Morphocompletion for #5664 ⟨a, b | aabaab=baabb⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabaab ⇒ baabb
2. baabbaab ⇒ aabbaabb
3. aaaabbaabb ⇒ baabbbaab
4. aabbaabbbaab ⇒ bbaabbbaabb
5. aabbaabbbbaab ⇒ bbbaabbbaabb
6. aabbaabbbbbaab ⇒ bbbbaabbbaabb
7. baabbbaabbbaab ⇒ aabbbaabbbaabb
8. aabbaabbbbbbaab ⇒ bbbbbaabbbaabb
9. baabbbaabbbbaab ⇒ aabbbbaabbbaabb
10. aaaabbbaabbbaabb ⇒ baabbbbaabbbaab
11. aabbaabbbbbbbaab ⇒ bbbbbbaabbbaabb
12. baabbbaabbbbbaab ⇒ aabbbbbaabbbaabb
13. aaaabbbbaabbbaabb ⇒ baabbbbaabbbbaab
14. aabbaabbbbbbbbaab ⇒ bbbbbbbaabbbaabb
15. baabbbaabbbbbbaab ⇒ aabbbbbbaabbbaabb
16. aaaabbbbbaabbbaabb ⇒ baabbbbaabbbbbaab
17. aabbaabbbbbbbbbaab ⇒ bbbbbbbbaabbbaabb
18. baabbbaabbbbbbbaab ⇒ aabbbbbbbaabbbaabb
19. aaaabbbbbbaabbbaabb ⇒ baabbbbaabbbbbbaab
20. aabbaabbbbbbbbbbaab ⇒ bbbbbbbbbaabbbaabb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb116lf:111,ls:5,rf:126,rp:8,rs:15
[2/1]aa81lf:67,lp:14,rf:48,rp:6
[2/2]ab72lf:57,ls:15,rf:48,rs:5
[2/3]ba49lf:43,lp:6,rf:42,rp:6
[3/0]aab81lf:57,lp:9,ls:15,rf:48,rp:6,rs:5,lsrp:6
[3/1]bbb70lf:70,rf:75,rp:7,a:2
[3/2]baa49lf:43,lp:6,rf:42,rp:6
[3/3]abb46lf:41,ls:5,rf:43,rs:15
[3/4]bba36lf:36,rf:36,rp:1,a:1
[3/5]aaa15lf:10,lp:5,a:2
[3/6]aba1lf:1
[4/0]baab64lf:43,lp:6,ls:15,rf:42,rp:6,rs:5,lsrp:1
[4/1]aabb54lf:41,lp:8,ls:5,rf:43,rp:6,rs:15,lprs:8
[4/2]bbbb44lf:44,rf:41,rp:6,a:4
[4/3]bbaa36lf:36,rf:36,rp:1,a:1
[4/4]bbba26lf:26,rf:34,rp:1,a:2
[4/5]abbb26lf:26,rf:27,a:2
[4/6]abba10lf:10,rf:1,a:1
[5/0]bbaab50lf:36,ls:14,rf:36,rp:1,rs:5,lsrp:1,a:1
[5/1]baabb39lf:28,lp:6,ls:5,rf:37,rp:6,rs:15,re:1,lsrp:5,lprs:6
[5/2]bbbbb30lf:30,rf:24,rp:5,a:6
[5/3]bbbaa26lf:26,rf:34,rp:1,a:2
[5/4]aabbb26lf:26,rf:27,rp:5,a:2
[5/5]aabba18lf:10,lp:8,rf:1,rp:1,a:1
[5/6]bbbba14lf:14,rf:17,rp:1,a:4
[6/0]bbbaab39lf:26,ls:13,rf:34,rp:1,rs:5,lsrp:1,a:2
[6/1]bbaabb27lf:22,ls:5,rf:31,rp:1,rs:14,a:1
[6/2]baabbb27lf:22,lp:5,rf:22,rp:5,a:2
[6/3]bbbbbb19lf:19,rf:14,rp:4,a:8
[6/4]aabbaa18lf:10,lp:8,rf:1,rp:1,a:1
[6/5]bbbbaa14lf:14,rf:17,rp:1,a:4
[6/6]aabbbb14lf:14,rf:11,rp:4,a:4
[7/0]bbbbaab25lf:14,ls:11,rf:17,rp:1,rs:3,lsrp:1,a:4
[7/1]aabbaab19lf:10,lp:8,ls:1,rf:1,rp:1,lsrp:10,a:1
[7/2]bbbaabb17lf:13,ls:4,rf:29,rp:1,rs:13,a:3
[7/3]bbaabbb17lf:17,rf:17,rp:1,a:3
[7/4]baabbba16lf:11,lp:5,rf:15,rp:1,a:2
[7/5]abbbaab14lf:12,ls:2,rf:16,rs:2,a:2
[7/6]aabbbaa12lf:12,rf:16,rp:1,a:2

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaab=baabb⟩.