| Back: | ⟨a, b | abaaaba=baab⟩ |
|---|
Solved by morph:4/6. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaaba ⇒ baab |
| 2. | baabaaba ⇒ abaabaab |
| 3. | baabbaaaba ⇒ abaaabbaab |
| 4. | baaabaabaab ⇒ aabaabaabba |
| 5. | baababaabba ⇒ abbaababaab |
| 6. | aaabaabaabba ⇒ baababaab |
| 7. | baaaabaabaab ⇒ aabaabaabbaa |
| 8. | baababaababa ⇒ ababaababaab |
| 9. | aabaabaabbaba ⇒ bbaababaab |
| 10. | baaaaabaabaab ⇒ aabaabaabbaaa |
| 11. | aabaabaabbaaba ⇒ babaababaab |
| 12. | aabaabaabbbaba ⇒ bbbaababaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ba | 57 | lf:41,lp:7,ls:9,rf:34,rp:3,rs:1,lsrp:3,lprs:1 |
|---|---|---|---|
| [2/1] | aa | 44 | lf:40,lp:4,rf:30,rp:3,rs:2 |
| [2/2] | ab | 41 | lf:37,lp:1,ls:3,rf:38,rp:4,rs:9,lprs:1 |
| [2/3] | bb | 7 | lf:7,rf:8,rp:2,a:2 |
| [3/0] | aab | 37 | lf:31,lp:3,ls:3,rf:26,rp:3,rs:9,lsrp:3,lprs:3 |
| [3/1] | aba | 36 | lf:28,lp:1,ls:7,rf:24,rp:3,lsrp:3 |
| [3/2] | baa | 34 | lf:27,lp:7,rf:25,rp:2,rs:1,lprs:1 |
| [3/3] | aaa | 10 | lf:9,lp:1,rf:2,rs:1 |
| [3/4] | bba | 8 | lf:6,ls:2,rf:7,rp:1,rs:1,a:2 |
| [3/5] | abb | 6 | lf:6,rf:5,rp:1,a:2 |
| [3/6] | bab | 5 | lf:5,rf:8,rp:1,a:4 |
| [4/0] | baab | 29 | lf:22,lp:4,ls:3,rf:22,rp:2,rs:9,re:1,lprs:4 |
| [4/1] | aaba | 29 | lf:22,lp:3,ls:4,rf:13,rp:3 |
| [4/2] | abaa | 19 | lf:18,lp:1,rf:17,rp:2 |
| [4/3] | baba | 8 | lf:5,ls:3,rf:8,rp:1,a:4 |
| [4/4] | baaa | 8 | lf:5,lp:3,rf:2,rs:1,lprs:1 |
| [4/5] | abba | 7 | lf:5,ls:2,rf:5,rp:1,rs:1,lsrp:1,a:2 |
| [4/6] | aaab | 7 | lf:6,lp:1,rf:1 |
| [5/0] | abaab | 20 | lf:17,ls:3,rf:16,rp:1,rs:7,a:1 |
| [5/1] | baaba | 18 | lf:13,lp:3,ls:2,rf:10,rp:1,a:1 |
| [5/2] | aabaa | 18 | lf:15,lp:3,rf:7,rp:3,a:1 |
| [5/3] | aaaba | 9 | lf:6,lp:1,ls:2 |
| [5/4] | baabb | 7 | lf:6,lp:1,rf:3,a:2 |
| [5/5] | aabba | 7 | lf:5,ls:2,rf:4,rs:1,a:2 |
| [5/6] | bbaba | 4 | lf:2,ls:2,a:15 |
| [6/0] | aabaab | 21 | lf:15,lp:3,ls:3,rf:7,rp:3,rs:1,lsrp:3,a:1 |
| [6/1] | abaaba | 10 | lf:9,ls:1,rf:6,rp:1,lsrp:1,a:1 |
| [6/2] | baabaa | 9 | lf:8,lp:1,rf:4,a:1 |
| [6/3] | baabba | 8 | lf:5,lp:1,ls:2,rf:3,rs:1,a:2 |
| [6/4] | baaaba | 6 | lf:3,lp:1,ls:2 |
| [6/5] | baabab | 5 | lf:3,lp:2,rf:6,rp:1,a:4 |
| [6/6] | abaabb | 5 | lf:5,rf:3,a:4 |
| [7/0] | baabaab | 12 | lf:8,lp:1,ls:3,rf:4,rs:1,lprs:10,a:1 |
| [7/1] | aabaaba | 12 | lf:8,lp:3,ls:1,rf:3,rp:3,a:1 |
| [7/2] | abaabaa | 7 | lf:7,rf:4,rp:1,a:1 |
| [7/3] | baababa | 6 | lf:3,lp:2,ls:1,rf:6,rp:1,a:4 |
| [7/4] | abaabba | 6 | lf:4,ls:2,rf:3,rs:1,a:4 |
| [7/5] | aaabaab | 5 | lf:4,lp:1,a:4 |
| [7/6] | aabaabb | 4 | lf:4,rf:3,a:4 |
Considering [length 4 / frequency 6] aaab=c.
Rewriting system is complete. See ⟨a, b | abaaaba=baab⟩.