Morphocompletion for #5400 ⟨a, b | abbabba=aabb⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbabba ⇒ aabb
2. abbaabb ⇒ aabbbba
3. aabbbbabba ⇒ aabbabb
4. aabbbbaabb ⇒ aabbabbbba
5. abbaaabbbb ⇒ aaabbbbbba
6. aabbabbbbaa ⇒ abbaaabb
7. aabbabbbbabba ⇒ aaabbbb
8. aaabbbbbbabba ⇒ aaabbbbabb
9. aabbbbaaabb ⇒ aaabbbbbbaa
10. aaabbbbbbaabb ⇒ aaabbbbabbbba
11. abbaaabbabbbb ⇒ aaabbabbbbbba
12. abbaaaabbbbbb ⇒ aaaabbbbbbbba
13. aaabbbbabbbbaa ⇒ abbaaabbabb
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb65lf:58,ls:7,rf:51,rs:6
[2/1]aa35lf:25,lp:8,ls:2,rf:24,rp:11,rs:1,lprp:6,lprs:1
[2/2]ab33lf:28,lp:5,rf:21,rp:2
[2/3]ba25lf:21,ls:4,rf:15,rs:6
[3/0]abb37lf:28,lp:5,ls:4,rf:21,rp:2,rs:5,lprs:1
[3/1]bbb33lf:30,ls:3,rf:30,rs:1,a:1
[3/2]bba25lf:21,ls:4,rf:15,rs:6
[3/3]aab20lf:15,lp:5,rf:13,rp:4,lprp:2
[3/4]aaa11lf:8,lp:3,rf:10,rp:7,lprp:2,a:3
[3/5]baa11lf:9,ls:2,rf:3,rs:1,a:1
[3/6]bab8lf:8,rf:6
[4/0]aabb24lf:15,lp:5,ls:4,rf:13,rp:4,rs:2,re:1,lprp:2,lsrp:2,lprs:1
[4/1]abba21lf:12,lp:5,ls:4,rf:6,rp:2
[4/2]bbbb21lf:18,ls:3,rf:20,rs:1,a:1
[4/3]abbb12lf:12,rf:10,a:1
[4/4]bbaa11lf:9,ls:2,rf:3,rs:1,a:1
[4/5]aaab10lf:7,lp:3,rf:9,rp:6,lprp:2,a:3
[4/6]bbba9lf:9,rf:9,rs:6,a:1
[5/0]abbbb14lf:12,ls:2,rf:10,rs:1,a:1
[5/1]aaabb11lf:7,lp:3,ls:1,rf:9,rp:6,rs:1,lprp:2,lsrp:1,a:3
[5/2]aabbb11lf:8,lp:3,rf:7,rp:1,a:1
[5/3]bbbba9lf:9,rf:9,rs:6,a:1
[5/4]abbaa8lf:4,lp:4,rf:2,rp:2,a:1
[5/5]babba8lf:4,ls:4
[5/6]bbabb8lf:8,rf:6,rs:3
[6/0]aabbbb12lf:8,lp:3,ls:1,rf:7,rp:1,rs:1,a:1
[6/1]aaabbb8lf:5,lp:3,rf:6,rp:5,lprp:2,a:4
[6/2]bbabba8lf:4,ls:4
[6/3]abbbba7lf:7,rf:5,rs:3,a:1
[6/4]bbbbaa7lf:5,ls:2,rf:1,rs:1,a:3
[6/5]abbaaa6lf:3,lp:3,rf:2,rp:2,a:3
[6/6]bbaabb6lf:3,ls:3,a:1
[7/0]aaabbbb9lf:5,lp:3,ls:1,rf:6,rp:5,rs:1,re:1,lprp:2,lsrp:1,a:4
[7/1]aabbbba7lf:4,lp:3,rf:3,rp:1,rs:1,re:1,a:1
[7/2]abbbbaa6lf:4,ls:2,a:3
[7/3]bbbabba6lf:3,ls:3,a:2
[7/4]aabbabb5lf:3,lp:2,rf:4,rp:2,rs:2,re:1,a:2
[7/5]bbabbbb5lf:4,ls:1,rf:3,a:3
[7/6]abbaaab4lf:2,lp:2,rf:2,rp:2,a:3

Considering [length 3 / frequency 0] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbabba=aabb⟩.