Morphocompletion for #5341 ⟨a, b | ababaab=aaba⟩

Solved by morph:3/1,3/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababaab ⇒ aaba
2. ababaaaba ⇒ aabaabaab
3. aabaabaabbaab ⇒ ababaaaaba
4. aabaabaabbabaab ⇒ aabaabaababa
5. ababababaaaaba ⇒ aabaaabaabbaab
6. aabaaabaabbabaab ⇒ aabaaabaababa
7. ababaaaabaabaab ⇒ aabaabaabbaaaba
8. aabaaaabaabbabaab ⇒ aabaaaabaababa
9. aabaabaabbabaaaba ⇒ aabaabaaabaaab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab50lf:40,lp:4,ls:6,rf:31,rp:1,rs:3,lsrp:1,lprs:2
[2/1]aa40lf:35,lp:5,rf:35,rp:8,lprp:4
[2/2]ba37lf:34,ls:3,rf:28,rs:6
[2/3]bb5lf:5,rf:2,a:2
[3/0]aab37lf:26,lp:5,ls:6,rf:26,rp:8,rs:3,lprp:4,lsrp:5,lprs:1
[3/1]aba36lf:29,lp:4,ls:3,rf:26,rp:1,rs:6,lprs:2
[3/2]baa21lf:21,rf:18
[3/3]bab10lf:10,rf:4
[4/0]aaba23lf:15,lp:5,ls:3,rf:21,rp:8,rs:3,re:1,lprp:4,lsrp:3,lprs:1
[4/1]baab21lf:15,ls:6,rf:11,rs:2
[4/2]abaa20lf:20,rf:16
[4/3]baba10lf:10,rf:4,rs:3
[5/0]abaab19lf:14,ls:5,rf:10,rs:1
[5/1]aabaa17lf:12,lp:5,rf:15,rp:7,lprp:4,a:1
[5/2]ababa10lf:6,lp:4,rf:4,rp:1,rs:3
[5/3]aaaba9lf:6,ls:3,rf:6,rs:2,a:1
[6/0]aabaab14lf:10,lp:3,ls:1,rf:10,rp:4,rs:1,lprp:2,lsrp:1,a:1
[6/1]babaab8lf:4,ls:4
[6/2]ababaa7lf:4,lp:3,rf:1,rp:1
[6/3]baaaba5lf:3,ls:2,rf:4,rs:1,a:1

Considering [length 3 / frequency 1] aba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccbccbbccb ⇒ ccbccc
2. ccbccbbccc ⇒ ccbcccbccb
3. acbccbbccb ⇒ acbccc
4. acbccbbccc ⇒ acbcccbccb
5. cba ⇒ abc
6. cca ⇒ cbcc
7. cbcab ⇒ cc
8. cbcac ⇒ ccbccb
9. ccbccbca ⇒ ccbccbbcc
10. ccbccbbcab ⇒ ccbccbc
11. aba ⇒ c
12. aca ⇒ abcc
13. abcab ⇒ ac
14. abcac ⇒ acbccb
15. acbccbca ⇒ acbccbbcc
16. acbccbbcab ⇒ acbccbc
17. cbcaabc ⇒ ccbccbba
18. ccbccbbaab ⇒ cbcaac
19. abcaabc ⇒ acbccbba
20. acbccbbaab ⇒ abcaac
...

Collecting factors up to length 6 / frequency 7:

[2/0]cb32lf:26,lp:4,ls:2,rf:26,rp:2,rs:4,lprs:1,a:3
[2/1]cc30lf:22,lp:6,ls:2,rf:29,rp:7,rs:7,re:1,lprp:4,lsrp:1,lprs:3,a:4
[2/2]bc28lf:26,ls:2,rf:23,rs:3,a:2
[2/3]ab22lf:12,lp:4,ls:6,rf:3,rp:3,lsrp:1,a:1
[2/4]ca16lf:12,ls:4,rf:2,a:2
[2/5]ac16lf:8,lp:6,ls:2,rf:9,rp:7,rs:3,re:1,lprp:4,lsrp:1,lprs:1,a:2
[2/6]bb8lf:8,rf:4,a:9
[3/0]ccb24lf:17,lp:5,ls:2,rf:18,rp:6,rs:4,lprp:4,lsrp:1,lprs:1,a:6
[3/1]cbc18lf:15,lp:3,rf:18,rp:2,rs:2,a:4
[3/2]bcc14lf:14,rf:18,rs:4,a:5
[3/3]bca12lf:10,ls:2,rf:2,a:2
[3/4]abc10lf:5,lp:3,ls:2,rf:3,rp:3,rs:1,re:1,a:2
[3/5]acb10lf:5,lp:5,rf:6,rp:6,lprp:4,a:6
[3/6]cab8lf:4,ls:4,a:2
[4/0]bccb14lf:12,ls:2,rf:10,rs:4,a:6
[4/1]ccbc12lf:7,lp:5,rf:10,rp:6,rs:2,lprp:4,lprs:1,a:8
[4/2]cbca10lf:5,lp:3,ls:2,rf:1,rp:1,a:4
[4/3]acbc10lf:5,lp:5,rf:6,rp:6,lprp:4,a:6
[4/4]cbcc10lf:10,rf:15,rp:1,rs:1,re:1,a:6
[4/5]bcab8lf:4,ls:4,a:2
[4/6]ccbb8lf:8,rf:4,a:9
[5/0]acbcc10lf:5,lp:5,rf:6,rp:6,lprp:4,a:6
[5/1]ccbcc10lf:5,lp:5,rf:8,rp:6,lprp:4,a:8
[5/2]cbccb10lf:10,rf:10,rs:4,a:6
[5/3]bccbb8lf:8,rf:4,a:9
[5/4]ccbbc6lf:6,rf:2,a:9
[5/5]caabc4lf:2,ls:2,a:11
[5/6]bbaab4lf:2,ls:2,a:21

Considering [length 3 / frequency 3] bca=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababaab=aaba⟩.