Morphocompletion for #5657 ⟨a, b | aabaab=abbaa

Solved by morph:4/0,2/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbaa ⇒ aabaab
2. aabaabbbaa ⇒ aabaababaab
3. aabaaabaabbbbaa ⇒ aabaaabaabbabaab
4. aabaababaabbbaa ⇒ aabaababaababaab
5. aabaaabaababaabbbbaa ⇒ aabaaabaababaabbabaab
6. aabaababaaabaabbbbaa ⇒ aabaababaaabaabbabaab
...

Collecting factors up to length 7, frequency 3:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] baa, [3/1] aab, [3/2] aba
Length 4:[4/0] aaba, [4/1] bbaa, [4/2] abaa
Length 5:[5/0] aabaa, [5/1] bbbaa, [5/2] abaab
Length 6:[6/0] aabaab, [6/1] bbbbaa, [6/2] baabbb

Considering [length 4 / frequency 0] aaba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caba ⇒ aabc
2. aaba ⇒ c
3. cabba ⇒ abbc
4. abbcc ⇒ caabcba
5. cbbac ⇒ cabcba
6. abbac ⇒ aabcba
7. cbbca ⇒ aabccab
8. abbca ⇒ ccab
9. cbbaa ⇒ aabcab
10. abbaa ⇒ cab
11. aabcaabcba ⇒ cbbcc
12. aabcbbcc ⇒ cabcaabcba
13. cabbbac ⇒ aabcbcba
14. cabbbca ⇒ aabcbacab
15. cabbbaa ⇒ aabcbaab
16. abbcbbc ⇒ cccabbba
17. abbabbc ⇒ ccabbba
18. aabccabbba ⇒ cbbabbc
19. aabcccabbba ⇒ cbbcbbc
20. aabcbaabba ⇒ cabbbc
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] ab, [2/1] bb, [2/2] ba, [2/3] aa, [2/4] ca
Length 3:[3/0] abb, [3/1] bba, [3/2] aab, [3/3] cab, [3/4] bbc
Length 4:[4/0] aabc, [4/1] abba, [4/2] cabb, [4/3] abbc, [4/4] bbba
Length 5:[5/0] cabbb, [5/1] abbba, [5/2] aabcb, [5/3] aabcc, [5/4] bcbbc

Considering [length 2 / frequency 0] ab=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cda ⇒ adc
2. ada ⇒ c
3. cb ⇒ add
4. ab ⇒ d
5. cdba ⇒ dbc
6. dbcc ⇒ ccdda
7. dbac ⇒ cdda
8. dbca ⇒ ccd
9. dbaa ⇒ cd
10. dbcd ⇒ ccdb
11. dbad ⇒ cdb
12. cdbbc ⇒ cddadba
13. ccdbba ⇒ dbdbc
14. cdbbac ⇒ cddadda
15. cdbbaa ⇒ cddad
16. cdbbad ⇒ cddadb
17. ccdbbbc ⇒ ccdbdadba
18. cdbbdbc ⇒ cddacdbba
19. dbdbdbc ⇒ ccddadbba
20. ccdbbbaa ⇒ ccdbdad
...

Collecting factors up to length 6, frequency 5:

Length 2:[2/0] db, [2/1] cd, [2/2] ba, [2/3] bc, [2/4] bb
Length 3:[3/0] cdb, [3/1] dbc, [3/2] dbb, [3/3] dba, [3/4] bba
Length 4:[4/0] cdbb, [4/1] ccdb, [4/2] dbba, [4/3] bbaa, [4/4] bdbc
Length 5:[5/0] cdbba, [5/1] ccdbb, [5/2] bbbaa, [5/3] bbdbc, [5/4] dbbbc

Considering [length 2 / frequency 0] db=e.

Step 4

Rewriting system is complete. See a, b | aabaab=abbaa.