| Back: | ⟨a, b | aababa=baaab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | aababa ⇒ baaab |
| 2. | aababbaaab ⇒ babaaabba |
| 3. | aababbabaaab ⇒ babaaabbaaba |
| 4. | babaaabbaabaaba ⇒ aababbababaaab |
| 5. | aaaababbababaaab ⇒ baaabaabbaabaaba |
| 6. | babaaabbaabbaaab ⇒ aababbababaaabba |
| 7. | aabaaababbababaaab ⇒ baaabbaaabbaabaaba |
| 8. | baaabaabbaabaabaaba ⇒ aaaababbabababaaab |
| 9. | aababbababaaabbaaba ⇒ babaaabbaabbabaaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 44 | lf:39,ls:5,rf:35,rs:4 |
|---|---|---|---|
| [2/1] | ba | 44 | lf:37,lp:3,ls:4,rf:37,rp:6,rs:5,lsrp:2,lprs:1 |
| [2/2] | aa | 42 | lf:36,lp:6,rf:34,rp:3 |
| [2/3] | bb | 10 | lf:10,rf:11,a:1 |
| [3/0] | aab | 34 | lf:24,lp:5,ls:5,rf:21,rp:2,rs:4,lsrp:1,lprs:2 |
| [3/1] | aba | 28 | lf:24,ls:4,rf:20,rs:3 |
| [3/2] | baa | 19 | lf:18,lp:1,rf:18,rp:3 |
| [3/3] | bab | 17 | lf:15,lp:2,rf:14,rp:3 |
| [3/4] | aaa | 13 | lf:12,lp:1,rf:13,rp:1 |
| [3/5] | abb | 10 | lf:10,rf:11,a:1 |
| [3/6] | bba | 10 | lf:10,rf:11,rs:2,a:1 |
| [4/0] | aaba | 22 | lf:14,lp:5,ls:3,rf:9,rp:2,rs:3,lsrp:1,lprs:2 |
| [4/1] | aaab | 16 | lf:11,ls:5,rf:12,rs:4 |
| [4/2] | baba | 13 | lf:10,lp:2,ls:1,rf:11,rp:3 |
| [4/3] | abaa | 11 | lf:11,rf:10,a:1 |
| [4/4] | baaa | 11 | lf:10,lp:1,rf:11,rp:3 |
| [4/5] | abba | 10 | lf:10,rf:11,rs:2,a:1 |
| [4/6] | abab | 9 | lf:9,rf:7 |
| [5/0] | baaab | 16 | lf:10,lp:1,ls:5,rf:11,rp:3,rs:4,re:1,lsrp:2,lprs:1 |
| [5/1] | aabab | 10 | lf:6,lp:4,rf:3,rp:2 |
| [5/2] | baaba | 9 | lf:6,ls:3,rf:5,rs:3,a:3 |
| [5/3] | babaa | 8 | lf:6,lp:2,rf:7,rp:3,a:1 |
| [5/4] | abaaa | 7 | lf:7,rf:7,a:1 |
| [5/5] | abbaa | 6 | lf:6,rf:5,a:1 |
| [5/6] | aabaa | 6 | lf:5,lp:1,rf:3,a:6 |
| [6/0] | abaaab | 10 | lf:7,ls:3,rf:7,rs:3,a:1 |
| [6/1] | aababb | 8 | lf:5,lp:3,rf:3,rp:2,a:1 |
| [6/2] | babaaa | 8 | lf:6,lp:2,rf:7,rp:3,a:1 |
| [6/3] | ababba | 5 | lf:5,rf:3,a:1 |
| [6/4] | abaaba | 5 | lf:3,ls:2,rf:2,rs:2,a:6 |
| [6/5] | aabbaa | 5 | lf:5,rf:5,a:3 |
| [6/6] | babbab | 4 | lf:4,rf:3,a:3 |
| [7/0] | babaaab | 11 | lf:6,lp:2,ls:3,rf:7,rp:3,rs:3,lsrp:1,lprs:1,a:1 |
| [7/1] | aababba | 8 | lf:5,lp:3,rf:3,rp:2,a:1 |
| [7/2] | aabaaba | 5 | lf:3,ls:2,rf:2,rs:2,a:6 |
| [7/3] | ababbab | 4 | lf:4,rf:3,a:3 |
| [7/4] | aabbaab | 4 | lf:4,rf:4,a:3 |
| [7/5] | abbaaab | 4 | lf:2,ls:2,rf:1,a:1 |
| [7/6] | babbaba | 4 | lf:4,rf:3,a:3 |
Considering [length 3 / frequency 0] aab=c.
Rewriting system is complete. See ⟨a, b | aababa=baaab⟩.