Morphocompletion for #5333 ⟨a, b | abaabba=baba⟩

Back:⟨a, b | abaabba=baba⟩

Solved by morph:4/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabba ⇒ baba
2. abaabbbaba ⇒ babbaba
3. abaabbbbaba ⇒ babbbaba
4. abaabbbbbaba ⇒ babbbbaba
5. abaabbbbbbaba ⇒ babbbbbaba
6. abaabbbabbaba ⇒ babbabbaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] bbb, [3/2] bba, [3/3] abb, [3/4] aab, [3/5] baa, [3/6] bab
Length 4:[4/0] abaa, [4/1] baba, [4/2] aabb, [4/3] baab, [4/4] bbab, [4/5] bbbb, [4/6] abbb
Length 5:[5/0] abaab, [5/1] bbaba, [5/2] baabb, [5/3] aabbb, [5/4] bbbab, [5/5] abbbb, [5/6] bbbba
Length 6:[6/0] abaabb, [6/1] bbbaba, [6/2] baabbb, [6/3] aabbbb, [6/4] bbbbab, [6/5] aabbba, [6/6] abbaba
Length 7:[7/0] abaabbb, [7/1] bbbbaba, [7/2] baabbbb, [7/3] aabbbab, [7/4] aabbbbb, [7/5] abbbaba, [7/6] baabbba

Considering [length 4 / frequency 2] aabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaabba=baba⟩.