Morphocompletion for #5606 ⟨a, b | aaabba=abaab

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaabba ⇒ abaab
2. abaabaabba ⇒ abaabbaab
3. abaabbaabaabba ⇒ abaabbaabbaab
4. abaabbaababaabba ⇒ abaabbaababbaab
5. abaabbaabababaabba ⇒ abaabbaabababbaab
6. abaabbaabbaabaabba ⇒ abaabbaabbaabbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bba, [3/2] aab, [3/3] baa, [3/4] abb, [3/5] bab, [3/6] aaa
Length 4:[4/0] abba, [4/1] baab, [4/2] abaa, [4/3] aabb, [4/4] bbaa, [4/5] aaba, [4/6] baba
Length 5:[5/0] aabba, [5/1] abaab, [5/2] baabb, [5/3] bbaab, [5/4] abbaa, [5/5] baaba, [5/6] ababa
Length 6:[6/0] baabba, [6/1] abaabb, [6/2] abbaab, [6/3] aabbaa, [6/4] bbaaba, [6/5] baabaa, [6/6] aabaab
Length 7:[7/0] abaabba, [7/1] baabbaa, [7/2] aabbaab, [7/3] abbaaba, [7/4] baabaab, [7/5] aabaabb, [7/6] bbaabab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | aaabba=abaab.