Morphocompletion for #5922 ⟨a, b | abbaab=baaba

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abbaab ⇒ baaba
2. baababaab ⇒ abbabaaba
3. baabaabaab ⇒ ababbabaaba
4. baabaaabaab ⇒ abababbabaaba
5. ababbabaabaaab ⇒ baaababbabaaba
6. baabaaaabaab ⇒ ababababbabaaba
7. baabaaababaab ⇒ abbaaabbabaaba
8. baabaaaaabaab ⇒ abababababbabaaba
9. baabaaaababaab ⇒ ababbaaabbabaaba
10. baabaabbabaabaaab ⇒ abbabaaababbabaaba
11. baabaaaaaabaab ⇒ ababababababbabaaba
12. baabaaabaaabaab ⇒ abbaaabababbabaaba
13. baabaaaaababaab ⇒ abababbaaabbabaaba
14. baabaaabbabaabaaab ⇒ ababbabaaababbabaaba
15. baabaaaaaaabaab ⇒ abababababababbabaaba
16. baabaaabaaaabaab ⇒ abbaaababababbabaaba
17. baabaaaabaaabaab ⇒ ababbaaabababbabaaba
18. baabaaaaaababaab ⇒ ababababbaaabbabaaba
19. baabaaabaaababaab ⇒ abbaaabbaaabbabaaba
20. baabaaaaaaaabaab ⇒ ababababababababbabaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] baab, [4/1] abaa, [4/2] aaba, [4/3] aaab, [4/4] aaaa, [4/5] baaa, [4/6] baba
Length 5:[5/0] baaba, [5/1] abaab, [5/2] aabaa, [5/3] abaaa, [5/4] aaaba, [5/5] baaab, [5/6] aaaaa
Length 6:[6/0] baabaa, [6/1] aabaaa, [6/2] aabaab, [6/3] abaaab, [6/4] babaab, [6/5] aaabaa, [6/6] aaaaba
Length 7:[7/0] baabaaa, [7/1] aaabaab, [7/2] aabaaab, [7/3] ababaab, [7/4] aabaaaa, [7/5] abaaaba, [7/6] aaaabaa

Considering [length 6 / frequency 0] baabaa=c.

Step 2

Rewriting system is complete. See a, b | abbaab=baaba.