Morphocompletion for #708 ⟨a, b | abaabbaba=1⟩

Solved by morph:3/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabb ⇒ baba
2. baabaab ⇒ abbabaa
3. abbabaab ⇒ bbabaaba
4. bbabaabaa ⇒ 1
5. bbabaaaab ⇒ abbbaabaa
6. bbabaabab ⇒ abbabbaba
7. babaaabaab ⇒ aababbabaa
8. babaabaaaab ⇒ abababaabaa
9. babababaabaa ⇒ aab
10. bbabaabababa ⇒ abb
11. babaabababaabaa ⇒ aabaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa
Length 4:[4/0] baba, [4/1] abaa, [4/2] baab, [4/3] bbab
Length 5:[5/0] abaab, [5/1] babaa, [5/2] bbaba, [5/3] baaba
Length 6:[6/0] babaab, [6/1] bbabaa, [6/2] baabaa, [6/3] abaaba

Considering [length 3 / frequency 0] aba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bccc ⇒ a
2. cbacc ⇒ aa
3. ccab ⇒ bcca
4. abc ⇒ cba
5. cbbcc ⇒ ab
6. bccaa ⇒ ccc
7. aba ⇒ c
8. bccab ⇒ 1
9. ccabb ⇒ 1
10. abbc ⇒ cabb
11. cbacab ⇒ a
12. aabb ⇒ bc
13. acabb ⇒ bcc
14. baabb ⇒ bbc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] cc, [2/2] bc, [2/3] bb, [2/4] ba, [2/5] cb, [2/6] ca
Length 3:[3/0] abb, [3/1] cab, [3/2] bcc, [3/3] cca, [3/4] cba, [3/5] aab, [3/6] bbc
Length 4:[4/0] cabb, [4/1] acab, [4/2] ccab, [4/3] cbac, [4/4] bcca, [4/5] aabb, [4/6] baab
Length 5:[5/0] bacab, [5/1] cbaca

Considering [length 4 / frequency 0] cabb=d.

Step 3

Rewriting system is complete. See a, b | abaabbaba=1⟩.