Morphocompletion for #575 ⟨a, b | abba=abab

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: trailTotalLimit

#Rule
1. abab ⇒ abba
2. abbaab ⇒ abbaba
3. abbabaab ⇒ abbabbaa
4. abbabbaaab ⇒ abbabbabaa
5. abbabbabaaab ⇒ abbabbabbaaa
6. abbabbabbaaaab ⇒ abbabbabbabaaa
7. abbabbabbabaaaab ⇒ abbabbabbabbaaaa
8. abbabbabbabbaaaaab ⇒ abbabbabbabbabaaaa
9. abbabbabbabbabaaaaab ⇒ abbabbabbabbabbaaaaa
10. abbabbabbabbabbaaaaaab ⇒ abbabbabbabbabbabaaaaa
11. abbabbabbabbabbabaaaaaab ⇒ abbabbabbabbabbabbaaaaaa
12. abbabbabbabbabbabbaaaaaaab ⇒ abbabbabbabbabbabbabaaaaaa
13. abbabbabbabbabbabbabaaaaaaab ⇒ abbabbabbabbabbabbabbaaaaaaa
14. abbabbabbabbabbabbabbaaaaaaaab ⇒ abbabbabbabbabbabbabbabaaaaaaa
15. abbabbabbabbabbabbabbabaaaaaaaab ⇒ abbabbabbabbabbabbabbabbaaaaaaaa
16. abbabbabbabbabbabbabbabbaaaaaaaaab ⇒ abbabbabbabbabbabbabbabbabaaaaaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] abb, [3/1] bba, [3/2] bab, [3/3] aaa, [3/4] aab, [3/5] baa, [3/6] aba
Length 4:[4/0] abba, [4/1] bbab, [4/2] babb, [4/3] aaaa, [4/4] aaab, [4/5] baaa, [4/6] bbaa
Length 5:[5/0] abbab, [5/1] babba, [5/2] bbabb, [5/3] aaaaa, [5/4] aaaab, [5/5] baaaa, [5/6] abbaa
Length 6:[6/0] abbabb, [6/1] bbabba, [6/2] babbab, [6/3] aaaaab, [6/4] aaaaaa, [6/5] baaaaa, [6/6] abbaba
Length 7:[7/0] abbabba, [7/1] bbabbab, [7/2] babbabb, [7/3] aaaaaab, [7/4] aaaaaaa, [7/5] abbabaa, [7/6] baaaaaa

Considering [length 5 / frequency 0] abbab=c.

Step 2

Rewriting system is complete. See a, b | abba=abab.