Morphocompletion for #5349 ⟨a, b | ababaab=baba

Solved by morph:4/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaab ⇒ baba
2. babaabaab ⇒ ababababa
3. babaaabab ⇒ aababbaba
4. aababababa ⇒ babaaab
5. ababbabaaab ⇒ babaabababa
6. babaaabbaab ⇒ aabababbaba
7. babaabbabaaab ⇒ ababbabaababa
8. babaaabbabaab ⇒ aababababbaba
9. aababbabaababa ⇒ babababaaab
10. aaaababbabababa ⇒ babaaabaabab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa
Length 4:[4/0] baba, [4/1] abab, [4/2] abaa, [4/3] baab
Length 5:[5/0] babaa, [5/1] ababa, [5/2] abaab, [5/3] aabab
Length 6:[6/0] babaab, [6/1] babaaa, [6/2] abaaab, [6/3] bababa

Considering [length 4 / frequency 1] abab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abc ⇒ cab
2. caab ⇒ baba
3. abab ⇒ c
4. babac ⇒ cacab
5. acac ⇒ baba
6. aacbc ⇒ caacb
7. caaab ⇒ aacca
8. babaab ⇒ cac
9. cabaab ⇒ abbaba
10. babaac ⇒ acbaba
11. bcabaac ⇒ acbcaba
12. bccabaac ⇒ acbccaba
13. cacabac ⇒ babbaba
14. aaccac ⇒ caacab
15. aacbaba ⇒ caac
16. babaaab ⇒ acca
17. cabaaab ⇒ abaacca
18. caacbaab ⇒ aacbbaba
19. caacabac ⇒ aaccbaba
20. babaaaab ⇒ acaaacca
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] ac, [2/4] ca, [2/5] bc, [2/6] cb
Length 3:[3/0] aab, [3/1] aba, [3/2] aac, [3/3] bab, [3/4] baa, [3/5] caa, [3/6] cab
Length 4:[4/0] baba, [4/1] aaab, [4/2] abaa, [4/3] caba, [4/4] abac, [4/5] baac, [4/6] baab
Length 5:[5/0] babaa, [5/1] abaac, [5/2] cabaa, [5/3] abaab, [5/4] baaab, [5/5] cabac, [5/6] abaaa

Considering [length 3 / frequency 0] aab=d.

Step 3

Rewriting system is complete. See a, b | ababaab=baba.