Morphocompletion for #5491 ⟨a, b | aaaaba=babba

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. babba ⇒ aaaaba
2. babaaaaba ⇒ aaaaaaaaba
3. babaaaaaaaaba ⇒ aaaaaaaaaaaaba
4. babaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaba
5. babaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaba
6. babaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaba
7. babaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaba
8. babaaaaaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba
9. babaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba
10. babaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba
11. babaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba
12. babaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba ⇒ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] bab, [3/3] aab, [3/4] baa, [3/5] bba, [3/6] abb
Length 4:[4/0] aaaa, [4/1] baba, [4/2] aaba, [4/3] aaab, [4/4] abaa, [4/5] baaa, [4/6] babb
Length 5:[5/0] aaaaa, [5/1] babaa, [5/2] aaaba, [5/3] aaaab, [5/4] abaaa, [5/5] baaaa
Length 6:[6/0] aaaaaa, [6/1] babaaa, [6/2] aaaaba, [6/3] abaaaa, [6/4] aaaaab, [6/5] baaaaa, [6/6] baaaab
Length 7:[7/0] aaaaaaa, [7/1] babaaaa, [7/2] aaaaaba, [7/3] aaaaaab, [7/4] abaaaaa, [7/5] baaaaaa, [7/6] baaaaba

Considering [length 2 / frequency 1] ba=c.

Step 2

Rewriting system is complete. See a, b | aaaaba=babba.