Morphocompletion for #5315 ⟨a, b | abaabab=baaa

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaabab ⇒ baaa
2. baaaaabab ⇒ abaabbaaa
3. abaabaabaabbaaa ⇒ baaaaaaaabab
4. baaaaaaaababbaabab ⇒ abaabaabaabbaabaaa
5. baaaaabaabaabbaaa ⇒ abaabbaaaaaaaabab
6. abaabaabaabaabaabbaabaaa ⇒ baaaaaaaaaaababbaabab
7. baaaaaaaaaaababbaababbaabab ⇒ abaabaabaabaabaabbaabaabaaa
8. baaaaaaaababbaabaabaabbaaa ⇒ abaabaabaabbaabaaaaaaaabab
9. baaaaabaabaabaabaabbaabaaa ⇒ abaabbaaaaaaaaaaababbaabab
10. abaabaabaabaabaabaabaabbaabaabaaa ⇒ baaaaaaaaaaaaaababbaababbaabab
11. baaaaaaaaaaaaaababbaababbaababbaabab ⇒ abaabaabaabaabaabaabaabbaabaabaabaaa
12. baaaaaaaaaaababbaababbaabaabaabbaaa ⇒ abaabaabaabaabaabbaabaabaaaaaaaabab
13. baaaaaaaababbaabaabaabaabaabbaabaaa ⇒ abaabaabaabbaabaaaaaaaaaaababbaabab
14. baaaaabaabaabaabaabaabaabbaabaabaaa ⇒ abaabbaaaaaaaaaaaaaababbaababbaabab
15. abaabaabaabaabaabaabaabaabaabbaabaabaabaaa ⇒ baaaaaaaaaaaaaaaaababbaababbaababbaabab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aaa, [3/2] aba, [3/3] aab, [3/4] bba, [3/5] bab, [3/6] abb
Length 4:[4/0] aaba, [4/1] baab, [4/2] abaa, [4/3] aaaa, [4/4] baaa, [4/5] bbaa, [4/6] abba
Length 5:[5/0] baaba, [5/1] abaab, [5/2] aabaa, [5/3] aaaaa, [5/4] baaaa, [5/5] abbaa, [5/6] aabab
Length 6:[6/0] baabaa, [6/1] abaaba, [6/2] aabaab, [6/3] aaaaaa, [6/4] baaaaa, [6/5] bbaaba, [6/6] abbaab
Length 7:[7/0] abaabaa, [7/1] baabaab, [7/2] aabaaba, [7/3] aaaaaaa, [7/4] abbaaba, [7/5] baaaaaa, [7/6] baabaaa

Considering [length 3 / frequency 0] baa=c.

Step 2

Rewriting system is complete. See a, b | abaabab=baaa.