| Back: | ⟨a, b | abbaabba=b⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbab ⇒ babba |
| 2. | abbaabba ⇒ b |
| 3. | abbbbb ⇒ bbbbba |
| 4. | abbbabba ⇒ bbabbaab |
| 5. | abbaabbb ⇒ bbbaabba |
| 6. | abbaaabbb ⇒ bbbaaabba |
| 7. | bbabbaaabba ⇒ abbb |
| 8. | bbabbaaaabba ⇒ aabbb |
| 9. | bbabbaaaaabba ⇒ aaabbb |
| 10. | bbabbaaaaaabba ⇒ aaaabbb |
| 11. | abbbbabba ⇒ bbabbaabb |
| 12. | bbabbaababba ⇒ abbbb |
| 13. | bbabbaabaabba ⇒ ababbb |
| 14. | bbabbaaababba ⇒ aabbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 51 | lf:41,lp:7,ls:3,rf:32,rp:5,rs:8,lsrp:3,lprs:7 |
|---|---|---|---|
| [2/1] | ba | 43 | lf:33,ls:10,rf:12,rp:1,rs:4 |
| [2/2] | ab | 38 | lf:30,lp:7,ls:1,rf:15,rp:3,rs:1,lprs:1 |
| [2/3] | aa | 23 | lf:23,rf:12,rp:4 |
| [3/0] | bba | 47 | lf:30,lp:7,ls:10,rf:10,rp:2,rs:4,lsrp:2 |
| [3/1] | abb | 33 | lf:26,lp:7,rf:13,rp:2,rs:1,lprs:1 |
| [3/2] | bab | 13 | lf:12,ls:1,rf:4,rp:1,lsrp:1,a:1 |
| [3/3] | aaa | 12 | lf:12,rf:4,rp:2,a:3 |
| [3/4] | bbb | 11 | lf:8,ls:3,rf:14,rp:3,rs:7,lsrp:3,a:2 |
| [3/5] | aab | 11 | lf:11,rf:8,rp:2,rs:1 |
| [3/6] | baa | 11 | lf:11,rf:4 |
| [4/0] | abba | 35 | lf:21,lp:4,ls:10,rf:5,rs:3,lprs:12 |
| [4/1] | bbab | 18 | lf:10,lp:7,ls:1,rf:2,rp:2,a:1 |
| [4/2] | babb | 11 | lf:11,rf:4,rp:1,a:1 |
| [4/3] | abbb | 10 | lf:5,lp:3,ls:2,rf:7,rp:2,rs:5,re:1,a:2 |
| [4/4] | bbaa | 10 | lf:10,rf:4 |
| [4/5] | aabb | 8 | lf:8,rf:7,rp:2,rs:1 |
| [4/6] | aaab | 6 | lf:6,rf:3,rp:1,a:3 |
| [5/0] | bbabb | 16 | lf:9,lp:7,rf:2,rp:2,a:3 |
| [5/1] | babba | 15 | lf:11,ls:4,rf:3,rp:1,rs:1,re:1,a:1 |
| [5/2] | abbaa | 13 | lf:10,lp:3,rf:2 |
| [5/3] | aabba | 12 | lf:6,ls:6,rf:2,rs:2 |
| [5/4] | bbaaa | 6 | lf:6,rf:1,a:3 |
| [5/5] | aaabb | 5 | lf:5,rf:3,rp:1,a:3 |
| [5/6] | abbbb | 4 | lf:2,lp:2,rf:2,rp:1,rs:2,re:1,a:6 |
| [6/0] | bbabba | 18 | lf:9,lp:7,ls:2,rf:2,rp:2,lsrp:2,a:3 |
| [6/1] | aaabba | 8 | lf:4,ls:4,rf:1,rs:1,a:3 |
| [6/2] | babbaa | 7 | lf:7,rf:2,a:3 |
| [6/3] | abbaaa | 7 | lf:6,lp:1,a:3 |
| [6/4] | abbaab | 6 | lf:4,lp:2,rf:2,rs:1 |
| [6/5] | ababba | 4 | lf:2,ls:2,a:6 |
| [6/6] | baabba | 4 | lf:2,ls:2,rf:1,rs:1 |
| [7/0] | bbabbaa | 14 | lf:7,lp:7,rf:2,rp:2,a:3 |
| [7/1] | aaaabba | 6 | lf:3,ls:3,a:5 |
| [7/2] | babbaaa | 5 | lf:5,a:3 |
| [7/3] | bbbabba | 4 | lf:2,ls:2,a:4 |
| [7/4] | abbaabb | 4 | lf:2,lp:2,rf:1,rs:1 |
| [7/5] | aababba | 4 | lf:2,ls:2,a:6 |
| [7/6] | abbaaab | 4 | lf:3,lp:1,a:3 |
Considering [length 3 / frequency 0] bba=c.
Rewriting system is complete. See ⟨a, b | abbaabba=b⟩.