Morphocompletion for #5283 ⟨a, b | abaaaab=aaba⟩

Solved by morph:2/2,3/2,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaab ⇒ aaba
2. abaaaaaba ⇒ aabaaaaab
3. ababaaaaaaba ⇒ aabaaaaaabab
4. aaaaabaaaaabb ⇒ abaaaaaaba
5. abaabaaaaaaba ⇒ aabaaaaaabaab
6. aabaaaaabbaaaab ⇒ aaabaaaaabba
7. abaaaaaabaaaaab ⇒ aabaaaaaabaa
8. aabaaaaaababaaab ⇒ ababaaaaaaaba
...

Collecting factors up to length 7 / frequency 3:

[2/0]aa54lf:51,lp:3,rf:43,rp:6,rs:1,lprp:1
[2/1]ab31lf:22,lp:5,ls:4,rf:18,rp:2,rs:3,lsrp:1,lprs:3
[2/2]ba20lf:17,ls:3,rf:15,rs:4
[3/0]aaa37lf:36,lp:1,rf:28,rp:1
[3/1]aba24lf:16,lp:5,ls:3,rf:14,rp:2,rs:3,lprs:1
[3/2]aab21lf:15,lp:2,ls:4,rf:14,rp:5,rs:2,lsrp:2
[4/0]aaaa25lf:24,lp:1,rf:20
[4/1]aaab16lf:12,ls:4,rf:8,rp:1,rs:1,lsrp:1
[4/2]abaa15lf:11,lp:4,rf:9,rp:1,rs:1,lprs:1
[5/0]aaaab14lf:11,ls:3,rf:7,rs:1
[5/1]aaaaa14lf:13,lp:1,rf:13,a:1
[5/2]abaaa13lf:10,lp:3,rf:7,rp:1
[6/0]abaaaa12lf:9,lp:3,rf:7,rp:1
[6/1]aaaaab11lf:9,lp:1,ls:1,rf:7,rs:1,a:1
[6/2]aaaaba9lf:6,ls:3,rf:5,rs:2,a:1

Considering [length 2 / frequency 2] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: pendingRulesLimit

#Rule
1. ba ⇒ c
2. ccaaac ⇒ caca
3. ccaaab ⇒ cac
4. acaaac ⇒ aaca
5. acaaab ⇒ aac
6. cacaaaac ⇒ ccaaaaca
7. cacaaaab ⇒ ccaaaac
8. aacaaaac ⇒ acaaaaca
9. aacaaaab ⇒ acaaaac
10. cccaaaacaa ⇒ cacaaaaab
11. cacaaaaacc ⇒ cccaaaaaca
12. cacaaaaacb ⇒ cccaaaaac
13. accaaaacaa ⇒ aacaaaaab
14. aacaaaaacc ⇒ accaaaaaca
15. aacaaaaacb ⇒ accaaaaac
16. cacaaaaacac ⇒ ccacaaaaaca
17. cacaaaaacab ⇒ ccacaaaaac
18. aacaaaaacac ⇒ acacaaaaaca
19. aacaaaaacab ⇒ acacaaaaac
20. ccaaccaaaaac ⇒ cacaaaaaacb
...

Collecting factors up to length 6 / frequency 5:

[2/0]aa79lf:71,lp:6,ls:2,rf:60,rp:3,lsrp:1,a:2
[2/1]ac43lf:33,lp:3,ls:7,rf:30,rp:6,rs:8,lsrp:2,lprs:1,a:2
[2/2]ca38lf:32,lp:6,rf:31,rp:4,rs:8,lprs:3,a:2
[2/3]cc15lf:9,lp:4,ls:2,rf:10,rp:6,lsrp:1,a:3
[2/4]ab12lf:6,ls:6,rf:2,rs:2,a:2
[3/0]aaa43lf:43,rf:42,a:2
[3/1]aac33lf:22,lp:6,ls:5,rf:16,rp:3,rs:7,re:1,lsrp:1,lprs:3,a:2
[3/2]caa24lf:22,ls:2,rf:15,a:2
[3/3]aca22lf:20,lp:2,rf:19,rp:4,rs:8,lprs:1,a:2
[3/4]cac16lf:8,lp:6,ls:2,rf:8,rp:4,rs:1,re:1,a:3
[4/0]aaaa24lf:24,rf:27,a:6
[4/1]aaac20lf:15,ls:5,rf:13,rs:6,a:4
[4/2]acaa20lf:16,lp:2,ls:2,rf:9,rp:2,a:2
[4/3]caaa19lf:19,rf:15,a:2
[4/4]aaca18lf:12,lp:6,rf:8,rp:2,rs:7,re:1,lprs:3,a:4
[5/0]aaaac16lf:13,ls:3,rf:13,rs:6,a:6
[5/1]aacaa16lf:8,lp:6,ls:2,rf:1,rp:1,lsrp:1,a:7
[5/2]acaaa16lf:14,lp:2,rf:9,rp:2,a:2
[5/3]caaaa15lf:15,rf:15,a:6
[5/4]cacaa12lf:6,lp:6,rf:6,rp:2,a:6

Considering [length 3 / frequency 2] caa=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ba ⇒ c
2. caa ⇒ d
3. cdac ⇒ caca
4. cdab ⇒ cac
5. cdad ⇒ cada
6. adac ⇒ aaca
7. adab ⇒ aac
8. adad ⇒ aada
9. ddac ⇒ daca
10. ddab ⇒ dac
11. ddad ⇒ dada
12. ddaac ⇒ cdaad
13. cadaac ⇒ ddaab
14. cadaab ⇒ cdaac
15. cdaaca ⇒ ddaab
16. cdaada ⇒ cadaad
17. aadaab ⇒ adaac
18. adaaca ⇒ aadaac
19. adaada ⇒ aadaad
20. dadaab ⇒ ddaac
...

Collecting factors up to length 6 / frequency 5:

[2/0]da24lf:21,lp:1,ls:2,rf:15,rp:3,rs:3,a:3
[2/1]ad22lf:14,lp:5,ls:3,rf:10,rp:1,rs:3,lprs:1,a:3
[2/2]aa13lf:11,lp:1,ls:1,rf:14,rp:5,a:2
[2/3]ab12lf:6,ls:6,rf:2,rs:2,a:3
[2/4]ac12lf:7,ls:5,rf:10,rs:7,a:3
[3/0]ada18lf:11,lp:5,ls:2,rf:7,rp:1,rs:3,lprs:10,a:3
[3/1]cda10lf:5,lp:5,rf:2,rp:2,a:4
[3/2]daa9lf:9,rf:9,a:11
[3/3]dda8lf:4,lp:4,rf:3,rp:3,a:5
[3/4]dad8lf:4,lp:1,ls:3,rf:1,rp:1,lsrp:10,a:9
[4/0]adaa8lf:6,lp:2,rf:4,rp:1,a:11
[4/1]daab6lf:3,ls:3,rf:2,rs:2,a:11
[4/2]daac6lf:4,ls:2,rf:4,rs:4,a:11
[4/3]aada6lf:3,lp:1,ls:2,rf:3,rp:3,rs:1,re:1,lsrp:1,a:12
[4/4]aaca4lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:6
[5/0]adaab6lf:3,ls:3,a:11
[5/1]daada4lf:2,ls:2,a:15
[5/2]daaca4lf:2,ls:2,a:13
[5/3]adaac4lf:2,lp:1,ls:1,rf:2,rp:1,rs:2,re:1,lprs:10,a:16
[5/4]cadaa4lf:2,lp:2,rf:1,rp:1,a:11

Considering [length 3 / frequency 0] ada=e.

Step 4

Rewriting system is complete. See ⟨a, b | abaaaab=aaba⟩.