Morphocompletion for #5857 ⟨a, b | abaaba=babab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaba ⇒ babab
2. babababa ⇒ abababab
3. baabababab ⇒ ababababba
4. bababbaaba ⇒ abaabbabab
5. bababbababba ⇒ abbababbabab
6. aababababba ⇒ bababbabab
7. ababababbaba ⇒ bbababbabab
8. ababababbbaba ⇒ bbbababbabab
9. ababababbbbaba ⇒ bbbbababbabab
10. baaabababab ⇒ ababababbaa
11. baaaabababab ⇒ ababababbaaa
12. baaaaabababab ⇒ ababababbaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] baa, [3/3] bba, [3/4] aab, [3/5] abb, [3/6] aaa
Length 4:[4/0] abab, [4/1] baba, [4/2] aaba, [4/3] abba, [4/4] babb, [4/5] baaa, [4/6] baab
Length 5:[5/0] babab, [5/1] ababa, [5/2] bbaba, [5/3] babba, [5/4] ababb, [5/5] baaba, [5/6] aabab
Length 6:[6/0] ababab, [6/1] bababa, [6/2] bababb, [6/3] ababba, [6/4] aababa, [6/5] bbbaba, [6/6] aaabab
Length 7:[7/0] bababab, [7/1] abababa, [7/2] bababba, [7/3] aababab, [7/4] abababb, [7/5] aaababa, [7/6] babbaba

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | abaaba=babab.