Morphocompletion for #5916 ⟨a, b | abbaab=abaaa⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. abbaab ⇒ abaaa
2. abaaabaab ⇒ abaaaaaa
3. abaaaaaabaab ⇒ abaaaaaaaaa
4. abaaaaaaaaabaab ⇒ abaaaaaaaaaaaa
5. abaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaa
6. abaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaa
7. abaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaa
8. abaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaa
9. abaaaaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaaaaa
10. abaaaaaaaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
11. abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
12. abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
13. abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabaab ⇒ abaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa235lf:235,rf:260,rs:13
[2/1]ab64lf:38,lp:13,ls:13,rf:13,rp:13,lprp:13,lsrp:13
[2/2]ba25lf:25,rf:13
[2/3]bb1lf:1
[3/0]aaa210lf:210,rf:247,rs:13
[3/1]aab38lf:25,ls:13
[3/2]aba36lf:24,lp:12,rf:13,rp:13,lprp:12
[3/3]baa25lf:25,rf:13
[3/4]abb2lf:1,lp:1
[3/5]bba1lf:1
[4/0]aaaa198lf:198,rf:234,rs:12,a:1
[4/1]abaa36lf:24,lp:12,rf:13,rp:13,lprp:12
[4/2]baab26lf:13,ls:13
[4/3]aaab12lf:12,a:1
[4/4]aaba12lf:12,a:1
[4/5]baaa12lf:12,rf:13,rs:1
[4/6]abba2lf:1,lp:1
[5/0]aaaaa187lf:187,rf:222,rs:12,a:1
[5/1]abaaa24lf:12,lp:12,rf:13,rp:13,rs:1,re:1,lprp:12
[5/2]abaab24lf:12,ls:12,a:1
[5/3]aaaba12lf:12,a:1
[5/4]aabaa12lf:12,a:1
[5/5]aaaab11lf:11,a:2
[5/6]baaaa11lf:11,rf:12,a:1
[6/0]aaaaaa176lf:176,rf:210,rs:12,a:1
[6/1]aabaab24lf:12,ls:12,a:1
[6/2]abaaaa22lf:11,lp:11,rf:12,rp:12,lprp:11,a:1
[6/3]aaabaa12lf:12,a:1
[6/4]aaaaab11lf:11,a:2
[6/5]aaaaba11lf:11,a:2
[6/6]baaaaa11lf:11,rf:12,a:1
[7/0]aaaaaaa165lf:165,rf:198,rs:11,a:2
[7/1]aaabaab24lf:12,ls:12,a:1
[7/2]abaaaaa22lf:11,lp:11,rf:12,rp:12,lprp:11,a:1
[7/3]aaaaaab11lf:11,a:2
[7/4]aaaaaba11lf:11,a:2
[7/5]aaaabaa11lf:11,a:2
[7/6]baaaaaa11lf:11,rf:12,rs:1,a:1

Considering [length 2 / frequency 1] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbaab=abaaa⟩.