Morphocompletion for #5898 ⟨a, b | ababba=babab

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: workTotalLimit

#Rule
1. ababba ⇒ babab
2. bbababbba ⇒ ababbbabab
3. bbababbbba ⇒ abaababbbabab
4. bbababbbbba ⇒ abaabaababbbabab
5. bbababbbbbba ⇒ abaabaabaababbbabab
6. bbababbbbbbba ⇒ abaabaabaabaababbbabab
7. bbababbbbbbbba ⇒ abaabaabaabaabaababbbabab
8. bbababbbbbbbbba ⇒ abaabaabaabaabaabaababbbabab
9. bbababbbbbbbbbba ⇒ abaabaabaabaabaabaabaababbbabab
10. bbababbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaababbbabab
11. bbababbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaababbbabab
12. bbababbbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaabaababbbabab
13. bbababbbbbbbbbbbbbba ⇒ abaabaabaabaabaabaabaabaabaabaabaababbbabab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] bbb, [3/1] bba, [3/2] bab, [3/3] aba, [3/4] abb, [3/5] baa, [3/6] aab
Length 4:[4/0] bbbb, [4/1] bbba, [4/2] bbab, [4/3] abab, [4/4] babb, [4/5] abbb, [4/6] baba
Length 5:[5/0] bbbbb, [5/1] bbaba, [5/2] bbbba, [5/3] ababb, [5/4] babbb, [5/5] babab, [5/6] abbbb
Length 6:[6/0] bbbbbb, [6/1] bbabab, [6/2] bbbbba, [6/3] bababb, [6/4] ababbb, [6/5] babbbb, [6/6] abbbbb
Length 7:[7/0] bbbbbbb, [7/1] bbababb, [7/2] bbbbbba, [7/3] bababbb, [7/4] ababbbb, [7/5] babbbbb, [7/6] abbbbbb

Considering [length 5 / frequency 1] bbaba=c.

Step 2

Rewriting system is complete. See a, b | ababba=babab.