Morphocompletion for #5686 ⟨a, b | aababa=abaab⟩

Back:⟨a, b | aababa=abaab⟩

Solved by morph:6/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababa ⇒ abaab
2. abaabbaab ⇒ ababaabba
3. abaabbabaab ⇒ abababaabbaa
4. abaababbaab ⇒ ababaabbaba
5. ababaabbababa ⇒ ababaabbbaab
6. abaababbababa ⇒ abaababbbaab
7. ababaabbbababa ⇒ ababaabbbbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] abb, [3/5] bba, [3/6] bbb
Length 4:[4/0] baba, [4/1] baab, [4/2] abaa, [4/3] abab, [4/4] abba, [4/5] bbab, [4/6] aabb
Length 5:[5/0] abaab, [5/1] ababa, [5/2] baabb, [5/3] bbaab, [5/4] bbaba, [5/5] aabab, [5/6] abbab
Length 6:[6/0] abaabb, [6/1] bababa, [6/2] abbaab, [6/3] babaab, [6/4] abaaba, [6/5] ababaa, [6/6] bbabab
Length 7:[7/0] bbababa, [7/1] abaabba, [7/2] abaabab, [7/3] ababaab, [7/4] abbabab, [7/5] baababb, [7/6] baabbab

Considering [length 6 / frequency 3] babaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababa=abaab⟩.