| Back: | ⟨a, b | aaabbabba=1⟩ |
|---|
Solved by morph:2/0,4/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | bbaaa ⇒ aaabb |
| 2. | aaaabbabb ⇒ 1 |
| 3. | bbabba ⇒ abbabb |
| 4. | aaaabbabaaabb ⇒ baaa |
| 5. | aaabbaabbabb ⇒ bba |
| 6. | aaabbaaabbabb ⇒ bbaa |
| 7. | abbabbbba ⇒ bbaabbabb |
| 8. | abbabbbbbba ⇒ bbbbaabbabb |
| 9. | abbabbbbbbbba ⇒ bbbbbbaabbabb |
| 10. | abbabbbbbbbbbba ⇒ bbbbbbbbaabbabb |
| 11. | abbabbbbbbbbbbbba ⇒ bbbbbbbbbbaabbabb |
| 12. | abbabbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbaabbabb |
| 13. | abbabbbbbbbbbbbbbbbba ⇒ bbbbbbbbbbbbbbaabbabb |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] abb, [3/2] bba, [3/3] aaa |
| Length 4: | [4/0] bbbb, [4/1] abba, [4/2] bbba, [4/3] babb |
| Length 5: | [5/0] bbbbb, [5/1] abbab, [5/2] bbabb, [5/3] bbbba |
| Length 6: | [6/0] bbbbbb, [6/1] abbabb, [6/2] bbbbba, [6/3] bbabbb |
Considering [length 2 / frequency 0] bb=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | caaa ⇒ aaac |
| 2. | aaaacac ⇒ 1 |
| 3. | caca ⇒ acac |
| 4. | cb ⇒ bc |
| 5. | aaaacab ⇒ baaaaca |
| 6. | bb ⇒ c |
| 7. | aaacaacac ⇒ ca |
| 8. | aaacaaacac ⇒ caa |
| 9. | acacca ⇒ caacac |
| 10. | caccaa ⇒ aaccac |
| 11. | aaaacabc ⇒ b |
| 12. | aaaacabaaac ⇒ baaa |
| 13. | aaaccaacac ⇒ cca |
| 14. | acaccca ⇒ ccaacac |
| 15. | aaacaacabc ⇒ cab |
| 16. | acacccca ⇒ cccaacac |
| 17. | acaccccca ⇒ ccccaacac |
| 18. | acacccccca ⇒ cccccaacac |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] aa, [2/1] ac, [2/2] ca, [2/3] cc, [2/4] ab, [2/5] bc, [2/6] ba |
|---|---|
| Length 3: | [3/0] aaa, [3/1] aca, [3/2] cac, [3/3] aac, [3/4] cca, [3/5] ccc, [3/6] caa |
| Length 4: | [4/0] acac, [4/1] aaac, [4/2] aaca, [4/3] ccca, [4/4] aaaa, [4/5] cacc, [4/6] cccc |
| Length 5: | [5/0] aaaca, [5/1] acacc, [5/2] aacac, [5/3] aaaac, [5/4] cccca, [5/5] aacab, [5/6] caccc |
Considering [length 4 / frequency 0] acac=d.
Rewriting system is complete. See ⟨a, b | aaabbabba=1⟩.