Morphocompletion for #71 ⟨a, b | ababba=1⟩

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baab ⇒ abba
2. abab ⇒ bbaa
3. babbaa ⇒ 1
4. bbaaab ⇒ abbbaa
5. baaabb ⇒ aabbba
6. baaabba ⇒ aabbbaa
7. bbaaaab ⇒ aabbaba
8. bbabaaab ⇒ abbbabaa
9. baaaabbb ⇒ aaabbbba
10. baaabbbbaa ⇒ aabb
11. baaabbbabba ⇒ aabbb
12. aabbabbabaa ⇒ baaab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ba29lf:20,lp:7,ls:2,rf:11,rp:1,rs:4,lprs:3,a:2
[2/1]aa27lf:23,lp:1,ls:3,rf:13,rp:6,rs:4,lsrp:1,a:2
[2/2]ab23lf:17,lp:1,ls:5,rf:12,rp:3,rs:1,lsrp:3,a:2
[2/3]bb21lf:16,lp:3,ls:2,rf:17,rp:1,rs:2,a:2
[3/0]baa21lf:12,lp:6,ls:3,rf:5,rp:1,rs:4,lsrp:1,lprs:1,a:2
[3/1]aab15lf:10,lp:1,ls:4,rf:7,rp:5,rs:1,lsrp:1,lprs:1,a:8
[3/2]bba15lf:10,lp:3,ls:2,rf:8,rp:1,rs:3,a:2
[3/3]aaa10lf:10,rf:2,rp:1,a:8
[4/0]baaa13lf:8,lp:5,rf:1,rp:1,a:8
[4/1]aaab11lf:8,ls:3,rf:2,rp:1,rs:1,a:8
[4/2]aabb8lf:6,lp:1,ls:1,rf:6,rp:5,rs:1,re:1,lsrp:1,a:17
[4/3]bbaa8lf:4,lp:2,ls:2,rf:3,rp:1,rs:3,re:1,lprs:1,a:2
[5/0]baaab12lf:6,lp:4,ls:2,rf:1,rp:1,rs:1,re:1,a:8
[5/1]aaabb6lf:5,ls:1,rf:1,rp:1,a:19
[5/2]babba5lf:3,lp:1,ls:1,a:2
[5/3]aabba4lf:2,lp:1,ls:1,rf:1,rp:1,a:17
[6/0]baaabb6lf:3,lp:3,a:19
[6/1]baaaab4lf:2,lp:1,ls:1,a:17
[6/2]aaabbb4lf:3,ls:1,rf:1,rp:1,lsrp:1,a:23
[6/3]bbabaa4lf:2,lp:1,ls:1,rf:1,rs:1,lprs:1,a:22

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccbc ⇒ b
2. bbc ⇒ ccccbb
3. bcbc ⇒ ccbb
4. ba ⇒ c
5. cbca ⇒ 1
6. bbca ⇒ ccb
7. bcac ⇒ 1
8. bccac ⇒ cbcca
9. cbccac ⇒ bca
10. cacc ⇒ a
11. bcab ⇒ cbc
12. bccab ⇒ cbcc
13. bcccab ⇒ cbccc
14. acb ⇒ bca
15. acccb ⇒ cbcca
16. abc ⇒ cab
17. bcaa ⇒ acc
18. aacc ⇒ caca
...

Collecting factors up to length 6 / frequency 7:

[2/0]bc25lf:14,lp:7,ls:4,rf:7,rp:2,rs:1,lprs:1,a:3
[2/1]ca13lf:10,lp:1,ls:2,rf:7,rp:2,rs:5,a:6
[2/2]cc13lf:10,lp:1,ls:2,rf:11,rp:3,rs:3,a:3
[2/3]ac12lf:7,lp:2,ls:3,rf:2,rp:1,a:7
[2/4]cb10lf:6,lp:2,ls:2,rf:8,rp:5,rs:1,lsrp:1,a:3
[2/5]ab8lf:4,lp:1,ls:3,rf:1,rs:1,lprs:10,a:10
[2/6]aa4lf:2,lp:1,ls:1,a:11
[3/0]bca10lf:5,lp:3,ls:2,rf:2,rp:2,rs:2,re:2,a:6
[3/1]cac8lf:4,lp:1,ls:3,rf:1,rp:1,a:9
[3/2]cbc8lf:4,lp:2,ls:2,rf:5,rp:5,rs:1,re:1,a:3
[3/3]bcc7lf:4,lp:3,rf:4,rs:1,lprs:1,a:12
[3/4]cab6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:10
[3/5]acc6lf:3,lp:1,ls:2,rf:1,rp:1,rs:1,re:1,a:11
[3/6]cca4lf:4,rf:2,rs:2,a:12
[4/0]bcca5lf:3,lp:2,rf:2,rs:2,lprs:10,a:12
[4/1]ccab4lf:2,ls:2,a:22
[4/2]ccac4lf:2,ls:2,a:12
[4/3]accc2lf:1,lp:1,a:13
[4/4]bccc2lf:1,lp:1,rf:1,rs:1,lprs:1,a:28
[4/5]cbcc2lf:1,lp:1,rf:4,rp:4,rs:1,re:1,a:12
[4/6]cccb2lf:1,ls:1,rf:1,a:13
[5/0]cccab2lf:1,ls:1,a:28
[5/1]bccac2lf:1,ls:1,a:12
[5/2]bccca2lf:1,lp:1,a:28
[5/3]cbcca2lf:1,lp:1,rf:2,rp:2,rs:2,re:2,a:12
[5/4]cccbb0rf:1,rs:1,a:24
[5/5]cbccc0rf:1,rp:1,rs:1,re:1,a:28
[5/6]ccccb0rf:1,rp:1,a:24

Considering [length 3 / frequency 0] bca=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababba=1⟩.