Morphocompletion for #860 ⟨a, b | abbaabba=b⟩

Back:⟨a, b | abbaabba=b⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbab ⇒ babba
2. abbaabba ⇒ b
3. abbbbb ⇒ bbbbba
4. abbbabba ⇒ bbabbaab
5. abbaabbb ⇒ bbbaabba
6. abbaaabbb ⇒ bbbaaabba
7. bbabbaaabba ⇒ abbb
8. bbabbaaaabba ⇒ aabbb
9. bbabbaaaaabba ⇒ aaabbb
10. bbabbaaaaaabba ⇒ aaaabbb
11. abbbbabba ⇒ bbabbaabb
12. bbabbaababba ⇒ abbbb
13. bbabbaabaabba ⇒ ababbb
14. bbabbaaababba ⇒ aabbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] bab, [3/3] aaa, [3/4] bbb, [3/5] aab, [3/6] baa
Length 4:[4/0] abba, [4/1] bbab, [4/2] babb, [4/3] abbb, [4/4] bbaa, [4/5] aabb, [4/6] aaab
Length 5:[5/0] bbabb, [5/1] babba, [5/2] abbaa, [5/3] aabba, [5/4] bbaaa, [5/5] aaabb, [5/6] abbbb
Length 6:[6/0] bbabba, [6/1] aaabba, [6/2] babbaa, [6/3] abbaaa, [6/4] abbaab, [6/5] ababba, [6/6] baabba
Length 7:[7/0] bbabbaa, [7/1] aaaabba, [7/2] babbaaa, [7/3] bbbabba, [7/4] abbaabb, [7/5] aababba, [7/6] abbaaab

Considering [length 3 / frequency 0] bba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaabba=b⟩.