Morphocompletion for #72 ⟨a, b | abbaab=1⟩

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baab ⇒ abba
2. abbaa ⇒ aabab
3. aababb ⇒ 1
4. baaabba ⇒ aababab
5. baaaabab ⇒ aabababa
6. abbabaaabab ⇒ babaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] abb, [3/2] aab, [3/3] bab
Length 4:[4/0] abba, [4/1] baaa, [4/2] abab, [4/3] aaba
Length 5:[5/0] aabab, [5/1] baaab, [5/2] baaaa, [5/3] abbab
Length 6:[6/0] aaabab, [6/1] baaabb, [6/2] baaaab, [6/3] abbaba

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cacc ⇒ a
2. ccbc ⇒ b
3. caa ⇒ aacccc
4. caca ⇒ aacc
5. ab ⇒ c
6. accb ⇒ 1
7. cacb ⇒ acbc
8. ba ⇒ accccccb
9. bacc ⇒ 1
10. cba ⇒ bac
11. cbca ⇒ bcac
12. cbcca ⇒ bccac
13. ccbb ⇒ bcbc
14. aaccccb ⇒ cac
15. baa ⇒ acccc
16. baca ⇒ acc
17. bacb ⇒ cbc
18. bbac ⇒ ccb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cb, [2/1] ca, [2/2] cc, [2/3] ba, [2/4] ac, [2/5] aa, [2/6] bb
Length 3:[3/0] bac, [3/1] ccb, [3/2] acc, [3/3] cbc, [3/4] cac, [3/5] acb, [3/6] aca
Length 4:[4/0] bcca, [4/1] aacc, [4/2] cccb, [4/3] cbcc, [4/4] accc, [4/5] cccc, [4/6] bcbc
Length 5:[5/0] aaccc, [5/1] ccccb, [5/2] acccc, [5/3] bccac, [5/4] ccccc

Considering [length 3 / frequency 0] bac=d.

Step 3

Rewriting system is complete. See a, b | abbaab=1⟩.