| Back: | ⟨a, b | abaaba=abbab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaba ⇒ abbab |
| 2. | abaabbab ⇒ abbababa |
| 3. | abbabbaaba ⇒ abbabbbab |
| 4. | abbabbaabbab ⇒ abbabbbababa |
| 5. | abbababaaaba ⇒ abbabababab |
| 6. | abbabbbabbaaba ⇒ abbabbbabbbab |
| 7. | abbababaaabbab ⇒ abbabababababa |
| 8. | abbabbbababaaaba ⇒ abbabbbabababab |
| 9. | abbababababbaaba ⇒ abbababababbbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 48 | lf:36,lp:9,ls:3,rf:39,rp:9,rs:6,lprp:9,lsrp:3,lprs:6 |
|---|---|---|---|
| [2/1] | ba | 39 | lf:33,ls:6,rf:33,rs:3 |
| [2/2] | bb | 18 | lf:18,rf:21 |
| [2/3] | aa | 12 | lf:12 |
| [3/0] | aba | 25 | lf:17,lp:2,ls:6,rf:18,rs:3,lprs:1 |
| [3/1] | abb | 23 | lf:16,lp:7,rf:15,rp:9,lprp:7 |
| [3/2] | bab | 21 | lf:18,ls:3,rf:30,rs:6 |
| [3/3] | bba | 16 | lf:16,rf:15 |
| [3/4] | aab | 9 | lf:9 |
| [3/5] | baa | 9 | lf:9 |
| [3/6] | aaa | 3 | lf:3,a:4 |
| [4/0] | abba | 21 | lf:14,lp:7,rf:9,rp:9,lprp:7 |
| [4/1] | bbab | 15 | lf:12,ls:3,rf:15,rs:4 |
| [4/2] | aaba | 12 | lf:6,ls:6 |
| [4/3] | baba | 9 | lf:9,rf:18,rs:3,a:1 |
| [4/4] | abaa | 7 | lf:5,lp:2 |
| [4/5] | abab | 6 | lf:6,rf:15,rs:2,a:1 |
| [4/6] | baab | 6 | lf:6 |
| [5/0] | abbab | 20 | lf:10,lp:7,ls:3,rf:9,rp:9,rs:1,re:1,lprp:7,lsrp:3 |
| [5/1] | baaba | 8 | lf:4,ls:4 |
| [5/2] | babab | 6 | lf:6,rf:15,rs:2,a:1 |
| [5/3] | ababa | 5 | lf:5,rf:12,rs:3,a:1 |
| [5/4] | bbabb | 5 | lf:5,rf:5,a:2 |
| [5/5] | aaaba | 4 | lf:2,ls:2,a:4 |
| [5/6] | abaab | 4 | lf:2,lp:2 |
| [6/0] | abbabb | 8 | lf:4,lp:4,rf:4,rp:4,lprp:4,a:2 |
| [6/1] | aabbab | 6 | lf:3,ls:3,a:1 |
| [6/2] | abbaba | 6 | lf:3,lp:3,rf:4,rp:4,lprp:3,a:1 |
| [6/3] | bbaaba | 6 | lf:3,ls:3,a:2 |
| [6/4] | bababa | 5 | lf:5,rf:12,rs:3,a:1 |
| [6/5] | abbaab | 4 | lf:4,a:2 |
| [6/6] | baaaba | 4 | lf:2,ls:2,a:4 |
| [7/0] | abbaaba | 6 | lf:3,ls:3,a:2 |
| [7/1] | abbabab | 6 | lf:3,lp:3,rf:4,rp:4,lprp:3,a:1 |
| [7/2] | abaaaba | 4 | lf:2,ls:2,a:4 |
| [7/3] | abbabba | 4 | lf:2,lp:2,a:2 |
| [7/4] | abbabbb | 4 | lf:2,lp:2,rf:4,rp:4,lprp:2,a:2 |
| [7/5] | baabbab | 4 | lf:2,ls:2,a:1 |
| [7/6] | babbaab | 4 | lf:4,a:2 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | abaaba=abbab⟩.