Morphocompletion for #812 ⟨a, b | aabbaaab=a

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaab ⇒ aabbaa
2. aaaababb ⇒ a
3. aabbaaa ⇒ aaaabab
4. aaaababababb ⇒ aabba
5. aaaabababba ⇒ aaaabaababb
6. aaaabbbaaa ⇒ aaaabaabab
7. abaaaaabab ⇒ aabbaabaaa
8. abaaaabbaa ⇒ aaaababaab
9. aaaabaababba ⇒ aaaab
10. aaaababaabab ⇒ abaaa
11. abaaaaaabab ⇒ aaaababaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] bab, [3/4] baa, [3/5] abb, [3/6] bba
Length 4:[4/0] aaaa, [4/1] abab, [4/2] aaab, [4/3] abaa, [4/4] aaba, [4/5] baaa, [4/6] abba
Length 5:[5/0] aaaab, [5/1] aabab, [5/2] abaaa, [5/3] aaaba, [5/4] ababb, [5/5] bbaaa, [5/6] ababa
Length 6:[6/0] aaaaba, [6/1] aaabab, [6/2] abaaaa, [6/3] aabbaa, [6/4] ababba, [6/5] aababa, [6/6] aaaabb
Length 7:[7/0] aaaabab, [7/1] abaaaaa, [7/2] aaababa, [7/3] abaabab, [7/4] abababb, [7/5] aaaabaa, [7/6] aaaaaba

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See a, b | aabbaaab=a.