Morphocompletion for #5865 ⟨a, b | ababab=aabaa⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababab ⇒ aabaa
2. aabaaab ⇒ abaabaa
3. aabaabaabaa ⇒ abaabaaaaab
4. aabaababaabaa ⇒ abaabaaaaabab
5. aababaabaaaaab ⇒ abaabaaaaabbaa
6. abaabaaaaabbabab ⇒ abaabaaaaababaa
7. abaabaaaaababaaab ⇒ abaabaaaaabbaabaa
8. abaabaaaaabbaaabab ⇒ aababaabaaaaaabaa
9. abaabaaaaababbabab ⇒ abaabaaaaaabaaaa
10. aababaabaaaabaabaa ⇒ abaabaaaaabbaaaaab
11. aabaababaababaabaa ⇒ abaabaaaaababbaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa63lf:53,lp:6,ls:4,rf:66,rp:2,rs:7,lprs:2
[2/1]ab60lf:48,lp:5,ls:7,rf:37,rp:9,rs:4,lprp:3,lsrp:5
[2/2]ba41lf:41,rf:33
[2/3]bb3lf:3,rf:4,a:3
[3/0]aba43lf:38,lp:5,rf:29,rp:9,lprp:3
[3/1]aab38lf:29,lp:6,ls:3,rf:24,rp:2,rs:3,lprs:3
[3/2]baa31lf:27,ls:4,rf:29,rs:6
[3/3]aaa20lf:20,rf:35,rs:1,a:1
[3/4]bab18lf:14,ls:4,rf:4,rs:1
[3/5]abb3lf:3,rf:4,a:3
[3/6]bba3lf:3,rf:4,a:3
[4/0]abaa34lf:26,lp:4,ls:4,rf:25,rp:9,rs:5,lprp:3,lsrp:4,lprs:3
[4/1]aaba30lf:24,lp:6,rf:18,rp:2
[4/2]abab17lf:12,lp:1,ls:4,rf:4,rs:1
[4/3]baab14lf:14,rf:11,a:1
[4/4]aaab12lf:9,ls:3,rf:11,rs:3,a:1
[4/5]aaaa11lf:11,rf:23,rs:1,a:2
[4/6]baaa9lf:9,rf:12,a:1
[5/0]aabaa24lf:16,lp:4,ls:4,rf:14,rp:1,rs:4,re:1,lprs:1
[5/1]abaab18lf:14,lp:4,rf:10,rp:9,lprp:3,a:1
[5/2]baaba14lf:14,rf:11,a:1
[5/3]aabab11lf:8,lp:2,ls:1,rf:4,rp:1,rs:1,lsrp:1,a:3
[5/4]abaaa8lf:8,rf:10,a:1
[5/5]ababa8lf:7,lp:1,rf:2
[5/6]aaaab7lf:6,ls:1,rf:10,rs:2,a:2
[6/0]abaaba18lf:14,lp:4,rf:10,rp:9,lprp:3,a:1
[6/1]baabaa15lf:11,ls:4,rf:11,rs:2,a:1
[6/2]aabaaa8lf:7,lp:1,rf:10,a:1
[6/3]aabaab8lf:5,lp:3,a:2
[6/4]aababa8lf:6,lp:2,rf:2,rp:1,a:3
[6/5]aaaaab6lf:5,ls:1,rf:10,rs:2,a:2
[6/6]abaaaa6lf:6,rf:10,rs:1,a:2
[7/0]abaabaa19lf:11,lp:4,ls:4,rf:10,rp:9,rs:1,re:1,lprp:3,lsrp:4,a:1
[7/1]aabaaba8lf:5,lp:3,a:2
[7/2]aababaa8lf:6,lp:2,rf:2,rp:1,rs:1,a:3
[7/3]aabaaaa6lf:6,rf:10,rs:1,a:2
[7/4]baaaaab6lf:5,ls:1,rf:8,rs:2,a:2
[7/5]baabaaa6lf:6,rf:9,a:2
[7/6]abaaaaa5lf:5,rf:9,a:2

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababab=aabaa⟩.