| Back: | ⟨a, b | aaabba=abaab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | aaabba ⇒ abaab |
| 2. | abaabaabba ⇒ abaabbaab |
| 3. | abaabbaabaabba ⇒ abaabbaabbaab |
| 4. | abaabbaababaabba ⇒ abaabbaababbaab |
| 5. | abaabbaabababaabba ⇒ abaabbaabababbaab |
| 6. | abaabbaabbaabaabba ⇒ abaabbaabbaabbaab |
| 7. | abaabbaababababaabba ⇒ abaabbaababababbaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 38 | lf:31,ls:7,rf:25 |
|---|---|---|---|
| [2/1] | ab | 37 | lf:31,lp:6,rf:32,rp:7,rs:7,lprp:6,lprs:6 |
| [2/2] | aa | 21 | lf:20,lp:1,rf:19 |
| [2/3] | bb | 13 | lf:13,rf:12 |
| [3/0] | aba | 24 | lf:18,lp:6,rf:13,rp:7,lprp:6 |
| [3/1] | bba | 20 | lf:13,ls:7,rf:12 |
| [3/2] | aab | 19 | lf:19,rf:19,rs:7 |
| [3/3] | baa | 18 | lf:18,rf:19 |
| [3/4] | abb | 13 | lf:13,rf:12 |
| [3/5] | bab | 6 | lf:6,rf:6,a:4 |
| [3/6] | aaa | 2 | lf:1,lp:1 |
| [4/0] | abba | 20 | lf:13,ls:7,rf:12 |
| [4/1] | baab | 18 | lf:18,rf:19,rs:7 |
| [4/2] | abaa | 18 | lf:12,lp:6,rf:7,rp:7,lprp:6 |
| [4/3] | aabb | 13 | lf:13,rf:9 |
| [4/4] | bbaa | 6 | lf:6,rf:12,a:1 |
| [4/5] | baba | 6 | lf:6,rf:3,a:4 |
| [4/6] | abab | 6 | lf:6,rf:6,a:4 |
| [5/0] | aabba | 20 | lf:13,ls:7,rf:9 |
| [5/1] | abaab | 18 | lf:12,lp:6,rf:7,rp:7,rs:1,re:1,lprp:6 |
| [5/2] | baabb | 12 | lf:12,rf:9,a:1 |
| [5/3] | bbaab | 6 | lf:6,rf:12,rs:6,a:1 |
| [5/4] | abbaa | 6 | lf:6,rf:12,a:1 |
| [5/5] | baaba | 6 | lf:6,rf:3,a:1 |
| [5/6] | ababa | 6 | lf:6,rf:3,a:4 |
| [6/0] | baabba | 18 | lf:12,ls:6,rf:9,a:1 |
| [6/1] | abaabb | 16 | lf:11,lp:5,rf:6,rp:6,lprp:5,a:1 |
| [6/2] | abbaab | 6 | lf:6,rf:12,rs:6,a:1 |
| [6/3] | aabbaa | 6 | lf:6,rf:9,a:1 |
| [6/4] | bbaaba | 5 | lf:5,rf:3,a:2 |
| [6/5] | bababa | 3 | lf:3,rf:1,a:8 |
| [6/6] | babaab | 3 | lf:3,a:4 |
| [7/0] | abaabba | 22 | lf:11,lp:5,ls:6,rf:6,rp:6,lprp:5,lsrp:6,a:1 |
| [7/1] | baabbaa | 6 | lf:6,rf:9,a:1 |
| [7/2] | aabbaab | 6 | lf:6,rf:9,rs:3,a:1 |
| [7/3] | abbaaba | 5 | lf:5,rf:3,a:2 |
| [7/4] | bbaabab | 3 | lf:3,rf:3,a:4 |
| [7/5] | babaabb | 3 | lf:3,a:4 |
| [7/6] | baababa | 3 | lf:3,rf:2,a:4 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | aaabba=abaab⟩.