| Back: | ⟨a, b | ababaaab=b⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaabb ⇒ baaab |
| 2. | ababab ⇒ babaab |
| 3. | ababaab ⇒ babaaab |
| 4. | ababaaab ⇒ b |
| 5. | aaababb ⇒ babaaab |
| 6. | aaabaabb ⇒ baabaaab |
| 7. | babaabaaab ⇒ abb |
| 8. | babaaabaaab ⇒ aabb |
| 9. | abbabab ⇒ babaabb |
| 10. | ababbaaab ⇒ bb |
| 11. | aabbabb ⇒ babbaab |
| 12. | aaabaababb ⇒ bab |
| 13. | babaabbaaab ⇒ abbb |
| 14. | ababbbaaab ⇒ bbb |
| 15. | ababbbbaaab ⇒ bbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 57 | lf:40,lp:7,ls:10,rf:17,rp:2,rs:7,lsrp:2,lprs:2,lsrs:2 |
|---|---|---|---|
| [2/1] | aa | 35 | lf:30,lp:5,rf:13,rp:1 |
| [2/2] | ba | 31 | lf:28,lp:3,rf:14,rp:8 |
| [2/3] | bb | 19 | lf:14,ls:5,rf:12,rp:3,rs:7,re:1,a:3 |
| [3/0] | aab | 27 | lf:18,lp:1,ls:8,rf:9,rp:1,rs:6,lsrp:1,lprs:1,lsrs:1 |
| [3/1] | aba | 25 | lf:19,lp:6,rf:5 |
| [3/2] | bab | 20 | lf:15,lp:3,ls:2,rf:6,rp:6,rs:1,re:1,lsrp:2 |
| [3/3] | abb | 17 | lf:11,lp:1,ls:5,rf:5,rp:2,rs:3,re:1,lprs:1,a:3 |
| [3/4] | aaa | 16 | lf:12,lp:4,rf:4 |
| [3/5] | baa | 13 | lf:13,rf:8,rp:2 |
| [3/6] | bba | 6 | lf:6,rf:1,a:10 |
| [4/0] | aaab | 23 | lf:12,lp:4,ls:7,rf:4,rs:4,lprs:12 |
| [4/1] | abab | 18 | lf:10,lp:6,ls:2 |
| [4/2] | baba | 10 | lf:7,lp:3,rf:4,rp:4 |
| [4/3] | babb | 9 | lf:6,ls:3,rf:1,rp:1,lsrp:1,a:10 |
| [4/4] | abaa | 9 | lf:9,rf:5 |
| [4/5] | baaa | 8 | lf:8,rf:4,rp:1 |
| [4/6] | aabb | 7 | lf:4,lp:1,ls:2,rf:2,rp:1,rs:2,re:1,a:6 |
| [5/0] | baaab | 15 | lf:8,ls:7,rf:4,rp:1,rs:4,re:1 |
| [5/1] | ababb | 10 | lf:5,lp:3,ls:2,a:10 |
| [5/2] | babaa | 8 | lf:5,lp:3,rf:4,rp:4 |
| [5/3] | aaaba | 7 | lf:4,lp:3,a:6 |
| [5/4] | abaab | 6 | lf:5,ls:1,rf:2,rs:1,a:1 |
| [5/5] | ababa | 6 | lf:3,lp:3 |
| [5/6] | babab | 4 | lf:2,ls:2,a:2 |
| [6/0] | bbaaab | 8 | lf:4,ls:4,a:10 |
| [6/1] | abaaab | 7 | lf:4,ls:3,rf:3,rs:3 |
| [6/2] | babaab | 6 | lf:3,lp:2,ls:1,rf:2,rp:2,rs:1,re:1,a:1 |
| [6/3] | aaabaa | 5 | lf:3,lp:2,a:6 |
| [6/4] | ababbb | 4 | lf:2,lp:2,a:18 |
| [6/5] | aababb | 4 | lf:2,ls:2,a:13 |
| [6/6] | ababaa | 4 | lf:2,lp:2 |
| [7/0] | bbbaaab | 4 | lf:2,ls:2,a:18 |
| [7/1] | abbaaab | 4 | lf:2,ls:2,a:10 |
| [7/2] | babaaab | 4 | lf:2,lp:1,ls:1,rf:2,rp:2,rs:2,re:2 |
| [7/3] | aaabaab | 4 | lf:2,lp:2,a:14 |
| [7/4] | aabaaab | 4 | lf:2,ls:2,rf:1,rs:1,a:3 |
| [7/5] | ababbbb | 2 | lf:1,lp:1,a:23 |
| [7/6] | ababbba | 2 | lf:1,lp:1,a:18 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | ababaaab=b⟩.