Morphocompletion for #5827 ⟨a, b | abaaab=baaba⟩

Solved by morph:3/2,2/2,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baaba ⇒ abaaab
2. abaaababa ⇒ baaabaaab
3. abaaaabaaabba ⇒ babaaabaaab
4. abaaabaaabaaabba ⇒ bababaaabaaab
5. abaaabbaaababa ⇒ baabbaaabaaab
6. abaaaabaaaabaaabaabba ⇒ babababaaabaaab
7. abaaabbaaaabaaabba ⇒ baabbabaaabaaab
8. abaaabaabbaaababa ⇒ babaabbaaabaaab
9. abaaabaaabaaaabaaabaabba ⇒ bababababaaabaaab
10. abaaabbaaabaaabaaabba ⇒ baabbababaaabaaab
11. abaaabaabbaaaabaaabba ⇒ babaabbabaaabaaab
12. abaaaabaaababbaaababa ⇒ bababaabbaaabaaab
13. abaaabbaaabbaaababa ⇒ baabbaabbaaabaaab
14. abaaabbaaaabaaaabaaabaabba ⇒ baabbabababaaabaaab
15. abaaabaabbaaabaaabaaabba ⇒ babaabbababaaabaaab
16. abaaaabaaababbaaaabaaabba ⇒ bababaabbabaaabaaab
17. abaaabbaaabbaaaabaaabba ⇒ baabbaabbabaaabaaab
18. abaaabaaabaaababbaaababa ⇒ babababaabbaaabaaab
19. abaaabbaaabaabbaaababa ⇒ baabbabaabbaaabaaab
20. abaaabaabbaaabbaaababa ⇒ babaabbaabbaaabaaab
...

Collecting factors up to length 7 / frequency 3:

[2/0]aa139lf:139,rf:96
[2/1]ba120lf:99,lp:1,ls:20,rf:90,rp:19,lsrp:19
[2/2]ab117lf:98,lp:19,rf:91,rp:1,rs:20,lprs:19
[3/0]aba97lf:69,lp:19,ls:9,rf:53,rp:1,lsrp:1
[3/1]aaa71lf:71,rf:39
[3/2]baa69lf:68,lp:1,rf:57,rp:8
[4/0]abaa68lf:49,lp:19,rf:39,rp:1
[4/1]baaa59lf:59,rf:39,rp:1
[4/2]aaab59lf:59,rf:39,rs:20
[5/0]abaaa60lf:41,lp:19,rf:31,rp:1
[5/1]baaab47lf:47,rf:39,rp:1,rs:20
[5/2]aaaba41lf:41,rf:19,a:1
[6/0]abaaab49lf:34,lp:15,rf:31,rp:1,rs:20,re:1,lprs:15
[6/1]aaabaa30lf:30,rf:19,a:1
[6/2]baaaba29lf:29,rf:19,rp:1,a:1

Considering [length 3 / frequency 2] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ c
2. cca ⇒ acac
3. cba ⇒ acab
4. acaba ⇒ cc
5. acaacab ⇒ bacc
6. acacacab ⇒ babacc
7. acabcaba ⇒ cbcc
8. acaacaacacb ⇒ bababacc
9. acabcaacab ⇒ cbbacc
10. acacbcaba ⇒ bacbcc
11. acacacaacacb ⇒ babababacc
12. acabcacacab ⇒ cbbabacc
13. acacbcaacab ⇒ bacbbacc
14. acaccbcaba ⇒ babacbcc
15. acabcabcaba ⇒ cbcbcc
16. acacbcacacab ⇒ bacbbabacc
17. acabcabcaacab ⇒ cbcbbacc
18. acacccbcaba ⇒ bababacbcc
19. acabcacbcaba ⇒ cbbacbcc
20. acacbcabcaba ⇒ bacbcbcc
...

Collecting factors up to length 6 / frequency 5:

[2/0]ac58lf:41,lp:17,rf:19,rp:2,rs:1,a:2
[2/1]ca50lf:49,ls:1,rf:2,a:2
[2/2]ab31lf:24,ls:7,rf:12,rs:1,a:2
[2/3]ba20lf:10,lp:1,ls:9,rf:27,rp:10,lsrp:4,a:1
[2/4]bc16lf:16,rf:10,a:5
[3/0]aca49lf:32,lp:17,rf:2,rp:2,a:2
[3/1]cab31lf:24,ls:7,rf:1,rs:1,a:2
[3/2]cac17lf:17,rf:1,rs:1,a:6
[3/3]bca16lf:16,a:5
[3/4]aba16lf:8,ls:8,rf:11,a:3
[4/0]acab28lf:14,lp:7,ls:7,rf:1,rp:1,rs:1,re:1,a:2
[4/1]acac22lf:14,lp:8,rf:1,rp:1,rs:1,re:1,a:6
[4/2]caba16lf:8,ls:8,a:3
[4/3]bcab10lf:10,a:5
[4/4]cacb9lf:7,ls:2,a:11
[5/0]bcaba14lf:7,ls:7,a:5
[5/1]acacb12lf:6,lp:4,ls:2,a:11
[5/2]acabc12lf:6,lp:6,a:5
[5/3]cabca9lf:9,a:5
[5/4]aacab8lf:4,ls:4,a:4

Considering [length 2 / frequency 2] ab=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. daa ⇒ ac
2. ab ⇒ d
3. baa ⇒ c
4. cca ⇒ acac
5. acda ⇒ cc
6. dada ⇒ aacd
7. bada ⇒ acd
8. cb ⇒ bad
9. acaacd ⇒ bacc
10. ccda ⇒ bacc
11. acdda ⇒ cacd
12. acdb ⇒ badd
13. acacacd ⇒ bdacc
14. acdcda ⇒ badcc
15. ccdda ⇒ bacacd
16. ccdb ⇒ bdadd
17. ccdcda ⇒ bdadcc
18. acdcdda ⇒ badcacd
19. acdcdb ⇒ badbadd
20. ccdcdb ⇒ bdadbadd
...

Collecting factors up to length 6 / frequency 5:

[2/0]da22lf:11,lp:2,ls:9,rf:4,a:3
[2/1]cd20lf:18,ls:2,rf:5,rs:5,a:3
[2/2]ac19lf:11,lp:8,rf:12,rp:3,rs:2,re:1,a:3
[2/3]cc12lf:6,lp:6,rf:6,rp:1,rs:6,re:1,lprs:2,a:8
[2/4]db8lf:4,ls:4,rf:2,a:7
[3/0]acd16lf:8,lp:6,ls:2,rf:5,rp:1,rs:5,re:1,lprs:2,a:3
[3/1]ccd10lf:5,lp:5,a:10
[3/2]cdb8lf:4,ls:4,a:7
[3/3]cda8lf:4,ls:4,a:8
[3/4]dda6lf:3,ls:3,a:9
[4/0]cdda6lf:3,ls:3,a:9
[4/1]acdc6lf:3,lp:3,a:11
[4/2]cdcd5lf:5,a:11
[4/3]dcdb4lf:2,ls:2,a:16
[4/4]ccdc4lf:2,lp:2,a:20
[5/0]acdcd6lf:3,lp:3,a:11
[5/1]cdcdb4lf:2,ls:2,a:16
[5/2]ccdcd4lf:2,lp:2,a:20
[5/3]cdcda4lf:2,ls:2,a:11
[5/4]dcdda2lf:1,ls:1,a:18

Considering [length 2 / frequency 0] da=e.

Step 4

Rewriting system is complete. See ⟨a, b | abaaab=baaba⟩.