Morphocompletion for #5865 ⟨a, b | ababab=aabaa⟩

Back:⟨a, b | ababab=aabaa⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababab ⇒ aabaa
2. aabaaab ⇒ abaabaa
3. aabaabaabaa ⇒ abaabaaaaab
4. aabaababaabaa ⇒ abaabaaaaabab
5. aababaabaaaaab ⇒ abaabaaaaabbaa
6. abaabaaaaabbabab ⇒ abaabaaaaababaa
7. abaabaaaaababaaab ⇒ abaabaaaaabbaabaa
8. abaabaaaaabbaaabab ⇒ aababaabaaaaaabaa
9. abaabaaaaababbabab ⇒ abaabaaaaaabaaaa
10. aababaabaaaabaabaa ⇒ abaabaaaaabbaaaaab
11. aabaababaababaabaa ⇒ abaabaaaaababbaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] baa, [3/3] aaa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] abaa, [4/1] aaba, [4/2] abab, [4/3] baab, [4/4] aaab, [4/5] aaaa, [4/6] baaa
Length 5:[5/0] aabaa, [5/1] abaab, [5/2] baaba, [5/3] aabab, [5/4] abaaa, [5/5] ababa, [5/6] aaaab
Length 6:[6/0] abaaba, [6/1] baabaa, [6/2] aabaaa, [6/3] aabaab, [6/4] aababa, [6/5] aaaaab, [6/6] abaaaa
Length 7:[7/0] abaabaa, [7/1] aabaaba, [7/2] aababaa, [7/3] aabaaaa, [7/4] baaaaab, [7/5] baabaaa, [7/6] abaaaaa

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | ababab=aabaa⟩.