Morphocompletion for #5375 ⟨a, b | ababbba=baba⟩

Solved by morph:6/1,2/1,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

Collecting factors up to length 7, frequency 3:

Considering [length 6 / frequency 1] bbbaba=c.

Checking up to 20 rules for overlaps.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. bbbaba=c

Rewriting system is not complete: roundsLimit

Collecting factors up to length 6, frequency 5:

Length 2:	[2/0] ba, [2/1] bb, [2/2] ab, [2/3] bc, [2/4] ac
Length 3:	[3/0] aba, [3/1] bab, [3/2] bbb, [3/3] bba, [3/4] bac
Length 4:	[4/0] abab, [4/1] baba, [4/2] bbba, [4/3] babb, [4/4] bbab
Length 5:	[5/0] bbaba, [5/1] ababb, [5/2] bbbba, [5/3] ababc, [5/4] bbbab

Considering [length 2 / frequency 1] bb=d.

Checking up to 20 rules for overlaps.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(d) = 1; deg(b) = 2
Auxiliary generators:
1. bbbaba=c
2. bb=d

Rewriting system is not complete: roundsLimit

Collecting factors up to length 6, frequency 5:

Length 2:	[2/0] ba, [2/1] ac, [2/2] dd, [2/3] da, [2/4] ab
Length 3:	[3/0] aba, [3/1] dda, [3/2] dba, [3/3] bab, [3/4] bac
Length 4:	[4/0] baba, [4/1] badc, [4/2] abac, [4/3] daba, [4/4] cdba
Length 5:	[5/0] badba, [5/1] abadc, [5/2] cdbad, [5/3] babab, [5/4] babad

Considering [length 5 / frequency 0] badba=e.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(e) = deg(c) = 0, a < e < c; deg(d) = 1; deg(b) = 2
Auxiliary generators:
1. bbbaba=c
2. bb=d
3. badba=e

Rewriting system is complete. See ⟨a, b | ababbba=baba⟩.