| Back: | ⟨a, b | aababa=abaab⟩ |
|---|
Solved by morph:6/3. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababa ⇒ abaab |
| 2. | abaabbaab ⇒ ababaabba |
| 3. | abaabbabaab ⇒ abababaabbaa |
| 4. | abaababbaab ⇒ ababaabbaba |
| 5. | ababaabbababa ⇒ ababaabbbaab |
| 6. | abaababbababa ⇒ abaababbbaab |
| 7. | ababaabbbababa ⇒ ababaabbbbaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 37 | lf:28,lp:6,ls:3,rf:25,rp:7,rs:4,lprp:6,lsrp:3,lprs:3 |
|---|---|---|---|
| [2/1] | ba | 29 | lf:25,ls:4,rf:21,rs:2 |
| [2/2] | aa | 11 | lf:10,lp:1,rf:11,rs:1 |
| [2/3] | bb | 7 | lf:7,rf:10,a:1 |
| [3/0] | aba | 29 | lf:19,lp:6,ls:4,rf:15,rp:7,rs:1,lprp:6,lsrp:4,lprs:1 |
| [3/1] | aab | 14 | lf:10,lp:1,ls:3,rf:10,rs:4,lprs:1 |
| [3/2] | bab | 12 | lf:12,rf:8 |
| [3/3] | baa | 9 | lf:9,rf:11,rs:1 |
| [3/4] | abb | 6 | lf:6,rf:6,a:1 |
| [3/5] | bba | 6 | lf:6,rf:6,rs:1,a:1 |
| [3/6] | bbb | 1 | lf:1,rf:4,a:6 |
| [4/0] | baba | 14 | lf:10,ls:4,rf:7,rs:1 |
| [4/1] | baab | 12 | lf:9,ls:3,rf:10,rs:4 |
| [4/2] | abaa | 11 | lf:7,lp:4,rf:7,rp:2,lprp:1 |
| [4/3] | abab | 10 | lf:8,lp:2,rf:7,rp:5,lprp:2 |
| [4/4] | abba | 5 | lf:5,rf:3,rs:1,a:1 |
| [4/5] | bbab | 4 | lf:4,rf:1,a:2 |
| [4/6] | aabb | 4 | lf:4,rf:5,a:1 |
| [5/0] | abaab | 12 | lf:7,lp:4,ls:1,rf:7,rp:2,rs:1,re:1,lprp:1 |
| [5/1] | ababa | 12 | lf:6,lp:2,ls:4,rf:6,rp:5,lprp:2,lsrp:2 |
| [5/2] | baabb | 4 | lf:4,rf:5,a:1 |
| [5/3] | bbaab | 4 | lf:2,ls:2,rf:3,rs:3,a:1 |
| [5/4] | bbaba | 4 | lf:4,rf:1,rs:1,a:2 |
| [5/5] | aabab | 4 | lf:3,lp:1,rf:1 |
| [5/6] | abbab | 3 | lf:3,rf:1,a:2 |
| [6/0] | abaabb | 6 | lf:4,lp:2,rf:5,a:1 |
| [6/1] | bababa | 6 | lf:3,ls:3,rf:1,a:4 |
| [6/2] | abbaab | 4 | lf:2,ls:2,a:1 |
| [6/3] | babaab | 4 | lf:3,ls:1,rf:5,a:1 |
| [6/4] | abaaba | 4 | lf:2,lp:2,rf:1,rp:1,lprp:1,a:2 |
| [6/5] | ababaa | 4 | lf:2,lp:2,rf:5,rp:4,lprp:2,a:1 |
| [6/6] | bbabab | 3 | lf:3,a:6 |
| [7/0] | bbababa | 6 | lf:3,ls:3,a:6 |
| [7/1] | abaabba | 5 | lf:3,lp:2,rf:3,rs:1,lprs:1,a:1 |
| [7/2] | abaabab | 4 | lf:2,lp:2,rf:1,rp:1,lprp:1,a:2 |
| [7/3] | ababaab | 4 | lf:2,lp:2,rf:5,rp:4,lprp:2,a:1 |
| [7/4] | abbabab | 2 | lf:2,a:6 |
| [7/5] | baababb | 2 | lf:2,rf:1,a:2 |
| [7/6] | baabbab | 2 | lf:2,rf:1,a:2 |
Considering [length 6 / frequency 3] babaab=c.
Rewriting system is complete. See ⟨a, b | aababa=abaab⟩.