| Back: | ⟨a, b | ababaab=aaba⟩ |
|---|
Solved by morph:3/1,3/3. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | ababaab ⇒ aaba |
| 2. | ababaaaba ⇒ aabaabaab |
| 3. | aabaabaabbaab ⇒ ababaaaaba |
| 4. | aabaabaabbabaab ⇒ aabaabaababa |
| 5. | ababababaaaaba ⇒ aabaaabaabbaab |
| 6. | aabaaabaabbabaab ⇒ aabaaabaababa |
| 7. | ababaaaabaabaab ⇒ aabaabaabbaaaba |
| 8. | aabaaaabaabbabaab ⇒ aabaaaabaababa |
| 9. | aabaabaabbabaaaba ⇒ aabaabaaabaaab |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] aba, [3/2] baa, [3/3] bab |
| Length 4: | [4/0] aaba, [4/1] baab, [4/2] abaa, [4/3] baba |
| Length 5: | [5/0] abaab, [5/1] aabaa, [5/2] ababa, [5/3] aaaba |
| Length 6: | [6/0] aabaab, [6/1] babaab, [6/2] ababaa, [6/3] baaaba |
Considering [length 3 / frequency 1] aba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | ccbccbbccb ⇒ ccbccc |
| 2. | ccbccbbccc ⇒ ccbcccbccb |
| 3. | acbccbbccb ⇒ acbccc |
| 4. | acbccbbccc ⇒ acbcccbccb |
| 5. | cba ⇒ abc |
| 6. | cca ⇒ cbcc |
| 7. | cbcab ⇒ cc |
| 8. | cbcac ⇒ ccbccb |
| 9. | ccbccbca ⇒ ccbccbbcc |
| 10. | ccbccbbcab ⇒ ccbccbc |
| 11. | aba ⇒ c |
| 12. | aca ⇒ abcc |
| 13. | abcab ⇒ ac |
| 14. | abcac ⇒ acbccb |
| 15. | acbccbca ⇒ acbccbbcc |
| 16. | acbccbbcab ⇒ acbccbc |
| 17. | cbcaabc ⇒ ccbccbba |
| 18. | ccbccbbaab ⇒ cbcaac |
| 19. | abcaabc ⇒ acbccbba |
| 20. | acbccbbaab ⇒ abcaac |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] cb, [2/1] cc, [2/2] bc, [2/3] ab, [2/4] ca, [2/5] ac, [2/6] bb |
|---|---|
| Length 3: | [3/0] ccb, [3/1] cbc, [3/2] bcc, [3/3] bca, [3/4] abc, [3/5] acb, [3/6] cab |
| Length 4: | [4/0] bccb, [4/1] ccbc, [4/2] cbca, [4/3] acbc, [4/4] cbcc, [4/5] bcab, [4/6] ccbb |
| Length 5: | [5/0] acbcc, [5/1] ccbcc, [5/2] cbccb, [5/3] bccbb, [5/4] ccbbc, [5/5] caabc, [5/6] bbaab |
Considering [length 3 / frequency 3] bca=d.
Rewriting system is complete. See ⟨a, b | ababaab=aaba⟩.