Morphocompletion for #5319 ⟨a, b | abaabab=bbaa

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaabab ⇒ bbaa
2. abaabbbaa ⇒ bbaaaabab
3. bbaaaababbaabab ⇒ abaabbbabbaa
4. bbaaaababbaabbbaa ⇒ abaabbbabbaaaabab
5. abaabaabaabbbabbaa ⇒ bbaabaaaababbaabab
6. bbaabaaaababbaababbaabab ⇒ abaabaabaabbbabbabbaa
7. bbaabaaaababbaababbaabbbaa ⇒ abaabaabaabbbabbabbaaaabab
8. bbaaaababbaabaabaabbbabbaa ⇒ abaabbbabbaabaaaababbaabab
9. abaabaabaabaabaabbbabbabbaa ⇒ bbaabaabaaaababbaababbaabab
10. bbaabaabaaaababbaababbaababbaabab ⇒ abaabaabaabaabaabbbabbabbabbaa
11. bbaabaabaaaababbaababbaababbaabbbaa ⇒ abaabaabaabaabaabbbabbabbabbaaaabab
12. bbaabaaaababbaababbaabaabaabbbabbaa ⇒ abaabaabaabbbabbabbaabaaaababbaabab
13. bbaaaababbaabaabaabaabaabbbabbabbaa ⇒ abaabbbabbaabaabaaaababbaababbaabab
14. abaabaabaabaabaabaabaabbbabbabbabbaa ⇒ bbaabaabaabaaaababbaababbaababbaabab
15. bbaabaabaabaaaababbaababbaababbaababbaabab ⇒ abaabaabaabaabaabaabaabbbabbabbabbabbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] aba, [3/2] aab, [3/3] bba, [3/4] bab, [3/5] abb, [3/6] aaa
Length 4:[4/0] bbaa, [4/1] baab, [4/2] aaba, [4/3] abaa, [4/4] babb, [4/5] abba, [4/6] abab
Length 5:[5/0] baaba, [5/1] abaab, [5/2] bbaab, [5/3] abbaa, [5/4] babba, [5/5] aabab, [5/6] aabaa
Length 6:[6/0] babbaa, [6/1] baabaa, [6/2] bbaaba, [6/3] abaaba, [6/4] aabaab, [6/5] ababba, [6/6] abbaab
Length 7:[7/0] baabaab, [7/1] abaabaa, [7/2] babbaab, [7/3] ababbaa, [7/4] aababba, [7/5] bbaabab, [7/6] aabaaba

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | abaabab=bbaa.