Morphocompletion for #768 ⟨a, b | aaababaa=a⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aababa ⇒ ababaa
2. aaaaba ⇒ abaaaa
3. ababaaaa ⇒ a
4. ababaabaaaa ⇒ aaba
5. ababaaabaaaa ⇒ aaaba
6. ababaabaabaaaa ⇒ aabaaba
7. ababaabaaabaaaa ⇒ aabaaaba
8. ababaaabaabaaaa ⇒ aaabaaba
9. ababaaabaaabaaaa ⇒ aaabaaaba
10. ababaabaabaabaaaa ⇒ aabaabaaba
11. ababaabaabaaabaaaa ⇒ aabaabaaaba
12. ababaabaaabaabaaaa ⇒ aabaaabaaba
13. ababaaabaabaabaaaa ⇒ aaabaabaaba
14. ababaabaaabaaabaaaa ⇒ aabaaabaaaba
15. ababaaabaabaaabaaaa ⇒ aaabaabaaaba
16. ababaaabaaabaabaaaa ⇒ aaabaaabaaba
17. ababaabaabaabaabaaaa ⇒ aabaabaabaaba
18. ababaaabaaabaaabaaaa ⇒ aaabaaabaaaba
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa125lf:107,lp:2,ls:16,rf:59,rp:15,rs:2,lsrp:15,lprs:2,a:2
[2/1]ab89lf:73,lp:16,rf:41,rp:2,a:2
[2/2]ba75lf:73,ls:2,rf:41,rs:15,a:2
[3/0]aba91lf:73,lp:16,ls:2,rf:41,rp:2,rs:15,lsrp:2,lprs:15,a:2
[3/1]aaa68lf:51,lp:1,ls:16,rf:19,rp:7,rs:1,lsrp:7,lprs:1,a:2
[3/2]baa54lf:54,rf:25,rs:1,a:2
[3/3]aab41lf:40,lp:1,rf:38,rp:8,a:3
[3/4]bab17lf:17,rf:1,a:2
[4/0]abaa54lf:54,rf:25,rp:1,rs:1,a:2
[4/1]aaba42lf:40,lp:1,ls:1,rf:38,rp:8,rs:15,re:1,a:3
[4/2]aaaa34lf:17,lp:1,ls:16,rf:1,rs:1,lprs:1,a:2
[4/3]abab33lf:17,lp:16,rf:1,rp:1,a:2
[4/4]baaa33lf:33,rf:11,a:2
[4/5]baab21lf:21,rf:13,a:6
[4/6]aaab18lf:18,rf:17,rp:7,a:5
[5/0]aabaa38lf:38,rf:23,rp:7,a:5
[5/1]ababa34lf:17,lp:16,ls:1,rf:1,rp:1,lsrp:10,a:2
[5/2]abaaa33lf:33,rf:11,rp:1,a:2
[5/3]baaaa32lf:16,ls:16,rf:1,rs:1,a:2
[5/4]abaab21lf:21,rf:13,a:6
[5/5]baaba21lf:21,rf:13,rs:7,a:6
[5/6]aaaba19lf:18,ls:1,rf:17,rp:7,rs:7,re:1,a:5
[6/0]abaaaa32lf:16,ls:16,rf:1,rp:1,rs:1,re:1,a:2
[6/1]ababaa32lf:16,lp:16,rf:1,rp:1,rs:1,re:1,a:2
[6/2]aabaaa25lf:25,rf:10,rp:3,a:5
[6/3]abaaba21lf:21,rf:13,rs:7,a:6
[6/4]baabaa21lf:21,rf:6,a:6
[6/5]aaabaa17lf:17,rf:10,rp:6,a:5
[6/6]abaaab17lf:17,rf:10,a:5
[7/0]aabaaaa30lf:15,ls:15,a:5
[7/1]abaabaa21lf:21,rf:6,a:6
[7/2]abaaaba17lf:17,rf:10,rs:6,a:5
[7/3]baaabaa17lf:17,rf:4,a:5
[7/4]ababaaa16lf:8,lp:8,a:2
[7/5]ababaab16lf:8,lp:8,a:6
[7/6]aabaaba13lf:13,rf:13,rp:4,rs:7,re:1,a:8

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababaa=a⟩.