Morphocompletion for #568 ⟨a, b | abab=aaba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abab ⇒ aaba
2. abaaba ⇒ aabaab
3. abaaaba ⇒ aabaabb
4. abaaaaba ⇒ aabaabbb
5. aabaabbab ⇒ aaabaabba
6. abaaaaaba ⇒ aabaabbbb
7. aabaabbbab ⇒ aaabaabbaa
8. abaaaaaaba ⇒ aabaabbbbb
9. aabaabbaaba ⇒ aaabaabbaab
10. aabaabbbbab ⇒ aaabaabbaaa
11. abaaaaaaaba ⇒ aabaabbbbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] aaa, [3/3] baa, [3/4] bab, [3/5] bba, [3/6] abb
Length 4:[4/0] aaba, [4/1] abaa, [4/2] aaaa, [4/3] bbab, [4/4] baab, [4/5] baaa, [4/6] aaab
Length 5:[5/0] abaaa, [5/1] aaaba, [5/2] aabaa, [5/3] abaab, [5/4] aaaaa, [5/5] bbbab, [5/6] baabb
Length 6:[6/0] abaaaa, [6/1] aabaab, [6/2] aaaaba, [6/3] abaabb, [6/4] baaaaa, [6/5] aaaaab, [6/6] aaaaaa
Length 7:[7/0] aabaabb, [7/1] abaaaaa, [7/2] aaaaaba, [7/3] baabbab, [7/4] baaaaba, [7/5] baaaaaa, [7/6] abbbbab

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | abab=aaba.