Morphocompletion for #5815 ⟨a, b | abaaab=aabba

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabba ⇒ abaaab
2. abaaababba ⇒ abaabaaabaab
3. abaabaaabaababba ⇒ abaabaaababaaabaab
4. abaabaaababaaabaababba ⇒ abaabaaababaaababaaabaab
5. abaabaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaabaab
6. abaabaaababaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaababaaabaab
7. abaabaaababaaababaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaababaaababaaabaab
8. abaabaaababaaababaaababaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaababaaababaaababaaabaab
9. abaabaaababaaababaaababaaababaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaababaaababaaababaaababaaabaab
10. abaabaaababaaababaaababaaababaaababaaababaaababaaabaababba ⇒ abaabaaababaaababaaababaaababaaababaaababaaababaaababaaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] baa, [3/3] bab, [3/4] aaa, [3/5] bba, [3/6] abb
Length 4:[4/0] abaa, [4/1] aaba, [4/2] abab, [4/3] aaab, [4/4] baaa, [4/5] baba, [4/6] abba
Length 5:[5/0] abaaa, [5/1] aabab, [5/2] baaab, [5/3] aaaba, [5/4] ababa, [5/5] babaa, [5/6] abaab
Length 6:[6/0] abaaab, [6/1] baaaba, [6/2] aaabab, [6/3] aababa, [6/4] ababaa, [6/5] babaaa, [6/6] abaaba
Length 7:[7/0] abaaaba, [7/1] baaabab, [7/2] babaaab, [7/3] aaababa, [7/4] aababaa, [7/5] ababaaa, [7/6] aababba

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | abaaab=aabba.