Morphocompletion for #891 ⟨a, b | aaaabba=ab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabba ⇒ ab
2. abaabba ⇒ aaaabbb
3. abaaabba ⇒ abb
4. aaaabaaabbb ⇒ ababba
5. abbaabba ⇒ abaaabbb
6. abbaaabba ⇒ abbb
7. abaaabaaabbb ⇒ abbabba
8. aaaabbbabba ⇒ abaabaaabbb
9. abbbaabba ⇒ abbaaabbb
10. abbbaaabba ⇒ abbbb
11. abbaaabaaabbb ⇒ abbbabba
12. abbbbaabba ⇒ abbbaaabbb
13. abbbbaaabba ⇒ abbbbb
14. abbbaaabaaabbb ⇒ abbbbabba
15. abbbbbaabba ⇒ abbbbaaabbb
16. abbbbbaaabba ⇒ abbbbbb
17. abbbbbbaaabba ⇒ abbbbbbb
18. abbbbbbbaaabba ⇒ abbbbbbbb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb62lf:58,ls:4,rf:56,rs:13
[2/1]ab53lf:38,lp:15,rf:28,rp:17,rs:1,re:1,lprp:14
[2/2]ba48lf:34,ls:14,rf:14,rs:4
[2/3]aa45lf:42,lp:3,rf:14,rp:1
[3/0]abb43lf:31,lp:12,rf:23,rp:13,rs:1,re:1,lprp:11
[3/1]bba41lf:27,ls:14,rf:10,rs:4
[3/2]bbb31lf:27,ls:4,rf:33,rs:12,a:2
[3/3]aaa23lf:20,lp:3,rf:7,rp:1
[3/4]aab22lf:22,rf:7
[3/5]baa19lf:19,rf:6,a:1
[3/6]aba10lf:7,lp:3,rf:4,rp:3,a:1
[4/0]abba34lf:17,lp:3,ls:14,rf:6,rp:2,rs:4,lsrp:1,lprs:1
[4/1]abbb27lf:14,lp:9,ls:4,rf:16,rp:10,rs:7,re:1,lprp:8,lsrp:2,lprs:3,a:2
[4/2]aabb18lf:18,rf:6
[4/3]aaab17lf:17,rf:6
[4/4]baaa14lf:14,rf:5,a:1
[4/5]bbbb13lf:13,rf:17,rs:5,a:3
[4/6]bbaa12lf:12,rf:3,a:2
[5/0]aabba26lf:13,ls:13
[5/1]baaab14lf:14,rf:5,a:1
[5/2]aaabb13lf:13,rf:6
[5/3]abbbb12lf:6,lp:6,rf:7,rp:7,rs:1,re:1,lprp:5,a:3
[5/4]bbbaa9lf:9,rf:2,a:3
[5/5]aabbb9lf:5,ls:4,rf:6,rs:6,a:4
[5/6]bbaaa8lf:8,rf:3,a:2
[6/0]aaabba16lf:8,ls:8
[6/1]baaabb11lf:11,rf:5,a:1
[6/2]baabba10lf:5,ls:5,a:4
[6/3]aaabbb9lf:5,ls:4,rf:6,rs:6,a:4
[6/4]abbbbb8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:3,a:6
[6/5]bbaaab8lf:8,rf:3,a:2
[6/6]abaaab8lf:6,lp:2,rf:2,rp:1,a:1
[7/0]baaabba14lf:7,ls:7,a:1
[7/1]bbaabba8lf:4,ls:4,a:5
[7/2]baaabbb8lf:4,ls:4,rf:5,rs:5,a:5
[7/3]bbbaaab6lf:6,rf:2,a:3
[7/4]bbaaabb6lf:6,rf:3,a:2
[7/5]abaaabb6lf:5,lp:1,rf:2,rp:1,a:1
[7/6]abbbbbb4lf:2,lp:2,rf:3,rp:3,rs:1,re:1,lprp:2,a:8

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaaabba=ab⟩.