Morphocompletion for #5304 ⟨a, b | abaaaba=baab⟩

Back:⟨a, b | abaaaba=baab⟩

Solved by morph:4/6. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaba ⇒ baab
2. baabaaba ⇒ abaabaab
3. baabbaaaba ⇒ abaaabbaab
4. baaabaabaab ⇒ aabaabaabba
5. baababaabba ⇒ abbaababaab
6. aaabaabaabba ⇒ baababaab
7. baaaabaabaab ⇒ aabaabaabbaa
8. baababaababa ⇒ ababaababaab
9. aabaabaabbaba ⇒ bbaababaab
10. baaaaabaabaab ⇒ aabaabaabbaaa
11. aabaabaabbaaba ⇒ babaababaab
12. aabaabaabbbaba ⇒ bbbaababaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] aba, [3/2] baa, [3/3] aaa, [3/4] bba, [3/5] abb, [3/6] bab
Length 4:[4/0] baab, [4/1] aaba, [4/2] abaa, [4/3] baba, [4/4] baaa, [4/5] abba, [4/6] aaab
Length 5:[5/0] abaab, [5/1] baaba, [5/2] aabaa, [5/3] aaaba, [5/4] baabb, [5/5] aabba, [5/6] bbaba
Length 6:[6/0] aabaab, [6/1] abaaba, [6/2] baabaa, [6/3] baabba, [6/4] baaaba, [6/5] baabab, [6/6] abaabb
Length 7:[7/0] baabaab, [7/1] aabaaba, [7/2] abaabaa, [7/3] baababa, [7/4] abaabba, [7/5] aaabaab, [7/6] aabaabb

Considering [length 4 / frequency 6] aaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaaba=baab⟩.