Morphocompletion for #5874 ⟨a, b | ababab=baaba⟩

Solved by morph:2/0,5/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaba ⇒ baabaab
2. ababab ⇒ baaba
3. baabaabbab ⇒ abbabaaba
4. baabaababbab ⇒ ababbabaaba
5. abbabaabaabab ⇒ baabaabbbaaba
6. ababaabbabaaba ⇒ baabaaabaabbab
7. baabaabbbaabaab ⇒ abbabaababaaba
8. baabaababaabbab ⇒ abbaaabbabaaba
9. ababbaaabbabaaba ⇒ baababaabaaabbab
...

Collecting factors up to length 7 / frequency 3:

[2/0]ab47lf:36,lp:5,ls:6,rf:31,rp:4,rs:3,lsrp:4,lprs:3
[2/1]ba41lf:34,lp:4,ls:3,rf:33,rp:5,rs:6,lsrp:3,lprs:4
[2/2]aa19lf:19,rf:21
[3/0]aba27lf:21,lp:3,ls:3,rf:20,rp:1,rs:6,lprs:1
[3/1]baa22lf:18,lp:4,rf:18,rp:5
[3/2]aab19lf:18,ls:1,rf:18,rs:1
[4/0]baab22lf:17,lp:4,ls:1,rf:15,rp:5,rs:1
[4/1]aaba15lf:12,ls:3,rf:13,rs:6
[4/2]abab12lf:7,lp:3,ls:2,rf:3,rp:1
[5/0]baaba19lf:12,lp:4,ls:3,rf:12,rp:5,rs:6,re:1,lsrp:3,lprs:4
[5/1]abaab12lf:11,ls:1,rf:9,rs:1,a:1
[5/2]abbab10lf:6,lp:1,ls:3,rf:6,rp:2,rs:2,lsrp:1,a:2
[6/0]baabaa10lf:6,lp:4,rf:4,rp:3,a:1
[6/1]abaaba8lf:6,ls:2,rf:6,rs:4,a:2
[6/2]aabaab7lf:6,ls:1,rf:3,rs:1,a:1

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caaccc ⇒ acccca
2. caca ⇒ accc
3. accccaaca ⇒ caaccaccc
4. caaccacccca ⇒ accccaaaccc
5. baaccc ⇒ cccca
6. baca ⇒ ccc
7. baaccaccc ⇒ ccccaaca
8. baaccaccaccc ⇒ ccccaacaaca
9. baccaaccaccc ⇒ cccccccaaca
10. cccb ⇒ bacc
11. ab ⇒ c
12. caacbacc ⇒ accccacb
13. caaccbacc ⇒ accccaccb
14. baacbacc ⇒ ccccacb
15. baaccbacc ⇒ ccccaccb
16. baaccacbacc ⇒ ccccaacacb
17. ccccacbcb ⇒ baacbcacc
18. ccccaccbcb ⇒ baaccbcacc
19. caacbacbacc ⇒ accccacbccb
20. baacbacbacc ⇒ ccccacbccb
...

Collecting factors up to length 6 / frequency 5:

[2/0]cc56lf:41,lp:3,ls:12,rf:59,rp:9,rs:7,lsrp:8,lprs:3,a:2
[2/1]ac36lf:35,lp:1,rf:26,rp:6,a:2
[2/2]ca30lf:20,lp:6,ls:4,rf:22,rp:1,rs:5,lsrp:1,lprs:1,a:2
[2/3]ba27lf:18,lp:9,rf:3,rp:3,a:2
[2/4]cb17lf:14,ls:3,rf:11,rs:7,a:4
[3/0]acc32lf:24,lp:1,ls:7,rf:15,rp:6,rs:3,lsrp:3,a:3
[3/1]ccc22lf:14,lp:3,ls:5,rf:33,rp:9,rs:4,re:1,lsrp:4,a:2
[3/2]baa14lf:7,lp:7,rf:2,rp:2,a:5
[3/3]aac14lf:14,rf:9,a:5
[3/4]bac13lf:11,lp:2,rf:1,rp:1,a:2
[4/0]bacc16lf:8,lp:1,ls:7,rf:1,rp:1,rs:1,re:1,a:4
[4/1]baac14lf:7,lp:7,rf:2,rp:2,a:5
[4/2]accc13lf:7,lp:1,ls:5,rf:8,rp:6,rs:3,re:1,lsrp:1,lprs:1,a:3
[4/3]caac12lf:7,lp:5,rf:6,rp:1,a:6
[4/4]cbac9lf:9,a:8
[5/0]cbacc14lf:7,ls:7,a:8
[5/1]baacc10lf:5,lp:5,rf:1,rp:1,a:5
[5/2]acbac7lf:7,a:8
[5/3]caacc7lf:4,lp:3,rf:1,rp:1,a:6
[5/4]cccca7lf:4,lp:2,ls:1,rf:13,rp:7,rs:2,re:1,a:5

Considering [length 5 / frequency 1] baacc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cccad ⇒ dcacc
2. cdcad ⇒ ddccc
3. cdcacc ⇒ dcd
4. dcca ⇒ cccaccc
5. cccca ⇒ dc
6. caad ⇒ acccacc
7. caacc ⇒ ad
8. caacdc ⇒ adccca
9. caca ⇒ accc
10. caacad ⇒ adaacc
11. baad ⇒ cccacc
12. baacc ⇒ d
13. baacdc ⇒ dccca
14. baca ⇒ ccc
15. baacad ⇒ daacc
16. baacaccc ⇒ daca
17. dcb ⇒ ccccc
18. cccb ⇒ bacc
19. ab ⇒ c
20. baacbacc ⇒ dccb
...

Collecting factors up to length 6 / frequency 5:

[2/0]ca24lf:15,lp:5,ls:4,rf:7,rs:3,lprs:1,a:3
[2/1]cc22lf:14,lp:3,ls:5,rf:29,rp:4,rs:11,lprs:2,a:2
[2/2]ba15lf:8,lp:7,rf:1,rp:1,a:2
[2/3]ac13lf:13,rf:10,rp:2,a:2
[2/4]ad12lf:6,ls:6,rf:3,rp:3,rs:1,re:1,lsrp:1,a:4
[3/0]baa12lf:6,lp:6,a:2
[3/1]acc9lf:5,ls:4,rf:9,rp:2,rs:6,a:2
[3/2]ccc9lf:5,lp:3,ls:1,rf:12,rp:4,rs:5,re:1,a:3
[3/3]caa8lf:4,lp:4,a:4
[3/4]aac8lf:8,rf:2,a:2
[4/0]baac10lf:5,lp:5,a:2
[4/1]caac6lf:3,lp:3,a:4
[4/2]acad4lf:2,ls:2,a:5
[4/3]aacc4lf:2,ls:2,rf:2,rs:2,a:2
[4/4]cdca4lf:2,lp:2,a:19
[5/0]baaca4lf:2,lp:2,a:5
[5/1]aacad4lf:2,ls:2,a:5
[5/2]aacdc4lf:2,ls:2,a:15
[5/3]baacb2lf:1,lp:1,a:20
[5/4]cbacc2lf:1,ls:1,a:20

Considering [length 3 / frequency 0] baa=e.

Step 4

Rewriting system is complete. See ⟨a, b | ababab=baaba⟩.