Morphocompletion for #698 ⟨a, b | abaaaabba=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ bbaaba
2. baaaab ⇒ aabbaa
3. aaaabb ⇒ baabaa
4. bbaababaab ⇒ abbbbaabaa
5. bbaabaaaa ⇒ 1
6. bbaaaaaab ⇒ aabbbaaaa
7. bbaabaabaab ⇒ aabbbbaabaa
8. bbaabaaabaab ⇒ aaabbbbaabaa
9. aaaabbbbaabaa ⇒ baab
10. baabaaaaaab ⇒ aaaabaabbaa
11. abbbaaaaaaaab ⇒ aaabbbbaaaaaa
12. baabaabaabaaaa ⇒ aaaab
13. baabaaaaaaaab ⇒ aabaabaabaaaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] aba
Length 4:[4/0] aaaa, [4/1] baab, [4/2] aaab, [4/3] abaa
Length 5:[5/0] aaaab, [5/1] baaba, [5/2] aaaaa, [5/3] aabaa
Length 6:[6/0] baabaa, [6/1] bbaaba, [6/2] aaaaaa, [6/3] aaaaab

Considering [length 4 / frequency 0] aaaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bcbcb ⇒ cbbbc
2. cbbbcb ⇒ bbcbbc
3. bcbbbcb ⇒ bbbcbbc
4. cbcbb ⇒ bcbbc
5. cbbbcbb ⇒ bbcbbcb
6. bbbcbbcbc ⇒ 1
7. bcbbcbcb ⇒ bbcbbcbc
8. cbbbcbbcb ⇒ 1
9. ac ⇒ ca
10. abcbb ⇒ bcbba
11. abbcbbc ⇒ cabbbcb
12. cabbbcbbcb ⇒ a
13. aa ⇒ bcbbc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cb, [2/1] bc, [2/2] bb, [2/3] ab, [2/4] ca, [2/5] ba
Length 3:[3/0] bcb, [3/1] cbb, [3/2] bbc, [3/3] bbb, [3/4] cbc, [3/5] abb, [3/6] abc
Length 4:[4/0] bbcb, [4/1] bcbb, [4/2] cbbb, [4/3] bbbc, [4/4] cbcb, [4/5] cbbc, [4/6] bcbc
Length 5:[5/0] bbbcb, [5/1] cbbbc, [5/2] bcbbc, [5/3] cbbcb, [5/4] bbcbb, [5/5] bbcbc, [5/6] abbcb

Considering [length 3 / frequency 0] bcb=d.

Step 3

Rewriting system is complete. See a, b | abaaaabba=1⟩.