [3/1] bbb, [3/2] baa, [3/3] bba, [3/4] aab, [3/5] bab, [3/6] aba
Length 4:[4/0] abbb, [4/1] bbaa, [4/2] aabb, [4/3] abba, [4/4] baab, [4/5] bbbb, [4/6] bbab
Length 5:[5/0] abbaa, [5/1] baabb, [5/2] abbbb, [5/3] bbaab, [5/4] aabba, [5/5] aabbb, [5/6] abbab
Length 6:[6/0] aabbaa, [6/1] bbaabb, [6/2] aabbab, [6/3] baabba, [6/4] bbbaab, [6/5] abbbbb, [6/6] baabbb
Length 7:[7/0] baabbaa, [7/1] bbbaabb, [7/2] baabbab, [7/3] bbaabba, [7/4] bbaabbb, [7/5] bbbbaab, [7/6] abbbbba

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaabbaa=ab.