| Back: | ⟨a, b | ababbba=baab⟩ |
|---|
Solved by morph:3/0,5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | ababbba ⇒ baab |
| 2. | baabbabbba ⇒ ababbbbaab |
| 3. | ababbababbbbaab ⇒ baababbabbba |
| 4. | baababbabbbaabbba ⇒ ababbababbbbabaab |
| 5. | baabbabbababbbbaab ⇒ ababbbbaababbabbba |
| 6. | ababbababbababbbbabaab ⇒ baabababbabbbaabbba |
| 7. | ababbababbbbaaababbbbaab ⇒ baababbabbbaaabbabbba |
| 8. | baabababbabbbaabbbaabbba ⇒ ababbababbababbbbababaab |
| 9. | baababbabbbaabbababbbbaab ⇒ ababbababbbbabaababbabbba |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa |
|---|---|
| Length 3: | [3/0] bba, [3/1] bab, [3/2] abb, [3/3] bbb |
| Length 4: | [4/0] baab, [4/1] babb, [4/2] abab, [4/3] bbba |
| Length 5: | [5/0] ababb, [5/1] bbaab, [5/2] abbba, [5/3] babbb |
| Length 6: | [6/0] bbbaab, [6/1] ababba, [6/2] babbab, [6/3] ababbb |
Considering [length 3 / frequency 0] bba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | cbabc ⇒ bcab |
| 2. | bba ⇒ c |
| 3. | baab ⇒ ababc |
| 4. | bababc ⇒ cab |
| 5. | cbabbcac ⇒ bcacbcba |
| 6. | ababcba ⇒ baac |
| 7. | baacbcba ⇒ ababbcac |
| 8. | cbabbcab ⇒ bcacbc |
| 9. | ababbcab ⇒ baacbc |
| 10. | baaababc ⇒ ababcaab |
| 11. | baacbbcab ⇒ ababbcacbc |
| 12. | bababbcac ⇒ cacbcba |
| 13. | cbabbcbaac ⇒ bcacbcabcba |
| 14. | ababcababc ⇒ baacab |
| 15. | ababcabcba ⇒ babaac |
| 16. | baacbcababc ⇒ ababbcacab |
| 17. | baacbcabcba ⇒ ababbcbaac |
| 18. | ababcabbcab ⇒ babaacbc |
| 19. | ababbcacbcba ⇒ baacbbcac |
| 20. | bababbcbaac ⇒ cacbcabcba |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] bc, [2/3] cb, [2/4] ac, [2/5] ca, [2/6] bb |
|---|---|
| Length 3: | [3/0] bab, [3/1] cba, [3/2] aba, [3/3] abc, [3/4] baa, [3/5] cab, [3/6] bca |
| Length 4: | [4/0] abab, [4/1] babc, [4/2] bcab, [4/3] bcba, [4/4] baac, [4/5] cbab, [4/6] abbc |
| Length 5: | [5/0] ababc, [5/1] bbcab, [5/2] baacb, [5/3] babbc, [5/4] babab, [5/5] ababb, [5/6] cbabb |
Considering [length 5 / frequency 0] ababc=d.
Rewriting system is complete. See ⟨a, b | ababbba=baab⟩.