Morphocompletion for #5383 ⟨a, b | abbaaab=aaba⟩

Solved by morph:3/0,5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abbaaab ⇒ aaba
2. abbaaaaba ⇒ aababaaab
3. aababaaabbbaaab ⇒ aababaaababa
4. aabaabaaabbbaaab ⇒ aabaabaaababa
5. aabaaabaaabbbaaab ⇒ aabaaabaaababa
6. aababaaabbbaaaaba ⇒ aababaaabababaaab
7. aabaaaabaaabbbaaab ⇒ aabaaaabaaababa
8. aabaaaaabaaabbbaaab ⇒ aabaaaaabaaababa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa52lf:46,lp:6,rf:34,rp:8,lprp:6
[2/1]ab36lf:28,lp:2,ls:6,rf:30,rs:2,lprs:1
[2/2]ba24lf:22,ls:2,rf:28,rs:6
[2/3]bb14lf:14
[3/0]aab36lf:24,lp:6,ls:6,rf:20,rp:8,rs:2,lprp:6,lsrp:6,lprs:1
[3/1]aaa22lf:22,rf:14
[3/2]baa18lf:18,rf:12
[3/3]aba16lf:14,ls:2,rf:28,rs:6
[4/0]aaab23lf:17,ls:6,rf:11,rs:2
[4/1]aaba20lf:12,lp:6,ls:2,rf:18,rp:8,rs:1,re:1,lprp:6,lsrp:2
[4/2]baaa17lf:17,rf:11
[4/3]abaa10lf:10,rf:12,a:1
[5/0]baaab19lf:13,ls:6,rf:9,rs:2
[5/1]aabaa12lf:8,lp:4,rf:8,rp:4,lprp:4,a:4
[5/2]abaaa9lf:9,rf:11,a:1
[5/3]bbaaa8lf:8
[6/0]bbaaab12lf:6,ls:6
[6/1]aabaaa10lf:7,lp:3,rf:7,rp:3,lprp:3,a:4
[6/2]abaaab7lf:7,rf:9,rs:2,a:1
[6/3]aaaaba6lf:4,ls:2,rf:2,a:1

Considering [length 3 / frequency 0] aab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aab ⇒ c
2. aca ⇒ cbac
3. abbac ⇒ ca
4. cbcbacb ⇒ acc
5. abbcbac ⇒ caa
6. cbacbbac ⇒ acca
7. accbac ⇒ cbacca
8. abbcbcbac ⇒ caaa
9. abbaacc ⇒ cabcbacb
10. ccacbbac ⇒ cccbacba
11. cbacbbcbac ⇒ accaa
12. cabacbbac ⇒ cabcbacba
13. acccbacb ⇒ cbcbaacc
14. accbcbac ⇒ cbaccaa
15. abbcbcbcbac ⇒ caaaa
16. abbcbaacc ⇒ cccbacb
17. ccacbbcbac ⇒ cccbacbaa
18. ccbaccaba ⇒ ccbaccbbac
19. cbacbbcbcbac ⇒ accaaa
20. accbcbcbac ⇒ cbaccaaa
...

Collecting factors up to length 6 / frequency 7:

[2/0]ac47lf:29,lp:5,ls:13,rf:16,rp:4,rs:2,lsrp:3,lprs:1,a:2
[2/1]cb38lf:32,lp:4,ls:2,rf:18,rp:5,rs:2,lsrp:1,a:3
[2/2]ba24lf:23,ls:1,rf:15,rs:2,a:2
[2/3]cc16lf:11,lp:3,ls:2,rf:16,rp:4,rs:2,lprp:3,lsrp:1,a:5
[2/4]ab16lf:9,lp:6,ls:1,rf:2,a:1
[2/5]bc15lf:15,rf:3,a:4
[2/6]bb12lf:12,rf:1,a:2
[3/0]bac33lf:20,ls:13,rf:11,rs:2,a:2
[3/1]cba19lf:16,lp:3,rf:14,rp:4,rs:2,a:3
[3/2]bcb15lf:15,rf:3,a:4
[3/3]acc13lf:7,lp:4,ls:2,rf:9,rp:4,rs:2,re:1,lprs:1,a:5
[3/4]abb12lf:6,lp:6,a:2
[3/5]acb10lf:8,ls:2,rf:5,rs:2,a:5
[3/6]cbc9lf:8,lp:1,rf:1,rp:1,a:5
[4/0]cbac27lf:15,lp:3,ls:9,rf:10,rp:4,rs:1,re:1,lsrp:3,a:3
[4/1]bcba10lf:10,rf:3,a:4
[4/2]cbcb9lf:8,lp:1,rf:1,rp:1,a:5
[4/3]bbac8lf:4,ls:4,rf:1,rs:1,a:2
[4/4]bacb8lf:6,ls:2,rf:5,rs:2,a:5
[4/5]abbc8lf:4,lp:4,a:4
[4/6]bbcb7lf:7,a:4
[5/0]bcbac17lf:9,ls:8,rf:2,a:4
[5/1]cbacb10lf:5,lp:3,ls:2,rf:5,rs:2,a:5
[5/2]abbcb8lf:4,lp:4,a:4
[5/3]cbcba7lf:6,lp:1,rf:1,rp:1,a:5
[5/4]cbbac6lf:3,ls:3,rf:1,rs:1,a:6
[5/5]ccbac5lf:3,lp:1,ls:1,rf:4,rp:1,lprp:1,a:7
[5/6]bcbcb5lf:5,a:11

Considering [length 5 / frequency 2] abbcb=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbaaab=aaba⟩.