Morphocompletion for #768 ⟨a, b | aaababaa=a⟩

Back:⟨a, b | aaababaa=a⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aababa ⇒ ababaa
2. aaaaba ⇒ abaaaa
3. ababaaaa ⇒ a
4. ababaabaaaa ⇒ aaba
5. ababaaabaaaa ⇒ aaaba
6. ababaabaabaaaa ⇒ aabaaba
7. ababaabaaabaaaa ⇒ aabaaaba
8. ababaaabaabaaaa ⇒ aaabaaba
9. ababaaabaaabaaaa ⇒ aaabaaaba
10. ababaabaabaabaaaa ⇒ aabaabaaba
11. ababaabaabaaabaaaa ⇒ aabaabaaaba
12. ababaabaaabaabaaaa ⇒ aabaaabaaba
13. ababaaabaabaabaaaa ⇒ aaabaabaaba
14. ababaabaaabaaabaaaa ⇒ aabaaabaaaba
15. ababaaabaabaaabaaaa ⇒ aaabaabaaaba
16. ababaaabaaabaabaaaa ⇒ aaabaaabaaba
17. ababaabaabaabaabaaaa ⇒ aabaabaabaaba
18. ababaaabaaabaaabaaaa ⇒ aaabaaabaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab
Length 4:[4/0] abaa, [4/1] aaba, [4/2] aaaa, [4/3] abab, [4/4] baaa, [4/5] baab, [4/6] aaab
Length 5:[5/0] aabaa, [5/1] ababa, [5/2] abaaa, [5/3] baaaa, [5/4] abaab, [5/5] baaba, [5/6] aaaba
Length 6:[6/0] abaaaa, [6/1] ababaa, [6/2] aabaaa, [6/3] abaaba, [6/4] baabaa, [6/5] aaabaa, [6/6] abaaab
Length 7:[7/0] aabaaaa, [7/1] abaabaa, [7/2] abaaaba, [7/3] baaabaa, [7/4] ababaaa, [7/5] ababaab, [7/6] aabaaba

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababaa=a⟩.