Morphocompletion for #683 ⟨a, b | aabbabbaa=1⟩

Solved by morph:3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbabba ⇒ abbabb
2. aaaabbabb ⇒ 1
3. bbaabbabb ⇒ abbabbbba
4. bbabbbbaa ⇒ aabbbbabb
5. bbaaabbabb ⇒ aaabbbbabb
6. aaaaaabbbbabb ⇒ bbaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bba, [3/1] abb, [3/2] aaa, [3/3] bab
Length 4:[4/0] babb, [4/1] bbab, [4/2] bbaa, [4/3] aaaa
Length 5:[5/0] bbabb, [5/1] abbab, [5/2] aabba, [5/3] aaabb
Length 6:[6/0] abbabb, [6/1] aabbab, [6/2] aaaabb, [6/3] bbbbaa

Considering [length 3 / frequency 0] bba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cca ⇒ acc
2. ccba ⇒ acbc
3. bb ⇒ caacc
4. aaacc ⇒ 1
5. caaa ⇒ aaac
6. bcaacc ⇒ caaccb
7. aaacacc ⇒ ca
8. caaacbc ⇒ bc
9. caaba ⇒ aaabc
10. aaacaacc ⇒ caa
11. aaacacacc ⇒ caca
12. aaaacbc ⇒ ba
13. aaacacbc ⇒ cba
14. aaacaacbc ⇒ caba
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ac, [2/3] cc, [2/4] bc, [2/5] cb, [2/6] ba
Length 3:[3/0] aaa, [3/1] aac, [3/2] acc, [3/3] caa, [3/4] cbc, [3/5] aca, [3/6] acb
Length 4:[4/0] aaac, [4/1] acbc, [4/2] aacc, [4/3] aaca, [4/4] acac, [4/5] cacc, [4/6] aacb
Length 5:[5/0] aaaca, [5/1] aacbc, [5/2] caacc, [5/3] acacc, [5/4] aacac, [5/5] aaacb, [5/6] aacaa

Considering [length 3 / frequency 0] aaa=d.

Step 3

Rewriting system is complete. See a, b | aabbabbaa=1⟩.