Morphocompletion for #631 ⟨a, b | aaabaabba=1⟩

Solved by morph:3/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaa ⇒ baaaab
2. aabaab ⇒ bbaaaa
3. bbaaaabaa ⇒ 1
4. baabbaa ⇒ bbaaaab
5. abbaaaab ⇒ bbaaaaba
6. abaabb ⇒ baabba
7. aabbbaaaa ⇒ bbaaaaaab
8. bbaaaaaabbaa ⇒ aab
9. baaaabbbaa ⇒ bbaaaaaabb
10. aabbbbaaaa ⇒ baabaaaabb
11. bbaaaababbaaaa ⇒ abaab
12. bbaaaababaaaab ⇒ abbaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] baa, [3/1] aaa, [3/2] aab, [3/3] bba
Length 4:[4/0] bbaa, [4/1] aaaa, [4/2] aabb, [4/3] baaa
Length 5:[5/0] baaaa, [5/1] bbaaa, [5/2] abbaa, [5/3] aaaab
Length 6:[6/0] bbaaaa, [6/1] baaaab, [6/2] aabbaa, [6/3] aabbba

Considering [length 3 / frequency 0] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caaccc ⇒ aac
2. baa ⇒ c
3. bcaac ⇒ 1
4. cbcaa ⇒ 1
5. ccbc ⇒ b
6. acbc ⇒ cbca
7. aacb ⇒ bcaa
8. caab ⇒ aabc
9. caaccb ⇒ aab
10. bbcaa ⇒ ccb
11. bcaab ⇒ cbc
12. cbccaab ⇒ bc
13. ccbb ⇒ bcbc
14. acbb ⇒ cbba
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] cb, [2/2] bc, [2/3] ca, [2/4] ac, [2/5] cc, [2/6] bb
Length 3:[3/0] caa, [3/1] cbc, [3/2] aab, [3/3] acb, [3/4] ccb, [3/5] bca, [3/6] aac
Length 4:[4/0] bcaa, [4/1] caac, [4/2] caab, [4/3] bbca, [4/4] accb, [4/5] cbca, [4/6] cbcc
Length 5:[5/0] caacc, [5/1] ccaab, [5/2] aaccb, [5/3] cbcca, [5/4] aaccc, [5/5] bccaa

Considering [length 4 / frequency 0] bcaa=d.

Step 3

Rewriting system is complete. See a, b | aaabaabba=1⟩.