Morphocompletion for #5852 ⟨a, b | abaaba=abbab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaaba ⇒ abbab
2. abaabbab ⇒ abbababa
3. abbabbaaba ⇒ abbabbbab
4. abbabbaabbab ⇒ abbabbbababa
5. abbababaaaba ⇒ abbabababab
6. abbabbbabbaaba ⇒ abbabbbabbbab
7. abbababaaabbab ⇒ abbabababababa
8. abbabbbababaaaba ⇒ abbabbbabababab
9. abbababababbaaba ⇒ abbababababbbab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] abb, [3/2] bab, [3/3] bba, [3/4] aab, [3/5] baa, [3/6] aaa
Length 4:[4/0] abba, [4/1] bbab, [4/2] aaba, [4/3] baba, [4/4] abaa, [4/5] abab, [4/6] baab
Length 5:[5/0] abbab, [5/1] baaba, [5/2] babab, [5/3] ababa, [5/4] bbabb, [5/5] aaaba, [5/6] abaab
Length 6:[6/0] abbabb, [6/1] aabbab, [6/2] abbaba, [6/3] bbaaba, [6/4] bababa, [6/5] abbaab, [6/6] baaaba
Length 7:[7/0] abbaaba, [7/1] abbabab, [7/2] abaaaba, [7/3] abbabba, [7/4] abbabbb, [7/5] baabbab, [7/6] babbaab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | abaaba=abbab.