Morphocompletion for #5827 ⟨a, b | abaaab=baaba

Solved by morph:3/2,2/2,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baaba ⇒ abaaab
2. abaaababa ⇒ baaabaaab
3. abaaaabaaabba ⇒ babaaabaaab
4. abaaabaaabaaabba ⇒ bababaaabaaab
5. abaaabbaaababa ⇒ baabbaaabaaab
6. abaaaabaaaabaaabaabba ⇒ babababaaabaaab
7. abaaabbaaaabaaabba ⇒ baabbabaaabaaab
8. abaaabaabbaaababa ⇒ babaabbaaabaaab
9. abaaabaaabaaaabaaabaabba ⇒ bababababaaabaaab
10. abaaabbaaabaaabaaabba ⇒ baabbababaaabaaab
11. abaaabaabbaaaabaaabba ⇒ babaabbabaaabaaab
12. abaaaabaaababbaaababa ⇒ bababaabbaaabaaab
13. abaaabbaaabbaaababa ⇒ baabbaabbaaabaaab
14. abaaabbaaaabaaaabaaabaabba ⇒ baabbabababaaabaaab
15. abaaabaabbaaabaaabaaabba ⇒ babaabbababaaabaaab
16. abaaaabaaababbaaaabaaabba ⇒ bababaabbabaaabaaab
17. abaaabbaaabbaaaabaaabba ⇒ baabbaabbabaaabaaab
18. abaaabaaabaaababbaaababa ⇒ babababaabbaaabaaab
19. abaaabbaaabaabbaaababa ⇒ baabbabaabbaaabaaab
20. abaaabaabbaaabbaaababa ⇒ babaabbaabbaaabaaab
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa
Length 4:[4/0] abaa, [4/1] baaa, [4/2] aaab
Length 5:[5/0] abaaa, [5/1] baaab, [5/2] aaaba
Length 6:[6/0] abaaab, [6/1] aaabaa, [6/2] baaaba

Considering [length 3 / frequency 2] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ c
2. cca ⇒ acac
3. cba ⇒ acab
4. acaba ⇒ cc
5. acaacab ⇒ bacc
6. acacacab ⇒ babacc
7. acabcaba ⇒ cbcc
8. acaacaacacb ⇒ bababacc
9. acabcaacab ⇒ cbbacc
10. acacbcaba ⇒ bacbcc
11. acacacaacacb ⇒ babababacc
12. acabcacacab ⇒ cbbabacc
13. acacbcaacab ⇒ bacbbacc
14. acaccbcaba ⇒ babacbcc
15. acabcabcaba ⇒ cbcbcc
16. acacbcacacab ⇒ bacbbabacc
17. acabcabcaacab ⇒ cbcbbacc
18. acacccbcaba ⇒ bababacbcc
19. acabcacbcaba ⇒ cbbacbcc
20. acacbcabcaba ⇒ bacbcbcc
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ac, [2/1] ca, [2/2] ab, [2/3] ba, [2/4] bc
Length 3:[3/0] aca, [3/1] cab, [3/2] cac, [3/3] bca, [3/4] aba
Length 4:[4/0] acab, [4/1] acac, [4/2] caba, [4/3] bcab, [4/4] cacb
Length 5:[5/0] bcaba, [5/1] acacb, [5/2] acabc, [5/3] cabca, [5/4] aacab

Considering [length 2 / frequency 2] ab=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. daa ⇒ ac
2. ab ⇒ d
3. baa ⇒ c
4. cca ⇒ acac
5. acda ⇒ cc
6. dada ⇒ aacd
7. bada ⇒ acd
8. cb ⇒ bad
9. acaacd ⇒ bacc
10. ccda ⇒ bacc
11. acdda ⇒ cacd
12. acdb ⇒ badd
13. acacacd ⇒ bdacc
14. acdcda ⇒ badcc
15. ccdda ⇒ bacacd
16. ccdb ⇒ bdadd
17. ccdcda ⇒ bdadcc
18. acdcdda ⇒ badcacd
19. acdcdb ⇒ badbadd
20. ccdcdb ⇒ bdadbadd
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] da, [2/1] cd, [2/2] ac, [2/3] cc, [2/4] db
Length 3:[3/0] acd, [3/1] ccd, [3/2] cdb, [3/3] cda, [3/4] dda
Length 4:[4/0] cdda, [4/1] acdc, [4/2] cdcd, [4/3] dcdb, [4/4] ccdc
Length 5:[5/0] acdcd, [5/1] cdcdb, [5/2] ccdcd, [5/3] cdcda, [5/4] dcdda

Considering [length 2 / frequency 0] da=e.

Step 4

Rewriting system is complete. See a, b | abaaab=baaba.