| Back: | ⟨a, b | abaaba=babab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaba ⇒ babab |
| 2. | babababa ⇒ abababab |
| 3. | baabababab ⇒ ababababba |
| 4. | bababbaaba ⇒ abaabbabab |
| 5. | bababbababba ⇒ abbababbabab |
| 6. | aababababba ⇒ bababbabab |
| 7. | ababababbaba ⇒ bbababbabab |
| 8. | ababababbbaba ⇒ bbbababbabab |
| 9. | ababababbbbaba ⇒ bbbbababbabab |
| 10. | baaabababab ⇒ ababababbaa |
| 11. | baaaabababab ⇒ ababababbaaa |
| 12. | baaaaabababab ⇒ ababababbaaaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 65 | lf:50,lp:7,ls:8,rf:44,rp:2,rs:1,lsrp:2,lprs:1 |
|---|---|---|---|
| [2/1] | ab | 55 | lf:47,lp:4,ls:4,rf:47,rp:7,rs:8,lsrp:4,lprs:4 |
| [2/2] | aa | 14 | lf:13,lp:1,rf:7,rs:3 |
| [2/3] | bb | 10 | lf:10,rf:17,rp:3,a:2 |
| [3/0] | aba | 46 | lf:36,lp:4,ls:6,rf:28,rp:6,lsrp:2 |
| [3/1] | bab | 43 | lf:36,lp:3,ls:4,rf:39,rp:2,rs:8,lprs:3 |
| [3/2] | baa | 10 | lf:6,lp:4,rf:4,rs:1,lprs:1 |
| [3/3] | bba | 9 | lf:7,ls:2,rf:14,rp:1,rs:1,a:2 |
| [3/4] | aab | 8 | lf:7,lp:1,rf:1 |
| [3/5] | abb | 7 | lf:7,rf:11,rp:1,a:2 |
| [3/6] | aaa | 6 | lf:6,rf:3,rs:2,a:6 |
| [4/0] | abab | 36 | lf:29,lp:3,ls:4,rf:27,rp:5,rs:8,lsrp:4,lprs:3 |
| [4/1] | baba | 32 | lf:25,lp:3,ls:4,rf:22,rp:2 |
| [4/2] | aaba | 10 | lf:7,lp:1,ls:2 |
| [4/3] | abba | 7 | lf:5,ls:2,rf:11,rp:1,rs:1,lsrp:1,a:2 |
| [4/4] | babb | 7 | lf:7,rf:9,a:2 |
| [4/5] | baaa | 6 | lf:3,lp:3,rf:2,rs:1,lprs:1,a:6 |
| [4/6] | baab | 4 | lf:3,lp:1,rf:1 |
| [5/0] | babab | 28 | lf:21,lp:3,ls:4,rf:22,rp:2,rs:8,re:1,lprs:3 |
| [5/1] | ababa | 22 | lf:18,lp:3,ls:1,rf:10,rp:5,lsrp:1,a:1 |
| [5/2] | bbaba | 7 | lf:4,ls:3,rf:10,rp:1,lsrp:1,a:2 |
| [5/3] | babba | 7 | lf:5,ls:2,rf:9,rs:1,a:2 |
| [5/4] | ababb | 7 | lf:7,rf:9,a:2 |
| [5/5] | baaba | 6 | lf:3,lp:1,ls:2 |
| [5/6] | aabab | 6 | lf:5,lp:1,a:4 |
| [6/0] | ababab | 24 | lf:17,lp:3,ls:4,rf:10,rp:5,rs:1,lsrp:4,a:1 |
| [6/1] | bababa | 12 | lf:10,lp:1,ls:1,rf:5,a:1 |
| [6/2] | bababb | 9 | lf:7,lp:2,rf:9,rp:1,a:2 |
| [6/3] | ababba | 7 | lf:5,ls:2,rf:9,rs:1,a:2 |
| [6/4] | aababa | 6 | lf:5,lp:1,a:4 |
| [6/5] | bbbaba | 4 | lf:2,ls:2,rf:2,rp:1,lsrp:1,a:17 |
| [6/6] | aaabab | 3 | lf:3,a:6 |
| [7/0] | bababab | 14 | lf:9,lp:1,ls:4,rf:5,rs:1,lprs:10,a:1 |
| [7/1] | abababa | 13 | lf:9,lp:3,ls:1,rf:5,rp:5,lsrp:10,a:1 |
| [7/2] | bababba | 9 | lf:5,lp:2,ls:2,rf:9,rp:1,rs:1,lsrp:1,a:2 |
| [7/3] | aababab | 6 | lf:5,lp:1,a:4 |
| [7/4] | abababb | 4 | lf:4,rf:4,a:4 |
| [7/5] | aaababa | 3 | lf:3,a:6 |
| [7/6] | babbaba | 3 | lf:2,ls:1,rf:5,a:4 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | abaaba=babab⟩.