Morphocompletion for #5542 ⟨a, b | aaabaa=abaab⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	abaab ⇒ aaabaa
2.	aaabaaaab ⇒ abaaaabaa
3.	abaaaabaaaaaab ⇒ aaaaabaaaaaabaa
4.	abaaaabaaaaaaaab ⇒ aaaaaaabaaaaaabaa
5.	abaaaabaaaaaaaaaab ⇒ aaaaaaaaabaaaaaabaa
6.	abaaaabaaaaaaaaaaaab ⇒ aaaaaaaaaaabaaaaaabaa
7.	abaaaabaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaabaaaaaabaa
8.	abaaaabaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaabaaaaaabaa
9.	abaaaabaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaabaaaaaabaa
10.	abaaaabaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaabaaaaaabaa
11.	abaaaabaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaabaaaaaabaa
12.	abaaaabaaaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaaaabaaaaaabaa
13.	aaabaaaaaabaaaaaab ⇒ abaaaaaabaaaaaabaa
14.	aaabaaaaaabaaaaaaaab ⇒ abaaaaaaaabaaaaaabaa
15.	aaabaaaaaabaaaaaaaaaab ⇒ abaaaaaaaaaabaaaaaabaa
16.	aaabaaaaaabaaaaaaaaaaaab ⇒ abaaaaaaaaaaaabaaaaaabaa
17.	aaabaaaaaabaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaabaaaaaabaa
18.	aaabaaaaaabaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaabaaaaaabaa
19.	aaabaaaaaabaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaabaaaaaabaa
20.	aaabaaaaaabaaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaaaabaaaaaabaa
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ab, [2/2] ba
Length 3:	[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa
Length 4:	[4/0] aaaa, [4/1] aaab, [4/2] abaa, [4/3] baaa, [4/4] aaba, [4/5] baab
Length 5:	[5/0] aaaaa, [5/1] aaaab, [5/2] abaaa, [5/3] baaaa, [5/4] aaaba, [5/5] aabaa
Length 6:	[6/0] aaaaaa, [6/1] abaaaa, [6/2] aaaaab, [6/3] aaabaa, [6/4] aabaaa, [6/5] baaaaa, [6/6] aaaaba
Length 7:	[7/0] aaaaaaa, [7/1] aaaaaab, [7/2] aaabaaa, [7/3] aabaaaa, [7/4] abaaaaa, [7/5] baaaaaa, [7/6] abaaaab

Considering [length 2 / frequency 1] ab=c.

Auxiliary generators:
1. c = ab
Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1

Rewriting system is complete. See ⟨a, b | aaabaa=abaab⟩.