Morphocompletion for #891 ⟨a, b | aaaabba=ab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabba ⇒ ab
2. abaabba ⇒ aaaabbb
3. abaaabba ⇒ abb
4. aaaabaaabbb ⇒ ababba
5. abbaabba ⇒ abaaabbb
6. abbaaabba ⇒ abbb
7. abaaabaaabbb ⇒ abbabba
8. aaaabbbabba ⇒ abaabaaabbb
9. abbbaabba ⇒ abbaaabbb
10. abbbaaabba ⇒ abbbb
11. abbaaabaaabbb ⇒ abbbabba
12. abbbbaabba ⇒ abbbaaabbb
13. abbbbaaabba ⇒ abbbbb
14. abbbaaabaaabbb ⇒ abbbbabba
15. abbbbbaabba ⇒ abbbbaaabbb
16. abbbbbaaabba ⇒ abbbbbb
17. abbbbbbaaabba ⇒ abbbbbbb
18. abbbbbbbaaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] bbb, [3/3] aaa, [3/4] aab, [3/5] baa, [3/6] aba
Length 4:[4/0] abba, [4/1] abbb, [4/2] aabb, [4/3] aaab, [4/4] baaa, [4/5] bbbb, [4/6] bbaa
Length 5:[5/0] aabba, [5/1] baaab, [5/2] aaabb, [5/3] abbbb, [5/4] bbbaa, [5/5] aabbb, [5/6] bbaaa
Length 6:[6/0] aaabba, [6/1] baaabb, [6/2] baabba, [6/3] aaabbb, [6/4] abbbbb, [6/5] bbaaab, [6/6] abaaab
Length 7:[7/0] baaabba, [7/1] bbaabba, [7/2] baaabbb, [7/3] bbbaaab, [7/4] bbaaabb, [7/5] abaaabb, [7/6] abbbbbb

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See a, b | aaaabba=ab.