| Back: | ⟨a, b | ababba=babab⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: workTotalLimit
| # | Rule |
|---|---|
| 1. | ababba ⇒ babab |
| 2. | bbababbba ⇒ ababbbabab |
| 3. | bbababbbba ⇒ abaababbbabab |
| 4. | bbababbbbba ⇒ abaabaababbbabab |
| 5. | bbababbbbbba ⇒ abaabaabaababbbabab |
| 6. | bbababbbbbbba ⇒ abaabaabaabaababbbabab |
| 7. | bbababbbbbbbba ⇒ abaabaabaabaabaababbbabab |
| 8. | bbababbbbbbbbba ⇒ abaabaabaabaabaabaababbbabab |
| 9. | bbababbbbbbbbbba ⇒ abaabaabaabaabaabaabaababbbabab |
| 10. | bbababbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaababbbabab |
| 11. | bbababbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaababbbabab |
| 12. | bbababbbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaabaababbbabab |
| 13. | bbababbbbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaabaabaababbbabab |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] bba, [3/2] bab, [3/3] aba, [3/4] abb, [3/5] baa, [3/6] aab |
| Length 4: | [4/0] bbbb, [4/1] bbba, [4/2] bbab, [4/3] abab, [4/4] babb, [4/5] abbb, [4/6] baba |
| Length 5: | [5/0] bbbbb, [5/1] bbaba, [5/2] bbbba, [5/3] ababb, [5/4] babbb, [5/5] babab, [5/6] abbbb |
| Length 6: | [6/0] bbbbbb, [6/1] bbabab, [6/2] bbbbba, [6/3] bababb, [6/4] ababbb, [6/5] babbbb, [6/6] abbbbb |
| Length 7: | [7/0] bbbbbbb, [7/1] bbababb, [7/2] bbbbbba, [7/3] bababbb, [7/4] ababbbb, [7/5] babbbbb, [7/6] abbbbbb |
Considering [length 5 / frequency 1] bbaba=c.
Rewriting system is complete. See ⟨a, b | ababba=babab⟩.