Morphocompletion for #5351 ⟨a, b | ababaab=bbaa

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababaab ⇒ bbaa
2. abababbaa ⇒ bbaaabaab
3. bbaaabaabbabaab ⇒ abababbabbaa
4. ababaaabababbabbaa ⇒ bbaabaaabaabbabaab
5. bbaaabaabbababbaa ⇒ abababbabbaaabaab
6. bbaabaaabaabbabaabbabaab ⇒ ababaaabababbabbabbaa
7. ababaaababaaabababbabbabbaa ⇒ bbaabaabaaabaabbabaabbabaab
8. bbaaabaabbabaaabababbabbaa ⇒ abababbabbaabaaabaabbabaab
9. bbaabaaabaabbabaabbababbaa ⇒ ababaaabababbabbabbaaabaab
10. bbaabaabaaabaabbabaabbabaabbabaab ⇒ ababaaababaaabababbabbabbabbaa
11. ababaaababaaababaaabababbabbabbabbaa ⇒ bbaabaabaabaaabaabbabaabbabaabbabaab
12. bbaaabaabbabaaababaaabababbabbabbaa ⇒ abababbabbaabaabaaabaabbabaabbabaab
13. bbaabaaabaabbabaabbabaaabababbabbaa ⇒ ababaaabababbabbabbaabaaabaabbabaab
14. bbaabaabaaabaabbabaabbabaabbababbaa ⇒ ababaaababaaabababbabbabbabbaaabaab
15. bbaabaabaabaaabaabbabaabbabaabbabaabbabaab ⇒ ababaaababaaababaaabababbabbabbabbabbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] aba, [3/2] bba, [3/3] aab, [3/4] bab, [3/5] abb, [3/6] aaa
Length 4:[4/0] abaa, [4/1] bbaa, [4/2] abba, [4/3] baab, [4/4] baba, [4/5] bbab, [4/6] abab
Length 5:[5/0] abaab, [5/1] abbab, [5/2] babaa, [5/3] bbaba, [5/4] babba, [5/5] baabb, [5/6] abbaa
Length 6:[6/0] babbaa, [6/1] abbaba, [6/2] baabba, [6/3] babaab, [6/4] aabbab, [6/5] abaabb, [6/6] baaaba
Length 7:[7/0] baabbab, [7/1] aabbaba, [7/2] abaabba, [7/3] bbabaab, [7/4] abbabaa, [7/5] abaaaba, [7/6] bbabbaa

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | ababaab=bbaa.