Morphocompletion for #5401 ⟨a, b | abbabba=abab⟩

Solved by morph:6/1,3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbabab ⇒ ababbba
2. abbabba ⇒ abab
3. ababbbaabb ⇒ abababbbba
4. ababbbabab ⇒ ababbabbba
5. ababbbabba ⇒ ababbab
6. ababbabbbaab ⇒ abababbbbaba
7. ababbabbbaba ⇒ ababbbaab
8. abababbbbabba ⇒ abababbbab
9. ababbabbbabba ⇒ abababb
10. abababbabbbbaa ⇒ ababbbaabab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab48lf:35,lp:10,ls:3,rf:31,rp:10,rs:5,lprp:10,lsrp:3,lprs:5
[2/1]ba36lf:31,ls:5,rf:25,rs:4
[2/2]bb30lf:29,ls:1,rf:19,rs:1
[2/3]aa4lf:3,ls:1,rf:2,a:3
[3/0]bab25lf:23,ls:2,rf:19,rs:4
[3/1]bba22lf:18,ls:4,rf:9,rs:3
[3/2]abb22lf:19,lp:2,ls:1,rf:10,rs:1
[3/3]aba22lf:13,lp:8,ls:1,rf:16,rp:10,rs:1,lprp:8,lsrp:1,lprs:1
[4/0]abab22lf:12,lp:8,ls:2,rf:15,rp:10,rs:2,re:1,lprp:8,lsrp:2,lprs:1
[4/1]babb16lf:16,rf:10,rs:1
[4/2]abba16lf:10,lp:2,ls:4,rf:2
[4/3]bbab11lf:11,rf:4,rs:2
[5/0]ababb14lf:8,lp:6,rf:9,rp:5,rs:1,lprp:3,lprs:1,a:1
[5/1]babba12lf:8,ls:4,rf:2
[5/2]bbabb8lf:8,rf:1
[5/3]babbb8lf:8,rf:7,a:1
[6/0]bbabba8lf:4,ls:4
[6/1]ababbb7lf:4,lp:3,rf:6,rp:3,a:1
[6/2]ababba7lf:4,lp:3,rf:2,rp:2,a:2
[6/3]babbba6lf:6,rf:5,rs:2,a:1

Considering [length 6 / frequency 1] ababbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccacb ⇒ ccabcc
2. cccabc ⇒ cacb
3. cacba ⇒ cabcca
4. ccaba ⇒ abca
5. ccabca ⇒ abcca
6. cccaba ⇒ cabca
7. cabb ⇒ abbc
8. abccaab ⇒ ccaca
9. cabcaab ⇒ caca
10. abbabc ⇒ caabbb
11. caabbab ⇒ cabca
12. ababbca ⇒ ccaab
13. cababba ⇒ caab
14. ababbb ⇒ c
15. cababbcb ⇒ cccc
16. abbcaab ⇒ ccaba
17. ababbab ⇒ abbca
18. abbabab ⇒ ca
19. abbcabab ⇒ cca
20. abbabba ⇒ abab
...

Collecting factors up to length 6 / frequency 7:

[2/0]ab50lf:34,lp:9,ls:7,rf:14,rp:5,rs:3,lprp:2,lsrp:1,lprs:2
[2/1]ca25lf:17,lp:6,ls:2,rf:21,rp:8,rs:10,re:1,lprp:4,lprs:3,lsrs:1,a:2
[2/2]ba22lf:17,ls:5,rf:2,rs:1
[2/3]bb16lf:14,ls:2,rf:4,rs:1
[2/4]cc13lf:8,lp:5,rf:11,rp:6,rs:2,lprp:1,lprs:1,a:10
[2/5]bc11lf:9,ls:2,rf:8,rs:1,a:4
[2/6]cb5lf:3,ls:2,rf:1,rs:1,a:48
[3/0]abb19lf:13,lp:5,ls:1,rf:3,rp:2,lsrp:10
[3/1]bab16lf:12,ls:4,rf:1,rs:1
[3/2]aba14lf:9,lp:3,ls:2,rf:2,rp:1,rs:1
[3/3]cab13lf:9,lp:4,rf:5,rp:3,a:5
[3/4]bba9lf:7,ls:2
[3/5]cca9lf:6,lp:3,rf:7,rp:5,rs:3,re:1,lprp:1,lprs:1,a:10
[3/6]abc8lf:5,lp:1,ls:2,rf:6,rp:2,a:7
[4/0]abba12lf:7,lp:3,ls:2
[4/1]abab12lf:7,lp:3,ls:2,rf:1,rp:1,rs:1,re:1
[4/2]caba9lf:5,lp:2,ls:2,rf:1,rs:1,a:5
[4/3]caab8lf:4,lp:1,ls:3,rf:3,rp:2,rs:2,re:1,a:5
[4/4]bbab7lf:5,ls:2
[4/5]babb6lf:6
[4/6]abbc6lf:4,lp:2,rf:2,rp:2,rs:1,re:1,a:4
[5/0]abbab10lf:5,lp:3,ls:2
[5/1]ababb8lf:5,lp:3,a:1
[5/2]abbca6lf:3,lp:2,ls:1,rf:1,rp:1,rs:1,re:1,a:4
[5/3]cabab6lf:3,lp:2,ls:1,a:5
[5/4]babba5lf:3,ls:2
[5/5]bcaab4lf:2,ls:2,a:17
[5/6]cabca4lf:2,lp:1,ls:1,rf:2,rp:2,rs:2,re:2,a:11

Considering [length 3 / frequency 1] bab=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbabba=abab⟩.